Summarize this article:
210 LearnersLast updated on October 23, 2025

The complement of a set is made up of all elements that are not present in the set, but present within a larger context known as the universal set. The complement of a set B is denoted by B′.
A set is a collection of objects referred to as elements. These elements are grouped because they share a common attribute or because specific rules specify the set. We denote sets using curly brackets “{ }” and separate each element with a comma.
For example, if we list the first few whole numbers, we can express the set as \(W = \{0, 1, 2, 3, 4, 5, …\}\), where W represents the set of whole numbers starting from 0.
The complement of a set A is the collection of all elements in the universal set U that are excluded from A.
It’s written as \(A′ = {x ∈ U | x ∉ A}\) or \(A′ = U - A\). For example, if \(U = \{1, 2, 3, 4, 5\}\) and \(A = \{2, 4\}\), then \(A′ = \{1, 3, 5\}\), consisting of elements excluded from A.
Understanding the properties of the complement of a set will help in solving problems related to intersections, unions, and set relationships.
Below are some of its properties:
The complement of a set A, denoted as A′, includes all the elements in the universal set U that are not in A.
This is expressed as:
\(A′ = {x ∈ U ∣ x ∉ A}\)
We can also write this as:
\(A′ = U - A\)
This means that A′ includes every element of U except those that are in A.
In the given Venn diagram, the universal set U holds two subsets: A and A'.

The complement of a set can be found by excluding the elements of the given set from the universal set.
Example
Universal set \((U): \{1, 2, 3, 4, 5, 6, 7\}\)
Given set \((A): {1, 3, 7}\)
Complement of A (A'):
\(A' = U - A = \{1, 2, 3, 4, 5, 6, 7\} − \{1, 3, 7\}\)
\(A' = \{2, 4, 5, 6\}\)
Step 1: Identify the universal set (U): Define the set that includes all possible elements.
Step 2: Define the given set (A): Identify the set for which you want to find the complement.
Step 3: Subtract elements of A from U: List all elements in U that are not in A.
Step 4: Express the complement: The result is the complement of A, denoted as A'.
Here are some parent and learner friendly tips and tricks for beginners to master complement of a set:
Use Venn diagrams to visualize. Draw circles for sets inside a rectangle representing 𝑈. The shaded part outside 𝐴 (but inside 𝑈) represents 𝐴′. Visualization helps make the concept concrete and prevents errors.
Use De Morgan’s laws to simplify complex problems. When faced with multiple sets: Replace ∪ with ∩ and ∩ with ∪, Then complement each individual set.
Example: \((A∪B∪C)′=A′∩B′∩C′\)
Relate to everyday life. If \(U = all \ fruits\), and \(A = tropical \ fruits\), then \(A′ = non-tropical\ fruits\). Using such relatable examples makes it easier to remember.
Test yourself with quick quizzes. Try writing small universes (like 1–10) and sets, and practice finding complements. Keep track using Venn diagrams or count formulas to cross-check your results.
Usually, the complement of a set is a concept of set theory. In the beginning, it can be confusing to the students. Identifying these mistakes and learning how to avoid them is important for accurate mathematical reasoning.
The complement of a set concept is widely applicable across various fields, aiding in decision-making and analysis. Some of the applications of the complement of a set are:
Given the universal set U = {Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday} and set B = {Monday, Tuesday, Wednesday, Thursday}, find B'.
\(B' = \{Friday, Saturday, Sunday\}\)
The complement of B consists of days in U not in B.
\(U = \{Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday\}\)
set \(B = \{Monday, Tuesday, Wednesday, Thursday\}\)
\(B' = U - B \\ B' = \{Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday\} - \{Monday, Tuesday, Wednesday, Thursday\}\\ B' = \{Friday, Saturday, Sunday\}\)
Let U = {1, 2, 3, 4, 5, 6, 7} and A = {1, 2, 3, 4}, find A'.
\(A' = \{5, 6, 7\}\)
The complement of A consists of elements in U that are not in A.
\(U = \{1, 2, 3, 4, 5, 6, 7\}\)
\(A = \{1, 2, 3, 4\}\)
\(A' = U - A\\ A' = \{1, 2, 3, 4, 5, 6, 7\} - \{1, 2, 3, 4\}\\ A' = \{5, 6, 7\}\)
If U = {a, b, c, d, e, f, g} and C = {a, c, e}, find C'.
\(C' = \{b, d, f, g\}\)
C' includes all elements in U that are not in C
\(U = \{a, b, c, d, e, f, g\}\)
\(C = \{a, c, e\}\)
\(C' = U - C\\ C' = \{a, b, c, d, e, f, g\} - \{a, c, e\}\\ C' = \{b, d, f, g\}\)
Given U = {apple, banana, orange, pear, mango} and D = {apple, banana, orange}, find D'.
\(D' = \{pear, mango\}\)
D' contains fruits in U that are not in D.
\(U = \{apple, banana, orange, pear, mango\}\)
\(D = \{apple, banana, orange\}\)
\(D' = U - D\\ D' = \{apple, banana, orange, pear, mango\} - \{apple, banana, orange\}\\ D' = \{pear, mango\}\)
Let U = {1, 2, 3, 4, 5, 6} and E = {2, 4, 6}, find E'.
\(E' = \{1, 3, 5\}\)
E' includes elements in U not in E.
\(U = \{1, 2, 3, 4, 5, 6\}\)
\(E = \{2, 4, 6\}\)
\(E' = U - E\\ E' = \{1, 2, 3, 4, 5, 6\} - \{2, 4, 6\}\\ E' = \{1, 3, 5\}\)
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.






