Last updated on May 27th, 2025
When a number is multiplied by itself thrice, the resultant number is called the cube of a number. Cubing is used while comparing sizes of objects or things with cubic measurements. In this topic, we shall learn about the cube of 875.
A cube number is a value obtained by raising a number to the power of 3, or by multiplying the number by itself three times. When you cube a positive number, the result is always positive. When you cube a negative number, the result is always negative. This is because a negative number by itself three times results in a negative number. The cube of 875 can be written as 875³, which is the exponential form. Or it can also be written in arithmetic form as, 875 × 875 × 875.
In order to check whether a number is a cube number or not, we can use the following three methods, such as multiplication method, a factor formula (a³), or by using a calculator. These three methods will help kids to cube the numbers faster and easier without feeling confused or stuck while evaluating the answers. By Multiplication Method Using a Formula Using a Calculator
The multiplication method is a process in mathematics used to find the product of two numbers or quantities by combining them through repeated addition. It is a fundamental operation that forms the basis for more complex mathematical concepts. Step 1: Write down the cube of the given number. 875³ = 875 × 875 × 875 Step 2: You get 669,921,875 as the answer. Hence, the cube of 875 is 669,921,875.
The formula (a + b)³ is a binomial formula for finding the cube of a number. The formula is expanded as a³ + 3a²b + 3ab² + b³. Step 1: Split the number 875 into two parts. Let a = 800 and b = 75, so a + b = 875 Step 2: Now, apply the formula (a + b)³ = a³ + 3a²b + 3ab² + b³ Step 3: Calculate each term a³ = 800³ 3a²b = 3 × 800² × 75 3ab² = 3 × 800 × 75² b³ = 75³ Step 4: Add all the terms together: (a + b)³ = a³ + 3a²b + 3ab² + b³ (800 + 75)³ = 800³ + 3 × 800² × 75 + 3 × 800 × 75² + 75³ 875³ = 512,000,000 + 144,000,000 + 135,000,000 + 421,875 875³ = 669,921,875 Step 5: Hence, the cube of 875 is 669,921,875.
To find the cube of 875 using a calculator, input the number 875 and use the cube function (if available) or multiply 875 × 875 × 875. This operation calculates the value of 875³, resulting in 669,921,875. It’s a quick way to determine the cube without manual computation. Step 1: Ensure the calculator is functioning properly. Step 2: Press 8 followed by 7 and then 5 Step 3: If the calculator has a cube function, press it to calculate 875³. Step 4: If there is no cube function on the calculator, simply multiply 875 three times manually. Step 5: The calculator will display 669,921,875.
The cube of any even number is always even, while the cube of any odd number is always odd. The product of two or more perfect cube numbers is always a perfect cube. A perfect cube can always be expressed as the product of three identical groups of equal prime factors.
There are some typical errors that kids might make during the process of cubing a number. Let us take a look at five of the major mistakes that kids might make:
What is the cube and cube root of 875?
The cube of 875 is 669,921,875 and the cube root of 875 is approximately 9.545.
First, let’s find the cube of 875. We know that the cube of a number, such that x³ = y Where x is the given number, and y is the cubed value of that number So, we get 875³ = 669,921,875 Next, we must find the cube root of 875 We know that the cube root of a number ‘x’, such that ³√x = y Where ‘x’ is the given number, and y is the cube root value of the number So, we get ³√875 ≈ 9.545 Hence the cube of 875 is 669,921,875 and the cube root of 875 is approximately 9.545.
If the side length of the cube is 875 cm, what is the volume?
The volume is 669,921,875 cm³.
Use the volume formula for a cube V = Side³. Substitute 875 for the side length: V = 875³ = 669,921,875 cm³.
How much larger is 875³ than 750³?
875³ – 750³ = 444,734,375.
First, find the cube of 875³, that is 669,921,875 Next, find the cube of 750³, which is 421,875,000 Now, find the difference between them using the subtraction method. 669,921,875 – 421,875,000 = 248,046,875 Therefore, 875³ is 248,046,875 larger than 750³.
If a cube with a side length of 875 cm is compared to a cube with a side length of 100 cm, how much larger is the volume of the larger cube?
The volume of the cube with a side length of 875 cm is 669,921,875 cm³
To find its volume, we multiply the side length by itself three times (since it’s a 3-dimensional object). Cubing 875 means multiplying 875 by itself three times: 875 × 875 = 765,625, and then 765,625 × 875 = 669,921,875. The unit of volume is cubic centimeters (cm³), because we are calculating the space inside the cube. Therefore, the volume of the cube is 669,921,875 cm³.
Estimate the cube of 874 using the cube of 875.
The cube of 874 is approximately 669,921,875.
First, identify the cube of 875, The cube of 875 is 875³ = 669,921,875. Since 874 is only a tiny bit less than 875, the cube of 874 will be almost the same as the cube of 875. The cube of 874 is approximately 669,921,875 because the difference between 874 and 875 is very small. So, we can approximate the value as 669,921,875.
Binomial Formula: It is an algebraic expression used to expand the powers of a number, written as (a + b)ⁿ, where ‘n’ is a positive integer raised to the base. The formula is used to find the square and cube of a number. Cube of a Number: Multiplying a number by itself three times is called the cube of a number. Exponential Form: It is a way of expressing numbers using a base and an exponent (or power), where the exponent value indicates how many times the base is multiplied by itself. For example, 2³ represents 2 × 2 × 2 equals 8. Volume of a Cube: It is the space occupied by a cube, calculated using the formula side³, where 'side' is the length of one side of the cube. Perfect Cube: A number that can be expressed as the cube of an integer. For example, 8 is a perfect cube because it can be expressed as 2³.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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