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Last updated on September 27, 2025
Algebraic expressions are classified into types based on the number of terms present, such as monomial, binomial, etc. A binomial is an algebraic expression with two unlike terms connected by addition or subtraction. In this article, we will be learning about binomials.
A binomial is an algebraic expression that consists of two unlike terms, including constants and variables, connected by arithmetic operators such as the plus (+) and minus (-). For example, 2x + 3y is a binomial. Algebraic expressions are classified as monomial (one term), binomial (two terms), and trinomial (three terms) based on the number of terms, as shown in the image below:
A binomial coefficient is a numerical factor that appears in front of each term when expanding an expression like (x + y)2. The binomial expression (x + y)n can be expanded as
(x + y)n = nC0 xn y0 + nC1 xn - 1 y1 + nC2 xn - 2 y2 + … + nCn - 1 x1 yn - 1 + nCn x⁰ yn.
After expanding (x + y)5, we get the expanded form like:
(x + y)5 = 5C0 x5 y0 + 5C1 x4 y1 + 5C2 x3 y2 + 5C3 x2 y3 + 5C4 x1 y4 + 5C5 x0 y5
= x5 + 5x4y + 10x3y2 + 10x2y3 + 5xy4 + y5.
In this expansion, the numbers 1, 5, 10, 10, 5, 1 are the binomial coefficients. When we arrange these binomial coefficients in a triangle, we will get Pascal’s Triangle.
In Pascal’s Triangle, each row represents the binomial coefficients for the expression of (x + y)n, where n corresponds to the row number starting from 0.
Row 0 (n = 0) = (x + y)0 = Coefficients: 1
Row 1 (n = 1) = (x + y)1 = Coefficients: 1, 1
Row 2 (n = 2) = (x + y)2 = Coefficients: 1, 2, 1
Row 3 (n = 3) = (x + y)3 = Coefficients: 1, 3, 3, 1
Factoring binomials means breaking them into smaller pieces that can be multiplied to get the original expression. There are four methods for factorizing binomials:
Factoring Binomials Using Greatest Common Factor
Take out the common number or common terms from both terms.
For example, 2x2 + 6x, both terms share a common factor 2x, which can be factored out.
So the binomial will become 2x(x + 3).
Factoring Binomials Using the Difference of Squares
If two terms don’t share a common factor, they can still be factorized if they follow a special pattern.
If a binomial is in the form of a2 - b2, we can use the identity: a2 - b2 = (a + b)(a - b).
For example, a2 - 9, since 9 is a perfect square (32), it can be rewritten as, a2 - 9 = (a + 3)(a - 3).
Factoring Binomials Using the Sum of Cubes
If we are adding cubes like x3 + 27, here the 27 can be written as 33.
We can apply the identity: a3 + b3 = (a + b)(a2 - ab + b2).
Therefore, x3 + 27 can be written as (x + 3)(x2 - 3x + 9).
Factoring Binomials Using the Difference of Cubes
When dealing with the difference of two cubes, such as y3 - 64, we can use the identity, a3 - b3 = (a - b)(a2 + ab + b2).
Since 64 is 43, the expression can be factored as: y3 - 64 = (y - 4)(y2 + 4y + 16).
A binomial is an expression made up of exactly two terms joined by a plus or a minus sign. (x +3) and (x - 7) are examples of binomials. Squaring a binomial means multiplying the binomial by itself. We can use three identities or formulas for squaring a binomial.
Example: Find the square of (3y + 2)
Here, both terms are positive.
So, we can use, (a + b)2 = a2 + 2ab + b2
(3y + 2)2 = (3y)2 + 2(3y)(2) + 22
= 3y2 + 12y + 4
Binomials and binomial coefficients are widely used in real life, especially in areas like mathematics, science, and finance. They help to solve problems involving probabilities, patterns, and algebraic expressions. Here are some of the real-life examples where binomials are used.
While working with binomials, students make mistakes that can be avoided with a few helpful tips. These errors happen when applying formulas, combining like terms, or performing multiplication steps incorrectly. Here are some of those mistakes and how to prevent them.
What is the square of (x + 3)²?
x2 + 6x + 9
Use the identity:
(a + b)2 = a2 + 2ab + b2
Here, a = x, b = 3
(x + 3)2 = x2 + 2(x)(3) + 32
= x2 + 6x + 9
Factor the binomial: 4x² + 8x
4x(x + 2)
Find the GCF of both terms.
GCF of 4x2 + 8x is 4x
Divide each term with the GCF
4x2 ÷ 4x = x
8x ÷ 4x = 2
So, 4x2 + 8x = 4x(x + 2)
Factor x² - 16
(x + 4)(x - 4)
Use the identity, a2 - b2 = (a + b)(a - b)
We can write x2 - 16 as
x2 - 42 = (x + 4)(x - 4)
Factor x³ + 27
(x + 3)(x2 - 3x + 9)
This is a sum of cubes, x3 + 33.
Use the identity: a3 + b3 = (a + b)(a2 - ab + b2)
So, x3 + 33 = (x + 3)(x2 - 3x + 9)
Factor: y³ - 8
(y - 2)(y2 + 2y + 4)
y3 - 8 can be written as y3 - 23
Use the identity, x3 - y3 = (x - y)(x2 + xy + y2)
y3 - 8 = (y - 2)(y2 + 2y + 4)
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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