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252 LearnersLast updated on December 15, 2025

Polynomials are expressions that include variables and constants connected by operations such as addition, subtraction, and multiplication. They are essential in the field of mathematics and are used to solve algebraic equations.

Polynomials are algebraic expressions made up of constants and in determinate. They are used to represent numbers in almost all branches of mathematics. For instance, 2x + 9 and x2 + 3x + 11 are polynomials.
The highest exponent is the polynomial's degree. Polynomials can be subjected to a variety of operations, including addition, subtraction, multiplication, and division.
Examples of Polynomials
2x + 9
This is a polynomial of degree 1 (linear polynomial).
\(x2 + 3x + 11\)
This is a polynomial of degree 2 (quadratic polynomial).
\(5x3 − 4x + 7\)
This is a polynomial of degree 3 (cubic polynomial).
7
This is a constant polynomial with degree 0.
\(4x4 + x2 − 6\)
This is a polynomial of degree 4.
The degree of a polynomial is the highest or greatest exponent of the variable in the polynomial.
This degree is used in Descartes’ rule of signs for calculating the maximum zeroes a polynomial equation can have.
Let us take an example.
Example:The polynomial 3x4 + 7 has a degree of 4.
Here, the degree of the polynomial is the highest exponent amongst all variables.
The standard form of a polynomial is the way of writing all terms in descending order. The expression with the highest exponent comes first, then the terms with descending powers. The process ends at the constant term, which has no variables.
For example: Arrange the polynomial 4 + 3x2 + x in standard form.
Explanation: To express the above expression in standard form, we will find the highest exponent in this expression, which is x2, so the 3x2 term will come first.
Then, we will arrange them in decreasing powers accordingly until the constant term at the end. So, the standard form of 4 + 3x2 + x will be: 3x2 + x + 4.


Polynomials are classified into different types based on their degree and the number of terms. Based on the number of terms, polynomials are classified as monomials, binomials, and trinomials.
Polynomials can be classified based on their degree (the highest power of the variable).
These classifications make it easier to identify and solve polynomials.
A term in a polynomial is a single component of the expression that consists of a variable raised to a power (called an exponent) and a number (called a coefficient). Positive (+) or negative (-) symbols are used to separate terms.
Every polynomial is composed of one or more terms. Among the terms are
Theorem 1: Degree of Polynomials
Definition: For two polynomials A and B:
The degree of (A ± B) is less than or equal to the greater of the degrees of A and B.
The degree of (A × B) is the sum of their degrees.
Example
A(x) = 3x² + 2x
B(x) = x³ − 5
Degree of (A + B) = 3
Degree of (A × B) = 2 + 3 = 5
Theorem 2: Division Algorithm
Definition: For any polynomials A and B, where B ≠ 0, there exist polynomials Q and R such that
A = BQ + R, where the degree of R is less than the degree of B.
Example
x² + 3x + 2 ÷ (x + 1)
= (x + 1)(x + 2) + 0
Theorem 3: Factor (Bézout’s) Theorem
Definition: (x − a) is a factor of P(x) if and only if P(a) = 0.
Example
P(x) = x² − 4
P(2) = 0
So, (x − 2) is a factor.
Theorem 4: Zeros of Factors
Definition: If polynomial Q divides polynomial P, then every zero of Q is also a zero of P.
Example
P(x) = (x − 1)(x + 2)
Zeros are 1 and −2.
Theorem 5: Factorization Theorem
Definition: A polynomial of degree n can be expressed as a product of n linear factors.
Example
2x² − 8 = 2(x − 2)(x + 2)
Theorem 6: Number of Roots
Definition: A polynomial of degree n has exactly n roots, counting multiplicities.
Example
x³ − 1 has three roots.
Theorem 7: Coprime Divisibility
Definition: If a polynomial is divisible by two coprime polynomials, then it is divisible by their product.
Example
If a polynomial is divisible by (x − 1) and (x + 1),
then it is divisible by (x − 1)(x + 1).
Theorem 8: Complex Conjugate Roots
Definition: If a real polynomial has a complex root, then its complex conjugate is also a root.
Example
If 2 + 3i is a root, then 2 − 3i is also a root.
Theorem 9: Factorization of Real Polynomials
Definition: A real polynomial can be factored into linear factors and quadratic factors with no real roots.
