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Last updated on October 30, 2025

Zeros of a Cubic Polynomial

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The zeros of a polynomial are the values of x for which f(x) = 0. To find a zero, you can use trial values to divide the polynomial, factor the result, and solve the remaining cubic or quadratic equations.

Zeros of a Cubic Polynomial for US Students
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What are Zeros of a Cubic Polynomial?

The zeros of a cubic polynomial are the points at which the polynomial becomes zero. Since the highest degree of a cubic polynomial is three, it can have up to three zeros. A cubic polynomial always has at least one real solution, whereas a quadratic polynomial might not have any. Some or all zeros may be repeated.
In the cubic polynomial \(ax^3 + bx^2 + cx + d = 0 \), where a ≠ 0 and a, b, c are the coefficients of x3, x2, x, and d is the constant term, let α, β, and γ be the zeros.

 

Zeros of Cubic Polynomial Formulas
A cubic polynomial formula’s sum of zeros is \(α+β+γ= -b/a\)
A cubic polynomial formula’s sum of the products of zeros is \(αβ+βγ+γα=c/a\)
A cubic polynomial formula’s product of zeros is \(αβγ= -d/a\)


Properties of Zeros of a Cubic Polynomial
Since its degree is 3, a cubic polynomial can have at most three zeros.
Even if the other two are complex, every cubic polynomial with real coefficients will have at least one real zero.
For a cubic polynomial \(ax^3 + bx^2 + cx + d \) with zeros p, q, r:
\(p + q + r = -\frac{b}{a} \)  it is the sum of zeros.
\(pq + qr + rp = \frac{c}{a} \) it is the sum of the products taken two at a time.
\(pqr = -\frac{d}{a} \) it is the product of the zeros.
 

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How to Find Zeros of a Cubic Polynomial?

Consider a cubic polynomial with the formula \(ax^3 + bx^2 + cx + d = 0 \), where a. A cubic polynomial can have three zeros because its highest power (or degree) is three.  Since three is a cubic polynomial’s highest power (or degree), it is possible for it to contain three zeros.


By taking the actions listed below, we can quickly determine a cubic polynomial’s zeros:


Step 1: Assume that the three zeros of a given cubic polynomial are (p - q), p, and (p + q).

Step 2: Utilizing a cubic polynomial formula’s sum of zeros, find p.

Step 3: Factor the equation into a quadratic polynomial to determine the remaining two zeros.

For example, find the zeros of the cubic polynomial
\(x^3 - 12x^2 + 39x - 28 = 0 \)
Let the zeros of a given cubic polynomial be (p - q), p, and (p + q). Then, a cubic polynomial’s sum of zeros equals -b / a.

\((p + q) + p + (p - q) = -12/1\)
\(3p = 12\)
\(p = 4\).

Now factorize the equation into a quadratic polynomial to determine the remaining two zeros.

\(x^3 - 12x^2 + 39x - 28 = (x - 4)(x^2 - 8x + 7) \)
\( x^3 - 12x^2 + 39x - 28 = (x - 4)(x - 1)(x - 7) \)

⇒x = 1, x = 4, and x = 7 are the three zeros of the given cubic polynomial.
 

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Product of Zeros of a Cubic Polynomial

Let α, β, and γ be the cubic polynomial \( ax^3 + bx^2 + cx + d = 0 \), where a ≠ 0 and a, b, and c are the coefficients of \(x^3\), \(x^2\), and x, and d is the constant term. Next, a cubic polynomial’s product of zeros is provided as follows:

Product of zeros of a cubic polynomial = \( -\dfrac{\text{constant term}}{\text{coefficient of } x^3} \).

\( \alpha \beta \gamma = -\frac{d}{a} \).

Example: Determine the cubic polynomial \(\ kx^3 - 5x^2 - 12x + k = 0 \ \)
.
If the polynomial is \(\ kx^3 - 5x^2 - 12x + k = 0 \), then we have a = k, and d = k.

Product of zeros = -(constant term)/(coefficient of \(x^3\))

\(\ \alpha \beta \gamma = -\frac{k}{k} = -1 \ \)

Therefore, the product of the zeros of a cubic polynomial is -1.


Sum of Zeros of a Cubic Polynomial
Let α, β, and γ be the zeros of the cubic polynomial \(\ ax^3 + bx^2 + cx + d = 0 \ \) where a ≠ 0, where a, b, and c are the coefficients of \(x^3\),\(x^2\), and x and d is the constant term. Next, a cubic polynomial’s sum of zeros is expressed as follows:

\(\ \text{The sum of zeros of a cubic polynomial} = -\frac{\text{coefficient of } x^2}{\text{coefficient of } x^3} \ \)

\(\ \alpha + \beta + \gamma = -\frac{b}{a} \ \).

