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Last updated on September 1, 2025

Quadratic Polynomial

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Expressions that consist of variables, constants, and exponents are polynomial expressions; they are combined using arithmetic operations such as addition, subtraction, and multiplication. The quadratic polynomials are polynomials where the highest degree of the variable is 2.

Quadratic Polynomial for US Students
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What is a Quadratic Polynomial?

A quadratic polynomial is a second-degree polynomial that has the highest exponent of 2. It is written in the form ax2 + bx + c, where a ≠ 0. Here, x is the variable, a and b are coefficients, and c is the constant. 

 

The values of x that satisfy the equation are the roots of the quadratic polynomial.

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What is the Formula for Quadratic Polynomial?

The standard form of the quadratic polynomial is ax2 + bx + c = 0. There are different methods to find the solution to a quadratic equation:

 

  • Factorizing 
     
  • Completing the square
     
  • Quadratic formula
     
  • Graph 

 

The quadratic formula is the simplest way to find the roots of a quadratic polynomial equation. To find the solution of a quadratic equation, we use the quadratic formula:

 

x = -b  ± √b2 - 4ac/2a

 

The expression under the square root b2-4ac is the discriminant of the root. The discriminant D is used to determine the nature of the root.

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What Are the Roots of Quadratic Polynomial?

The value of x in a quadratic equation is the root of a quadratic polynomial; it is also known as a solution or zero. 

 

To analyze the nature of the root, we use the discriminant, D = b2 - 4ac, the root can be both real and imaginary. Based on the discriminant, the roots can be:

 

  • If D > 0, then the roots are real 
     
  • If D < 0, then the roots are imaginary
     
  • If D = 0, then the root has one real and repeated root. 
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What is the Sum and Product of Roots of Quadratic Polynomial?

To understand the relationship between the roots and the coefficients, we use the roots of a quadratic equation. The sum and product of the roots of a quadratic equation in standard form are calculated using the coefficients. Let the roots be α and β, for a quadratic equation: ax2 + bx + c = 0, then:

 

  • Sum of the roots: α + β = -coefficient of x / coefficient of x2 = -b/a

 

  • Product of the roots: α∙β = constant / coefficient of x2 = c/a

 

If the sum and product of the roots are given, the quadratic equation can be obtained by:

x2 - (α + β)x + α∙β = 0 

 

For example, find the sum and product of the roots of x2 - 8x + 15 = 0

Here, a = 1, b = -8, and c = 15

Sum of the roots = -b/a 

= -(-8)/1 = 8

 

Product of the roots: c/a 

= 15/1 

= 15

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Graphical Representation of Quadratic Polynomial

The graph of the quadratic polynomial forms a parabola, which may open upwards or downwards depending on the value of a. The quadratic equation is in the form of ax2 + bx + c. The equation of the parabola is y = ax2 + bx + c. To plot the graph, the value of x is substituted into the equation to find the value of y, resulting in the points (x, y) on the curve. The points where the parabola intersects the x-axis represent the real roots of the equation, if they exist. If the value of the discriminant is negative, then the graph does not cross the x-axis, showing that the equation has no real roots.

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How to Find Quadratic Polynomial?

To form the quadratic polynomial, we use the values of the roots of the equation. The polynomial can be formed using the formula: x2 - (α + β)x + α.β = 0, where α and β are the roots of the quadratic equation.  

For example, if the roots of a quadratic polynomial are 5 and 3, find the quadratic polynomial 
The general form of a quadratic polynomial with roots is x2 - (α + β)x + α  β = 0 
Here, α = 5
β = 3 
That is x2 - (5 + 3)x + 5 × 3 = 0 
x2 - 8x + 15 = 0

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How to Factorize Quadratic Polynomials?

Factorizing the quadratic polynomial is a method used to find the roots of the quadratic equation. In this process, the polynomial is broken down into a product of factors, which is reverse multiplication. A few factorization methods are:

 

  • Common Factor Method
     
  • Sum of Difference Method
     
  • Factor by Grouping Method
     
  • Perfect Square Trinomials Method
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Common Factor Method

If all the terms in a polynomial share a common factor, we can factor it out. By using the distributive law in reverse, that is 
x(a + b) = xa + xb. 

