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Last updated on September 26, 2025
Polynomials are expressions consisting of variables, constants, and exponents. Based on their degrees, polynomials are classified into different types. In this article, we will learn about the three main types of polynomials.
Linear, quadratic, and cubic are the three main types of polynomials. We shall learn more about them in the following sections.
A polynomial with a degree of one is known as a linear polynomial. Here, the highest exponent of the expression is one. It is of the form p(x) = ax + b, where a ≠ 0. Examples of linear polynomials are:
p(x) = 3x + 2
q(x) = 𝜋y + 5
r(z) = -8z
A polynomial where the highest exponent is 2 is known as a quadratic polynomial. The quadratic polynomial will be in the form of p(x) = ax2 + bx + c, where a ≠ 0. Examples of quadratic polynomials are:
p(x) = 5x2 + 2x + 2
q(y) = y2 - 2
s(z) = 7z2 + z
In a cubic polynomial, the highest exponent of the variable is 3. Its general form is p(x) = ax3 + bx2 + cx + d, where a ≠ 0. Here are a few examples of cubic polynomials:
Polynomials are widely used in real-life situations. From calculating how much something costs to predicting how a ball moves, here are some of the examples of the real-life applications of linear, quadratic, and cubic polynomials.
When learning about polynomials, especially linear, quadratic, and cubic types, it is normal to make mistakes. That’s why it’s important to learn about a few common mistakes beforehand, so that we can avoid them in the future.
Solve the linear equation: 2x + 5 = 11
x = 3
To find the value of x, the first step is to subtract 5 on both sides of the equation.
2x + 5 - 5 = 11 - 5
Now, the equation becomes:
2x = 6
Divide both sides by 2 to isolate x.
2x/2 = 6/2
x = 3
Solve the quadratic equation: x2 - 5x + 6 = 0
x = 2 or x = 3
Let’s use the factorization method to solve the quadratic equation:
x2 - 5x + 6 = (x - 2)(x - 3)
Now set each factor to 0.
x - 2 = 0; x - 3 = 0
Therefore, x = 2, x = 3.
Solve the cubic equation: x3 - 6x2 + 11x - 6 = 0
x = 1, 2, 3
Factorizing the polynomial, we get:
x3 - 6x2 + 11x - 6 = (x - 1)(x - 2)(x - 3)
Setting each factor to 0,
x - 1 = 0
x - 2 = 0
x - 3 = 0
Therefore, x = 1, 2, and 3.
Solve the quadratic equation: x2 + 7x + 10 = 0
x = -2 or x = -5
Let’s use the factorization method again.
x2 + 7x + 10 = (x + 2)(x + 5)
Setting the equation to 0, we get:
x + 2 = 0
x = -2
x + 5 = 0
x = -5
Solve the linear equation: 3x - 9 = 0
x = 3
We should add 9 on both sides of the equation to isolate 3x.
3x - 9 + 9 = 0 + 9
3x = 9
Now, divide both sides by 3 to isolate x.
3x/3 = 9/3
x = 3