Example: Determine the cubic polynomial \(\ 5x^3 - 15x^2 - 12x + 27 = 0 \ \).

\(\ \text{Sum of zeros of a cubic polynomial} = -\frac{\text{coefficient of } x^2}{\text{coefficient of } x^3} \ \)
\(\ \alpha + \beta + \gamma = -\frac{b}{a} \ \).

If the polynomial is \(\ 5x^3 - 15x^2 - 12x + 27 = 0 \ \), then we have
a= 5 and b = -15.

Sum of zero = -ba

\(\ \alpha + \beta + \gamma = -\left(-\frac{15}{5}\right) = 3 \ \)

Therefore, the given cubic polynomial’s sum of zeros is 3.
 

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Nature of Zeros of a Cubic Polynomial

Consider a cubic polynomial with the formula \(\ ax^3 + bx^2 + cx + d = 0 \ \), where a ≠ 0. The nature of these zeros can be defined by the use of the discriminant of a cubic polynomial. The following relation proves it:
\(\ D = b^2c^2 - 4ac^3 - 4b^3d - 27a^2d^2 + 18abcd \ \)
Therefore,

  1. The cubic polynomial contains real zeros and at least one repeated zero when D = 0.
     
  2. The cubic polynomial has three distinct and real zeros when D > 0.
     
  3. The cubic polynomial has one real zero and two complex conjugates when 
     

D < 0.
For example,
Determine the type of zeros in the cubic polynomial \( x^3+x=0\). Applying the discriminant formula.
Given that \(x^3+x=0\) is a cubic polynomial, we have 

a = 1, b = 0, c = 1, and d = 0.

We know, \(\ D = b^2c^2 - 4ac^3 - 4b^3d - 27a^2d^2 + 18abcd \ \)
So,

\(\ D = (0)^2(1)^2 - 4(1)(1)^3 - 4(0)^3(0) - 27(1)^2(0)^2 + 18(1)(0)(1)(0) \ \)

\(\ D = 0 - 4 - 0 - 0 + 0 \ \)

\(D=-4<0\)

The given cubic polynomial has one real zero and two complex conjugates since 

D < 0.
 

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Relation Between Zeros and Coefficients of a Cubic Polynomial

The values of the variable for which the polynomial’s value is zero are known as zeros of the polynomial. Let α, β, and γ be the zeros of the cubic polynomial \(\ ax^3 + bx^2 + cx + d = 0 \ \), where a ≠ 0, and a, b, and c are the coefficients of \(x^3\), \(x^2\), x and d is the constant term.


Then, a cubic polynomial’s zeros and coefficients have the following relationship:


Sum of zeros = -ba
\(\ \alpha + \beta + \gamma = -\frac{b}{a} \ \).


Sum of the product of zeros = ca.
\(\ \alpha\beta + \beta\gamma + \gamma\alpha = \frac{c}{a} \ \).


Product of zeros = -da
\(\ \alpha\beta\gamma = -\frac{d}{a} \ \).


For Example:
Check the connection between zeros and coefficients of \(\ x^3 + 5x^2 - 6x = 0 \ \) if the zeros are given as -6, -0, and -1.
Comparing the given cubic polynomial with \(\ ax^3 + bx^2 + cx + d = 0 \ \)


⇒a=1, b=5, c=-6, and d=0
Given the zeros: -6, -0, and -1


⇒α=-6,β=0, and γ=1
Check that the cubic polynomial’s zeros sum is correct, i.e.


\(\ \alpha + \beta + \gamma = -\frac{b}{a} \ \)
\(\ (-6) + 0 + 1 = -\frac{5}{1} \ \)
⇒ -5= -5.


Confirm the total product of the cubic polynomial’s zeros, i.e.
\(\ \alpha\beta + \beta\gamma + \gamma\alpha = \frac{c}{a} \ \)
\( (-6)(0) + (0)(1) + (1)(-6) = -6 \)
⇒-6=-6


Confirm that the cubic polynomial’s zeros are multiplied, that is,
\( \alpha\beta\gamma = -\frac{d}{a} \)
\((-6)(0)(1)=-01\)
⇒ 0 = 0.
 

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Tips and Tricks to Master Zeros of Cubic Polynomial

Mastering the zeros of a cubic polynomial helps in understanding the relationship between factors and roots. It also strengthens algebraic problem-solving and graph interpretation skills.

 

  • Always start by checking for common factors in the polynomial before proceeding with other methods it simplifies your work.