 

Factoring out x, as it is the common factor: 
xa + xb = x(a + b). 

 

For example, factoring 4x2 + 2x = 0

Here, the common factor is 2x, factoring it out

4x2 + 2x = 2x(2x + 1)

So, it can be factorized as 2x(2x + 1)

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Sum of Difference Method

When the two factors of a polynomial are the same, but one is addition and the other is subtraction, we use the sum of difference method to factorize the polynomial. This can be represented as: (x - a)(x + a)
It can be expanded as: 
(x - a)(x + a) = x2 - ax + xb - a2
= x2 - a2 

Find the solution of (x + 8)(x - 8) using the sum of the difference method

Using the identity: (a + b)(a - b) = a2 - b2
Here, a = x and b = 8
So, (x + 8)(x - 8) = x2 - 82
= x2 - 64

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Factor by Grouping Method

In the grouping method, the terms of a polynomial are arranged into pairs or groups such that each group has a common factor. To factor the polynomial by the grouping method, follow these steps:
Factor out the common factor from the quadratic polynomial
Each group of the expression is factorized
Now factoring the common binomial

For example, factoring x2 + 5x + 2x + 10 by grouping method
Grouping the terms: 
x2 + 5x + 2x + 10 = (x2 + 5x) + (2x + 10)
In x2 + 5x, the common factor is x
So, x(x + 5)
The common factor in (2x + 10) is 2
So, 2(x + 5)

x(x + 5) + 2(x + 5) = (x + 5)(x + 2)

Factoring out the common binomial, (x + 5)(x + 2)

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Perfect Square Trinomials Method

The equations with the pattern of a perfect square are solved using the perfect square trinomial method 
The perfect square trinomial formulas are:
(a + b)2 = a2 + 2ab + b2
(a - b)2 = a2 - 2ab + b2

For example, factor the quadratic equation x2 + 16x +64
Here, a2 = x2, a = x
2ab = 16x, ab = 8x
b2 = 64, so b = 8


x2 + 16x + 64 = x2 + (2 × x × 8) + 82
= (x + 8)2

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Real-world Applications of Quadratic Polynomials

In real life, we use the quadratic polynomial in different fields like sports, physics, finance, engineering, etc. Here are some of the applications of quadratic polynomials.

 

  • In sports like basketball, soccer, disc throw, javelin throw, and shot put, the motion of the ball or the object will be in a parabolic path. We use the quadratic equation to calculate the maximum height, modeling projectile motion, and to determine the distance traveled. 

 

  • For the natural movements of characters and objects in video games and animation, the quadratic polynomials are used.

 

  • In business, to model and solve problems related to profit maximization, optimal production level, and cost minimization.
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Common Mistakes and How to Avoid Them in Quadratic Polynomials

When working with quadratic polynomials, students often repeat the same mistakes. Here are some common mistakes and the ways to avoid them. By learning these, students can master quadratic polynomials. 

Mistake 1

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Confusing linear and quadratic polynomials

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Students frequently confuse linear expressions like 3x + 2 with a quadratic polynomial, as it has the variable x. But it is wrong, as the highest power of a quadratic polynomial is 2 and the highest power of a linear polynomial is 1.

 

For example,3x + 2 is a linear polynomial, and 3x2 + 5x - 2 is a quadratic polynomial. 

Mistake 2

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Think that a can be zero

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The student thinks that the value of a in a quadratic polynomial can be 0, which is wrong. Because if a = 0, then x2 becomes 0x2, which makes it a linear polynomial, not a quadratic polynomial. Always remember that for any quadratic polynomial, the value of a cannot be 0.

Mistake 3

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Using the incorrect quadratic formula

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When finding the root of a quadratic polynomial, students mostly get confused with the sign, that is, x = (-b ± √b2 + 4ac) 2a instead of x = (-b ± √b2 - 4ac)2a, which results in wrong roots. So, memorize the quadratic formula to avoid the confusion.

Mistake 4

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Mixing up the formulas for the sum and product of roots

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Mixing with sum and product formulas is common among students, like sum = c/a instead of -b/a and product = -b/a instead of  c/a. This will result in errors, so always memorize the formulas: sum of roots =-b/a and product of roots = c/a.

