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Last updated on October 16, 2025
In mathematics, ‘i’ refers to the imaginary unit, which is defined as i = √(-1). In this article, let’s learn about imaginary numbers, how they are represented on a plane, and their applications.
As the name suggests, imaginary numbers are not real, as they involve the square root of a negative number. A non-zero real number multiplied by the imaginary unit ‘i’ (which is also called iota), where i = √(-1), results in an imaginary number.
Let’s understand this better by squaring some real numbers:
(- 4)2 = -4 × -4 = 16
(82) = 8 × 8 = 64
(1.5)2 = 1.5 × 1.5 = 2.25
In the above examples, were there any negative numbers? No. This indicates that any real number's square is always positive. Therefore, we need imaginary numbers to produce a negative square. We frequently encounter the square root of negative numbers in mathematics, particularly when applying the quadratic formula to solve quadratic equations. It is necessary to use imaginary numbers in these situations. Let’s now take a look at some imaginary numbers:
√(-4) = √(-1) · √4 = i (2) = 2i
√(-3) = √(-1) · √3 = i √3
The real number system is extended to include complex and imaginary numbers. Any number that includes the square root of a negative number is considered an imaginary number. They are of the form bi, where b \(\neq\) 0. The fundamental imaginary unit, represented by 𝑖, is the square root of −1.
This indicates that 𝑖² = −1. On the other hand, a complex number includes both imaginary and real numbers. They are of the form a + bi, where a is the real part and b is the imaginary part.
Students can perform addition and subtraction by combining like terms, real with real, imaginary with imaginary.
Example for addition:
\((3 + 2i) + (1 + 4i) = (3 + 1) + (2i + 4i) = 4 + 6i \)
Example for subtraction:
\((5 + 7i) - (2 + 3i) = (5 - 2) + (7i - 3i) = 3 + 4i \)
Multiplication uses the distributive property: each term of the first complex number is multiplied by each term of the second. Remember, i2 = -1
\( (2 + 3i)(4 + i) = 2 \times 4 + 2 \times i + 3i \times 4 + 3i \times i \)
\(= 8 + 2i + 12i + 3i^2\)
\(= 8 + 14i + 3(-1) = 5 + 14i\)
For complex numbers, dividing complex numbers involves multiplying the numerator and denominator by the conjugate of the denominator to remove its imaginary part.
For example, divide: \( \frac{4 + 2i}{1 - i} \)
\( =\frac{4 + 2i}{1 - i} \)
\(= \frac{(4 + 2i)(1 + i)}{(1 - i)(1 + i)} \)
\(= \frac{4 + 4i + 2i + 2i^2}{1 - i^2} \)
\(= \frac{4 + 6i + 2(-1)}{1 - (-1)} \)
\(= \frac{2 + 6i}{2} = 1 + 3i\)
The “plane” in complex numbers refers to the complex plane, also called the Argand plane. This graph shows both the real and imaginary parts of a complex number: the horizontal axis represents real numbers, and the vertical axis represents imaginary numbers. A pure imaginary number, like 3i or −2i, lies on the vertical axis since its real part is zero.
For example, consider the complex number 3+4i. You move 3 units along the X-axis (real part) and 4 units along the Y-axis (imaginary part), plotting the point (3, 4). This point can be visualized as a vector from the origin (0, 0) to (3, 4). Dashed lines often show the movement along each axis. Such visualizations help in understanding operations like addition, subtraction, or finding the modulus; here, the modulus is \(|3 + 4i| = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5.\)
In mathematics, 𝑖 is the imaginary unit, defined by \(i^2= -1\). It was introduced because no real number squared gives a negative result. This allows us to work with complex numbers of the form a+bi, where a and b are real.
For example, in 2+3i, 2 is the real part and 3𝑖 is the imaginary part. Equations like \(x^2+1=0\) this can now be solved, giving x = i, and x = -i
The basic definition of the imaginary unit, 𝑖, where 𝑖= -1, is used to calculate imaginary numbers. The property 𝑖² = −1 is added to standard arithmetic rules when calculating with imaginary numbers. The square root of −9, for instance, can be expressed as follows: -9 = 9 (-1) = 9 -1 = 3𝑖.
The imaginary unit i has a unique property:
\(i^2=−1\) From this, higher powers of i follow a repeating pattern:
𝑖1 = 𝑖,
𝑖2 = −1,
𝑖3 = −𝑖,
and 𝑖4 = 1
This cycle repeats every four powers. In general, for any positive integer 𝑛:
\(i^n = i^{n \bmod 4} \)
For example: calculate i27:
\(27 \div 4 = 6 \text{ remainder } 3 \implies i^{27} = i^3 = -i \)
Solving problems involving imaginary numbers can get tricky. That’s why it is important to have a few tricks up our sleeves. Take a look at some handy tips and tricks given below to stay ahead of the curve.
For beginners, comprehending imaginary numbers can be challenging, particularly when addressing their special characteristics. This section lists some of the most frequent errors made when working with imaginary numbers and offers helpful tips for avoiding them. Students can improve their understanding of complex number operations and establish a more secure mathematical foundation by identifying these mistakes early on.
Imaginary numbers, represented by i, extend the real number system and allow us to solve equations and model problems that cannot be addressed with only real numbers.
What is the square root of -36?
6i
Since it is known that √-1 = i,
Therefore, √-36 can be written as,
√-36 = √36 . √-1 = 6i
Add the Imaginary Numbers 4i + 7i
11i
We will be adding the coefficients of i, that is 4 + 7, which will give 11.
Therefore, the imaginary numbers 4i + 7i will be 11i.
Multiply i7
– i
For the solution, will be following the power cycle,
i1 = i, i2 = -1, i3 = -i, i4 = 1 (pattern repeats every 4 powers)
i7 = i4 + 3
i7 = i4 . i3
Substitute the values of i4 and i3, we get the simplified form of, i7 which gives the result as -i.
Subtract 3i from 7i
4i
Let’s subtract 7i - 3i:
7i - 3i = (7 - 3)i = 4i
Here, we’ve just subtracted the numbers 3 from 7 and retained i (imaginary part).
Divide 4i by -2i.
-2
Let’s take the equation 4i/-2i
4i/-2i can be written as
4/-2 . i/i
= -2 . 1
= -2