     
  • Use the rational root Theorem to test possible rational zeros; it saves time by narrowing down potential values.

     
  • Once you find one zero, use synthetic or long division to reduce the cubic equation to a quadratic and solve easily.

     
  • Remember that the sum and product of zeros relate to the coefficients of the polynomial, helping in quick verification.

     
  • Practice factoring and substitution regularly; familiarity with patterns like \(( 𝑥 − 𝑎 ) ( 𝑥 − 𝑏 ) ( 𝑥 − 𝑐 ) (x−a)(x−b)(x−c)\) improves accuracy and speed.
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Common Mistakes and How to Avoid Them in Zeros of a Cubic Polynomial

Students may make some mistakes on the zeros of a cubic polynomial, like using the wrong trial values, and more. Let us look at the mistakes and learn how to quickly correct them.

Mistake 1

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The function is not set to zero
 

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Always keep in mind that you must set the function equal to zero in order to determine the zeros of the polynomial.
Rather than simply factoring without thinking, write:
\(\ f(x) = x^{3} + 2x^{2} - x - 2 \Rightarrow x^{3} + 2x^{2} - x - 2 = 0 \ \)
To find the zeros, solve the equation now.
 

Mistake 2

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Ignoring formula signs
 

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Always remember, when calculating the sum or product of zeros, many students overlook the negative sign in formulas. For example
For \(\ f(x) = 2x^{3} + 3x^{2} - x - 6 \ \), the product of zeros is:
\(\ \alpha\beta\gamma = -\frac{d}{a} = -\frac{-6}{2} = 3 \ \)
Signs should always be checked twice before being entered into the formula.

Mistake 3

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Making use of quadratic equation formulas
 

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Always keep in mind that you, avoid using quadratic formulas for the product of zeros, like ca.
For the cubic polynomials, use \(ax^3+dx^2+cx+d:\)
For the product of zeros = -da, and not ca
Learn the proper formulas for all the cubic expressions.
 

Mistake 4

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The polynomial is not organized in standard form.
 

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Always write the polynomial in the standard descending order of powers before using formulas. For example:
\(f(x)=5-2x+x^3\)
Rewrite as:
\(f(x)=x^3-2x+5\)
Now, accurately identify the coefficients:
A = 1, b = 0, c = -2, d = 5
 

Mistake 5

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Considering all zeros to be actual numbers

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The answer is that not every cubic polynomial has three real roots. Some might have two complex roots in addition to one real one.
For example:
There is only one real zero in \(f(x)=x^3+1\):
x =-1
The other two are complex. Always check by factoring or using the rational root theorem.
 

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Real Life Examples on Zeros of a Cubic Polynomial

Zeros of a cubic polynomial are used in areas like engineering, physics, and more. Let us see how the zeros of cubic polynomials help in real life.
 

  • Engineering - To simulate the form of suspension cables in bridges, engineers employ cubic polynomials. The zeros of the polynomial show the spots where the cable really touches the ground, such as in a hanging wire or bridge support. In design, identifying the zeros helps in identifying stress and anchor points.

     
  • Physics - A cubic equation can be used to model the height of a thrown ball over time. The times the ball touches the ground are indicated by the zeros. This helps in determining the flight’s maximum range and duration.

     
  • Profit models for business - A business uses a cubic function to model its profit over time.
    \(\ P(x) = -2x^{3} + 15x^{2} - 30x + 10 \ \) This function’s zeros indicate break-even points, or times when the profit is zero. When the profit is zero. For financial planning, this is helpful.

     
  • Speed optimization in automotive design - A cubic equation can be used to model the relationship between vehicle speed and fuel efficiency. The zeros represent the speeds at which fuel efficiency is zero or ineffective. This helps in design improvement for increased mileage.

     
  • Environmental science - Cubic polynomials are used to simulate the water flow rate in a dam or river over time. When the flow rate is zero, the zeros alert scientists, which may indicate a flood or drought warning.
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Solved Examples On Zeros of a Cubic Polynomial

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Problem 1

Find the zeros of f(x)=x3-6x2+11x-6

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\(\ f(x) = 0 \Rightarrow x^{3} - 6x^{2} + 11x - 6 = 0 \ \)
 

Explanation

By trying with different values, we discover that x = 1 satisfies the equation. When x = 1 is substituted into the polynomial, gives  1-6+11-6=0 is obtained, confirming that x = 1 is a zero. The quotient is, \(\ x^{2} - 5x + 6 = (x - 2)(x - 3) \ \). As a result, the full factorization of the polynomial is \(\ f(x) = (x - 1)(x - 2)(x - 3) \ \), and its zeros are 1, 2, and 3.
 