Example
P(x) = (x − 1)(x² + 4)
Theorem 10: Remainder Theorem
Definition: The remainder when f(x) is divided by (x − a) is f(a).
Example
f(x) = x³ − 2x + 1
Remainder when divided by (x − 2) = f(2) = 5
Theorem 11: Rational Root Theorem
Definition: Any rational root of a polynomial is of the form p/q,
where p divides the constant term, and q divides the leading coefficient.
Example
For 2x³ − 3x − 1,
Possible rational roots are ±1 and ±1/2
Like numbers, polynomials can be used in various mathematical operations, such as addition, subtraction, multiplication, and division. In order to properly simplify or solve polynomial expressions, these operations adhere to certain procedures and guidelines.
1. Addition: Like terms, or terms with the same variable raised to the same power, are combined when adding polynomials.
For example, in the expression (3𝑥2 + 2𝑥 + 5) + (4𝑥2 − 𝑥 + 1), we add the like terms by combining the coefficients of x2, x and the constant terms separately:
3x2 + 4x2 = 7x2
2x - x = x
5 + 1 = 6
7𝑥2 + 𝑥 + 6.
2. Subtraction: Similar to addition, subtraction involves first changing the signs of the terms in the polynomial being subtracted.
For example, in (5𝑥2 + 3x − 2) − (2x2 + x + 4), we will distribute the minus sign to all terms of the second polynomial. Therefore, (2x2) becomes (−2x2), x becomes −x, and + 4 becomes −4.
− 2x2 + x + 4 = − 2x2 − x − 4.
= 5𝑥2 + 3𝑥 − 2 − 2x2 − 𝑥 − 4
= (5x2 − 2x2) + (3x − x) (− 2 − 4)
= 3x2 + 2x − 6
Changing the signs guarantees accurate subtraction and helps to prevent errors.
3. Multiplication: For the multiplication of polynomials, all terms of the first polynomial are multiplied by all terms in the second. We can use the distributive or FOIL method to multiply
\((x + 2)(x + 3) = x × x + x × 3 + 2 × x + 2 × 3\)
=\( x^2 + 3x + 2x + 6 = x^2 + 5x + 6\).
The answer is \( x^2 + 5x + 6\).
When working with polynomials that contain more than two terms, this process may need several steps.
3. Division: The final operation is polynomial division, a more complex process, and the most commonly used methods are synthetic division or long division. On occasion, the expression can be simplified by factoring instead of performing long division.
For instance, the expression \(x^2 + 3𝑥 + 2\) can be easily divided by 𝑥 + 1 by first factoring the numerator into (𝑥 + 1) (𝑥 + 2), now the expression can be simplified into x + 2 after canceling out the common factor.
Factorization of polynomials means breaking a polynomial into simpler factors that, when multiplied, give the original expression. For example,\( x² + 5x + 6\) can be written as (x + 2)(x + 3). It helps in finding roots, simplifying expressions, and solving equations using methods like grouping, common factors, or special formulas such as the difference of squares.
Polynomial Equations
A polynomial equation is an equation formed by setting a polynomial equal to zero.
The general form of a polynomial equation is
\(P(x) = anxn + an-1xn-1 + … + a1x + a0 = 0,\)
where an, an-1, …, a0 are constants and an is not zero.
Solving a polynomial equation means finding the value or values of the variable that make the equation true.
Examples
\(x2 + 3x + 2 = 0\)
\(x3 + x + 1 = 0\)
\(x + 7 = 0\)
Polynomial Functions
A polynomial function is a function defined by a polynomial expression. It contains variables with non-negative integer powers, along with constants and coefficients.
General form
f(x) = anxn + an-1xn-1 + … + a1x + a0, where an ≠ 0.
Examples
\(f(x) = x2 + 4\)
\(g(x) = −2x3 + x − 7\)
\(g(x) = −2x3 + x − 7\)
Finding the values of the variable (often 𝑥) that cause the equation to equal zero is the process of solving polynomial equations. We refer to these values as roots or solutions. This is a detailed tutorial on how to solve polynomial equations:
For example, you would rewrite a polynomial like \(x^2 − 5x + 6\) as x2 − 5x + 6 = 0 if you were given it. The next step is to identify the values of 𝑥 for which this equality is valid; these are referred to as the equation's roots or solutions.
