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293 LearnersLast updated on December 15, 2025

A cubic polynomial is an important mathematical concept. It plays a vital role in various scientific fields like physics, economics, and engineering. In this article, we will learn the formula, graph, and roots of cubic polynomials.

A polynomial is a mathematical expression that consists of constants, variables, and exponents, depending on its type. For example, a type of polynomial where the highest degree of the variable is 3 is called a cubic polynomial. It is expressed as \(ax^3 + bx^2 + cx + d\). Here, we can see that the highest power of the variable x is 3. The coefficients, a, b, and c, and the constant d, are real numbers and \(a ≠ 0\). A cubic equation is an equation that contains a cubic polynomial.
A cubic polynomial is a polynomial of degree 3. Its general form is:
\(f(x) = ax³ + bx² + cx + d, where a ≠ 0.\)
A cubic equation is when we set the polynomial equal to zero:
\(ax³ + bx² + cx + d = 0\)
The values of x that make f(x) = 0 are called roots.
Examples
\(x³ − 6x² + 11x − 6 = 0 → roots: x = 1, 2, 3\)
\(2x³ + 3x² − 5x − 6 = 0 \)→ roots can be found by factorization
\(x³ + x + 1 = 0 \)→ one real root and two complex roots
A cubic equation has the form:
x³ + bx² + cx + d = 0
Simple Steps
Plug in small numbers like 1, 2, -1, -2 to find a root.
Once you find a root, say r, factor out (x - r).
The remaining part will be a quadratic.
Solve the quadratic to get the other two roots.
Example
x³ - 6x² + 11x - 6 = 0
Try x = 1 → works, so x = 1 is a root.
Factor out (x - 1) → left with x² - 5x + 6
Solve x² - 5x + 6 = 0 → x = 2, 3
All roots: x = 1, 2, 3


Synthetic division is a quick and effective method to reduce a cubic polynomial to a quadratic. The quadratic can then be solved easily. Here, the division of two polynomials can be represented in the form \({p(x) \over q(x)} = Q + {R \over q(x)}\).
Here, p(x) is the dividend
q(x) is the linear divisor.
Q is the quotient
R is the remainder
The steps involved in the synthetic division method are:
Step 1: Make sure the polynomial is in the standard form. If not re-arrange them in standard form, even if the coefficients are zero.
For example, \(x^3 + 2x - 4 \)should be rewritten as \(x^3 + 0x^2 + 2x - 4\). Here, 1, 0, 2, -4 are the coefficients.
Step 2: We will now perform the division by considering the coefficients as the dividend and zero of the linear factor (x - r) as the divisor. Naturally, the coefficients will take the dividend’s place.
Here, the divisor is a linear factor: q(x) = x - r and r is the value that makes the divisor zero. Now write r in the divisor’s place.
Step 3: Write the coefficient of the polynomial in a row. Write r (the zero) to the left.
Step 4: Bring the first coefficient straight down as it is
Step 5: Now multiply the number just brought down by r, and write the result under the next coefficient and add. Repeat the process for all coefficients.
Step 6: Group the coefficients and the variables together to get the quotient. The last number is the remainder and other numbers gives the quotient, which is one degree less than the original polynomial.
Step 7: Use factorization or quadratic formula to find the remaining roots.
The factor theorem helps identify factors and roots, which simplifies the factoring of the polynomial. Let’s see how the factor theorem can be used to solve a cubic polynomial \(p(x) = ax^3 + bx^2 + cx + d\):
Step 1: Identify possible rational roots by using the rational root theorem. If required, use the synthetic division method to see if the remainder is 0.
Step 2: Confirm that \(x - r\) is a factor by checking if the remainder from synthetic division is 0.
Step 3: Divide p(x) by \(x - r\) by using the synthetic division method to get a quadratic quotient. Once the quadratic quotient is found, the given polynomial can be written as \(p(x) = (x - r) \)(quadratic).
Step 4: Solve the quadratic further if the remainder is not equal to zero and find the remaining roots.
A cubic polynomial can also be solved with the help of graphs. The roots of the polynomial can be found by looking at the points where the graph cuts or crosses the x-intercept. There are two things we should remember while plotting the graph:
Here is a step-by-step process on how to sketch the graph of a cubic polynomial:
Step 1: The first step is to find the y-intercept. In other words, we should evaluate p(0).
Step 2: Use the rational root theorem to find the roots. Once the roots are found, we can apply synthetic division to confirm the roots. Once we confirm the roots, we can factor the polynomial.
Step 3: Check the sign of a, which will later decide how the graph looks.
Step 4: Plot the points obtained from the calculations. After this, we can draw a smooth curve to finish the graph.
A cubic polynomial’s roots represent the values of x in such a way that they equate the polynomial to zero. Usually, a cubic polynomial will have three roots, including complex roots. Their properties are as follows:
If the multiplicity is 1, then the graph cuts the x-axis. For multiplicity 2, the graph touches the x-axis and turns back. When multiplicity is 3, the graph flattens at the x-axis. It then crosses the x-axis, giving rise to an S-shaped curve.
Learning cubic polynomials helps students understand complex curves, solve real-world problems, and develop analytical skills. Here are a few tips and tricks:
Before solving a cubic polynomial, always check if there is a common factor among all terms. Factorization simplifies the cubic equation and often reduces it to a quadratic, which makes it easier to solve.
Teach factorization step by step by factoring common terms and using grouping.
Encourage solving in stages, factor first, then solve the remaining quadratic.
Students can make mistakes while working on cubic polynomials. Here are a few common mistakes that anyone can avoid:
Cubic polynomials are used to model and solve many real-world problems involving curved or nonlinear relationships. Understanding how to use cubic polynomials helps in several fields beyond academics.
Find f (2) for the polynomial function f (x) = x3 + 2x2 - 4x
8
Substituting x = 2, we obtain:
\(f (2) = 2^3 + 2(2)^2 - 4(2) \)
\( = 8 + 2(4) - 8 \)
\(= 8 + 8 - 8\)
\(= 8\)
Find f (1) for the function f (x) = -2x^2 + x^3 + 6 - 10x
-5
First, we should rearrange the polynomial function in the correct order.
So, the correct order is \(f (x) = x^3 - 2x^2 - 10x + 6\). Now, let us substitute the value of x as 1 in the rearranged polynomial function:
\(f (1) = (1)^3 - 2(1)^2 - 10(1) + 6\)
\(= 1 - 2 - 10 + 6 \)
\(= -5 \)
Find f (3) for the function f (x) = 4x^3 + x^2
117
Replacing x with 3 in the equation, we get:
\(f (3) = 4(3)^3 + (3)^2 \)
\(= 4(27) + 9 \)
\(= 108 + 9 \)
\(= 117\)
Find f (-2) for the function f (x) = x^3 + x
-10
Changing the value of x to -2 in the equation, we get:
\(f (-2) = (-2)^3 + (-2) \)
\(= -8 - 2 \)
\(= -10 \)
Find f(-4) for the function f (x) = -x + 2x^2 + 4 - x^3
104
Rewrite the function in the standard form,
\(f (x) = - x^3 + 2x^2 - x + 4\)
Now, let us replace the value of x with -4 in the rearranged equation.
So, \(f(-4) = -(-4)^3 + 2(-4)^2 - (-4) + 4 \)
\(= - (-64) + 2 (16) + 4 + 4 \)
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.