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Problem 2

Find the zeros f(x)=x3+3x2-4x-12=0

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\(\ f(x) = 0 \Rightarrow x^{3} + 3x^{2} - 4x - 12 = 0 \ \)
 

Explanation

We test x = 2 in the polynomial, and we get \(\ 8 + 12 - 8 - 12 = 0 \ \), which means that x = 2 is a zero.
Next, the cubic polynomial is then divided by (x - 2), resulting in the quotient \(\ x^{2} + 5x + 6 \ \). After factoring this with a quadratic component, we obtain \(\ x^{2} + 5x + 6 = (x + 2)(x + 3) \ \). that the function’s zeros are -3, -2, and 2, and its fully factorized form is \(\ f(x) = (x - 2)(x + 2)(x + 3) \ \)
 

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Problem 3

Find the zeros of f(x)=x3-7x+6

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\(\ f(x) = 0 \Rightarrow x^{3} - 7x + 6 = 0 \ \)
 

Explanation

When we substitute x as 1, such as x = 1, here, we obtain 1 – 7 + 6 = 0, indicating that x = 1 is a zero.
Next, we divide the polynomial by (x - 1), resulting in the quotient of \(\ x^{2} + x - 6 \ \). This quadratic expression is factored as, \(\ f(x) = (x - 1)(x - 2)(x + 3) \ \) and the zeros are -3, 1, and 2.
 

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Problem 4

Find the zeros of f(x)=2x2-3x2-2x+3=0

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\(\ f(x) = 0 \Rightarrow 2x^{3} - 3x^{2} - 2x + 3 = 0 \ \)
 

Explanation

When we try x = 1, we will get \(\ 2(1)^{3} - 3(1)^{2} - 2(1) + 3 = 2 - 3 - 2 + 3 = 0 \ \), which means x = 1 is a zero. When we divide the cubic polynomial by (x - 1), we will get the quotient that is \(\ 2x^{2} - x - 3 = (2x + 3)(x - 1) \ \). Thus, the fully factorized polynomial is, \(\ f(x) = (x - 1)^{2}(2x + 3) \ \) with the zero being 1 (repeated) and -32.
 

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Problem 5

Find the zeros of f(x)=x3-4x2-x+4

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\(\ f(x) = 0 \Rightarrow x^{3} - 4x^{2} - x + 4 = 0 \ \)
 

Explanation

After experimenting with various values, we discovered that x = 1 satisfies the equation. When x = 1 is substituted into the polynomial, \(\ 1 - 4 - 1 + 4 = 0 \ \) is obtained, indicating that x = 1 is a zero. The polynomial is then divided by (x - 1), resulting in the quotient \(\ x^{2} - 3x - 4 \ \). The quadratic expression is then factored as follows: \(\ x^{2} - 3x - 4 = (x - 4)(x + 1) \ \). Therefore, the full factorization is\(\ f(x) = (x - 1)(x - 4)(x + 1) \ \), and the zeros of the polynomial are -1, 1, and 4.
 

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FAQs On Zeros of a Cubic Polynomial

1.What is a cubic polynomial?

A cubic polynomial is an algebraic expression of degree 3, which is written in the form \(\ f(x) = ax^{3} + bx^{2} + cx + d \ \), where a ≠ 0 and a, b, c, and d are real numbers.
 

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2.How many zeros can a cubic polynomial have?

A cubic polynomial has exactly three zeros, though some of them are repeated or complex numbers.
 

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3.Can a cubic polynomial have repeated zeros?

Yes, this means one or more zeros can occur more than once, such as in a polynomial \(\ f(x) = (x - 2)^{2}(x + 3) \ \), where x=2 that has a repeated zero.
 

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4.How to find the zeros of cubic polynomials?

First, try values using the factor theorem to find one zero. Then, divide the polynomial by the corresponding linear factor and factor the resulting quadratic expression to find the remaining zeros.
 

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5.Can all the zeros of a cubic polynomial be complex?

No, a cubic polynomial must have at least one real zero. If it has complex zeros, they always occur in conjugate pairs (like a+bi and a - bi).

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6.How much time should my child spend on this topic?

A few short, focused practice sessions are better than one long study session. Regular revision and solving 2–3 problems daily help strengthen understanding without stress.

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7.What should I tell my child if they ask why this is important?

Explain that zeros help us understand how functions behave where they rise, fall, or change direction. This concept is used later in higher studies like calculus, data modeling, and even computer programming.

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8.How can I help my child understand what zeros mean?

Explain that zeros are the values of 𝑥 that make the polynomial equal to zero like points where a ball hits the ground. You can use simple graphs to show where the curve touches or crosses the x-axis.

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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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