Mistake 5

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Factoring the quadratic formula with no common factor

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Without checking the common factor or GCF, students sometimes try to factorize the quadratic formula, which can lead to errors or confusion. To avoid this error, always check whether the terms have a common factor or not; if there is no common factor, use the formula to find the roots. 

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Solved Examples of Quadratic Polynomials

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Problem 1

Write the standard form of a quadratic polynomial whose coefficients are a = 1, b = -6, and c = 8

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x2 - 6x + 8

Explanation

The standard form of a quadratic polynomial is:

ax2 + bx + c

 

Here, a = 1, b = -6, c = 8 

 

In standard form, we substitute the values of a, b, and c 

1x2 + -6x + 8 = x2 - 6x + 8

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Problem 2

Find the root of x^2 - 5x + 6 = 0

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x = 2 and x = 3

Explanation

To find the root, we use the quadratic formula,
x = (-b ± √b2 - 4ac)2a
Here, a = 1
b = -5
c = 6
x = (-(-5) ± √(-5)2 - 4 × 1 × 6)2 × 1
= (5 ± √25 - 24)2
= (5 ± √1)2
= (5 ± 1)2
So, x = (5 + 1)2= 62 = 3
x = (5 - 1)2= 24 = 2

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Problem 3

Find the sum and product of the roots for the quadratic polynomial 2x^2 - 4x + 1

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For the quadratic polynomial 2x2 - 4x + 1, the sum and product is 2 and 1/2

Explanation

The sum and product of the quadratic equation are calculated using the formula: 
Sum = -b/a
Product = c/a
Here, a = 2
b = -4
c = 1
Sum = -b/a 
= -(-4/2) 
= 4/2 = 2
Product = c/a
= ½ 

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Problem 4

Find the quadratic polynomial whose sum and product of roots are 7 and 10, respectively.

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x2 -7x + 10

Explanation

The quadratic equation, if the roots are α and β, is:

x2 - (α + β)x + (αβ)

Here, α + β = 7 and αβ = 10

Substituting the values in the standard form: x2 - (α + β)x + (αβ)

= x2 -7x + 10

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Problem 5

Factorize: x^2 + 7x + 10

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(x + 2)(x + 5)

Explanation

To factorize the equation, find two numbers whose product is 10 and whose sum is 7

 

Here, the numbers are 2 and 5, as their product is 10 and sum is 7.

So, x2 + 7x + 10 = (x + 2)(x + 5)

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FAQs on Quadratic Polynomials

1.What is a quadratic polynomial?

The polynomials with the highest degree of 2 are the quadratic polynomials.

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2.What is the degree of a quadratic polynomial?

For any quadratic polynomial, the degree is 2.

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3.What is the standard form of a quadratic polynomial?

The standard form of a quadratic polynomial is: ax2 + bx + c, where a ≠ 0.

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4.What is the quadratic formula?

One of the methods used to find the root of a quadratic equation is the quadratic formula. for any quadratic equation ax2 + bx + c = 0, the quadratic formula is x = (-b ± √b2 - 4ac)/2a

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5.How to find the sum of the roots of a quadratic polynomial?

For a quadratic equation ax2 + bx + c = 0, if α and β are its roots, then the sum of the roots is:

α + β = -b/a

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6.How does learning Algebra help students in United States make better decisions in daily life?

Algebra teaches kids in United States to analyze information and predict outcomes, helping them in decisions like saving money, planning schedules, or solving problems.

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7.How do technology and digital tools in United States support learning Algebra and Quadratic Polynomial?

At BrightChamps in United States, we encourage students to use apps and interactive software to demonstrate Algebra’s Quadratic Polynomial, allowing students to experiment with problems and see instant feedback for better understanding.

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8.How can cultural or local activities in United States support learning Algebra topics such as Quadratic Polynomial?

Traditional games, sports, or market activities popular in United States can be used to demonstrate Algebra concepts like Quadratic Polynomial, linking learning with familiar experiences.

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9.Does learning Algebra support future career opportunities for students in United States?

Yes, understanding Algebra helps students in United States develop critical thinking and problem-solving skills, which are essential in careers like engineering, finance, data science, and more.

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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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