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194 LearnersLast updated on October 22, 2025

The vertical line test is used to check whether the graph represents a function by checking whether a vertical line intersects the graph at more than one point. This article explains the vertical line test and how it works.
One can verify whether a curve represents a function in the coordinate plane by drawing a vertical line parallel to the y-axis. The curve assigns precisely one y-value to each x-value if this vertical line intersects the curve at only one point for each x-value.
Then the graph represents a function. On the other hand, the curve is not a function if the line crosses it more than once, resulting in multiple y-values for the same x-value.
To perform the vertical line test:
The first graph \((y = x²)\) has only one intersection with a vertical line at \(x = 1\). Therefore, it passes the test and is a function. The second graph, which is the circle with \(x² + y² = 1\), does not represent a function and fails the test because it has two intersection points with a vertical line at \(x = 0.5\).
To graphically apply the Vertical Line Test, sketch several vertical lines over the curve parallel to the y-axis. A graph can be considered a function if a line crosses the curve once; if it crosses twice or more, it is not.
Given below are a few tips and tricks that come in handy when students are working with vertical line tests.
Here are common mistakes and ways to avoid them while using the Vertical Line Test, including misaligned lines, domain gaps, and confusion.
Learn how to use the Vertical Line Test to find functional relationships in a variety of real-world situations.
Solve the Linear Function (y = 2x + 1)
The equation \(y = 2x + 1\) represents a function.
Step 1: We will draw a straight line.
Step 2: Insert vertical lines at x = -2, 0, and 2.
Step 3: Every vertical line should make one contact with the graph.
In conclusion, the Vertical Line Test → Function is passed. We will understand it better by the figure given below:
The quadratic function (y = x²)
The equation \((y = x²)\) passes the function.
For a given \(x = c, y = c².\)
For every 𝑐, exactly one 𝑦-value.
No vertical line ever makes multiple strikes.
Passes test ⇒ Function at last.
Circle (x² + y² = 4)
The equation \((x² + y² = 4)\) does not pass the function.
For\( x = c,\qquad y^2 = 4 - c^2 \quad\Rightarrow\quad y = \pm\sqrt{4 - c^2}. \)
Any \( |c| < 2 \) has two real 𝑦-values, one “lower” and one “upper.”
So, for many values of 𝑐, the vertical line intersects the graph at two points.
Therefore, if fails the test, ⇒ Not a function at last.
Cubic Function (y = x³)
Figure shown below.
Step 1: Draw the S-curve.
Step 2: Add vertical lines all across the domain.
Consequently, the ending shows every line crossing once. Lastly, the function is passed.
Sideways Parabola (x = y²)
Shown in the figure below.
The first step is to plot the sideways U-curve.
Step 2: Draw vertical lines in step two at x = 1 and 2. Each vertical line intersects the sideways parabola at two points, so it fails the test.
Step 3: Every vertical line intersects at two spots.
So it fails → Not a Function, at last.




