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144 LearnersLast updated on October 28, 2025

Compound inequalities are two inequalities that are joined by the words "and" or "or". Each part is solved like a regular inequality, but the final answer depends on whether both conditions must be true (“and”) or just one needs to be true (“or”).
A compound inequality merges two separate inequalities using the words “and” or “or”. Conjunction means both must hold simultaneously, like -1 < x < 3, while disjunction uses “or,” requiring at least one condition to be true.
Study Strategy: Think of compound inequality as restrictions. Like if you are allowed to have less than three chocolate per day, then it can be said the number of chocolate you eat per day can be more than 0 but should be less than 3.
This can be mathematically expressed as 0 < x < 3, where 'x' represents the number of chocolates you eat per day.
To represent a compound inequality on a graph, follow the steps mentioned below:
Let's practice this using a word problem
Practice Problem: Suppose you have $4, and you want to buy a toy. So, the money you can spend can be more than $0 or less than $4. Express these inequalities mathematically and on graph.
Solution: Lets represents the money with variable x.
Expressing these inequalities on graph:
The intersection of both regions will be the solution of \(0 < x \le 4\).
For solving compound inequalities, students needs to follow the steps given below:
Students often find compound inequalities difficult and confusion at first. To ease the process, let’s focus on some tips and tricks to help you easily grasp the concept of compound inequalities.
Parent Tip:
Students might make mistakes while dealing with compound inequalities. Some of these mistakes are common and can be avoided. Take a look at these common mistakes so that you can avoid them in the future.
Compound inequalities are used in our daily life. It helps us in budgeting and monitoring speed limits and temperature ranges. We will be learning in the field of architecture, nature, biology, art, and design also.
Solve −3 ≤ 2x −1 < 5
−1 ≤ x < 3
Start with the compound inequality:
−3 ≤ 2x −1 < 5
Step 1: Add 1 to all three parts to isolate the term with x:
−2 ≤ 2x < 6
Step 2: Divide all parts by 2:
−1 ≤ x < 3
Solve 4x − 7 > 9 or 2x + 1 ≤ −3
x > 4 or x ≤ −2
We’re given: 4x − 7 > 9 or 2x + 1 ≤ − 3
Solve each part separately:
1. 4x − 7 > 9
Add 7: 4x > 16
Divide by 4: x > 4
2. 2x + 1 ≤ −3
Subtract 1: 2x ≤ −4
Divide by 2:
x ≤ −2
Combine using OR:
Final Answer: x > 4 or x ≤ −2
If 7 is less than 2x + 1 which is also at most 15, what can x be?
3 < x ≤7
We’re given: 7 < 2x +1 ≤ 15
Step 1: Subtract 1 from all parts
6 < 2x ≤ 14
Step 2: Divide all parts by 2
3 < x ≤7
Solve −2 ≤ 4 −3x < 10
−2 <x ≤ 2
We’re solving the compound inequality: −2 ≤ 4 −3x < 10
Step 1: Subtract 4 from all parts
−6 ≤ −3x < 6
Step 2: Divide all parts by -3, and flip the inequality signs
2 ≥ x > −2
Rewriting in standard form:
−2 <x ≤ 2
Solve 6x − 3 < 9 and 2x + 7 ≥ 3
−2 ≤ x < 2
We’re solving a compound inequality using "and": 6x − 3 < 9 and 2x + 7 ≥ 3
Solve each part:
1. 6x − 3 < 9
Add 3: 6x < 12
Divide by 6: x < 2
2. 2x + 7 ≥ 3
Subtract 7: 2x ≥ −4
Divide by 2: x ≥ −2
Combine using AND (overlap):
Final answer: −2 ≤ x < 2




