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202 LearnersLast updated on October 28, 2025

The complement of A union B (A∪B)' is an important concept in set theory. This concept helps us understand how sets relate to each other by using operations like union, intersection, and complement. In this article, we will be learning more about A union B complement.
A union B complement refers to all the elements that are not in either set A or set B. It shows what lies outside the combined elements of both sets.
It is often written as \((A∪B)′ \) and can also be expressed using De Morgan’s Law as \(A′∩B′\).
A Venn diagram depicts the universal set U along with sets A and B. In the diagram shown below, the purple-colored area represents A union B complement. It gives us an idea about the elements that are not present in A or B.
To find the formula for the complement of A union B, we look for elements that are not in A or B.
According to set theory, the formula can be written using De Morgan’s Law. The laws says:
Proof of A Union B Complement
We need to prove that \((A \cup B)' = A'\cap B'\)
Here, we will be proving that both sides are subsets of each other.
So,\(\ (A \cap B)’ \subseteq (A \cup)B'\)
Here are a few tips and tricks to effectively solve A union B complement.
Parent Tip: Relate union, complement and intersection to real-life objects and situation to help children understand better. Encourage to draw Venn diagram for better visualization.
Understanding and solving the complement of A union B is not easy for students. They also make mistakes while solving this. This section aims at pointing out some common mistakes so that we can avoid making them.
A union B complement has many real-life applications in various fields. Some of these applications have been mentioned below:
A = {1, 2}, B = {3, 4}, U = {1, 2, 3, 4, 5}
(A \(\cup\) B)’ = {5}
So, the complement of the union of A and B is {5}.
A = {a, b}, B = {b, c}, U = {a, b, c, d}
(A \(\cup\) B)’ = {d}
A = {2, 4, 6}, B = {1, 3, 5}, U = {1, 2, 3, 4, 5, 6}
\((A \cup B)' = \phi\)
A = {x, y}, B = , U = {x, y, z}
\((A \cup B)'\) = {z}
A = , B = , U = {1, 2}
\((A \cup B)'\) = {1, 2}