𝑥² − 5x + 6 can be factored into (x − 2) (x − 3), for instance, meaning that x = 2 and x = 3 are the solutions since such numbers make each component zero. Simple polynomials, particularly quadratics or ones with recurring patterns like perfect square trinomials or the difference of squares, are good candidates for factoring.
\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)
Any quadratic equation with the form 𝑎𝑥² + bx + c = 0 can be solved using this formula. After entering the values for 𝑎, 𝑏, and 𝑐, you can simplify. It is especially helpful when the polynomial has complicated or irrational roots or doesn't factor smoothly. For instance, the quadratic formula yields the solutions x = 1 and x = −3 for the equation 𝑥² + 2x − 3 = 0.
After that, you test these values to check if they add up to zero using synthetic division or substitution.
The graph for the polynomial f(x) = x³ − 4x² − 7x + 10 is shown below. The real roots of the equation are represented by the spots where the curve crosses the x-axis. This visual method aids in locating approximations of solutions and comprehending the behavior of the function.
The zeros of polynomial functions are the values of the variable that make the function zero. In other words, the values of x when f(x) = 0 are the zeros of a polynomial function f(x).
The values of the variable that make a polynomial equal to zero are called zeros, also known as roots or solutions. In other words, the values of x when f(x) = 0 are the zeros of a polynomial function f(x). The values of variables are important for evaluating polynomial functions. Let \(f(x) = x² − 5x + 6\) be the polynomial, after factorization, (x - 2) (x - 3) = 0, therefore, x = 2,3.
Determining these values is essential to comprehending and evaluating polynomial functions, particularly in the context of graphing or equation solving.
Let's look at a basic example to better grasp this idea. Let \(f(x) = x² − 5x + 6\) be the polynomial in question. We set it to zero to determine its zeros: \(x² − 5x + 6 = 0\). The expression can be factored to obtain (x − 2)(x − 3) = 0. This indicates that x = 2 and x = 3 are the polynomial's zeros because entering either number into the function yields zero.
In a graphic representation, a polynomial's zeros match the graph's x-intercepts. These are the locations on the x-axis where the curve meets or crosses. For example, the graph will intersect the x-axis three times in a polynomial with three real zeros. Only the real zeros will show up as intercepts on the graph if some zeros are complex (using imaginary values).
Three distinct polynomial functions are displayed in this graph to represent different kinds of zeros:
Mastering polynomials becomes easier with a clear understanding of their structure and properties. Here are some quick tips to simplify solving and manipulating polynomial expressions effectively.
Students should understand variables, coefficients, constants, exponents, and degrees.
Begin with linear (degree 1) and quadratic (degree 2) polynomials before higher degrees
This section identifies common mistakes that students make when working with polynomials and provides simple guidance on how to solve expressions correctly and without confusion.
Polynomials are vital tools in research, technology, and daily decision-making because they are used to model motion, forecast trends, and address real-world issues in disciplines including engineering, physics, economics, and medicine.
Determine if the following is a polynomial 3x² - 1x + 5
No
All variables must have non-negative, whole-number exponents to qualify as polynomials.
The expression 1x in this example is equal to 𝑥⁻¹, which has a negative exponent.
Hence, this makes it non-polynomial.
Find the Degree of the polynomial 4x³ + 2x² - x² + 7
3
Multiply (x + 2)(x + 3)
x2 + 5x + 6
Solve this by using the distributive method or (FOIL method):
x(x + 3) + 2(x + 3)
= x2 + 3x + 2x + 6
= x2 + 5x + 6
The final answer is x2 + 5x + 6.
Evaluate a Polynomial P(x) = x³ - 2x² + 3x - 1 when x = 2
P(2) = 5
Substitute the value of x in the equation.
P(2) = (2)³ - 2(2)2 + 3(2) - 1
= 8 – 8 + 6 – 1
= 5
Hence, the final answer will be P(2) = 5.
Solve x² - 5x + 6 = 0
x = 2 or x = 3
Factorize the equation.
x² - 5x + 6 = (x - 2)(x - 3)
Set each factor to 0; that is,
(x - 2) = 0
(x - 3) = 0.
So, x = 2 and x = 3 will be the answer.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.






