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276 LearnersLast updated on October 17, 2025

A geometric sequence is calculated by multiplying the previous one by the same fixed number, known as the common ratio. This kind of sequence is used in areas like mathematics, science, finance, and computer simulations to model situations involving exponential increase.
A geometric sequence is a list of numbers, where each term is obtained by multiplying the previous term by a constant called the common ratio. If r > 1, the sequence grows; if 0 < r < 1, it decreases. Real-life examples include population growth or scientific experiments.

Both geometric and arithmetic sequences are number patterns.
Geometric Sequence
Definition: A sequence in which every term is set up by multiplying the previous term by a fixed non-zero number (common ratio).
Example: 2, 4, 8, 16, 32 (multiplied by 2 each time)
Formula: an = a1 × r(n-1)
Growth Type: Exponential (rapid increase or decrease)
Arithmetic Sequence
Definition: A sequence where each term is calculated by adding a common difference to the previous term; the subtraction corresponds to a negative common difference.
Example: 3, 6, 9, 12, 15 (add 3 each time)
Formula: an = a + (n−1) × d
Growth Type: Linear (constant increase or decrease)
A geometric sequence is a chain of numbers in which every term is obtained by multiplying the previous term by a fixed number, known as the common ratio.
1. nth Term of a Geometric Sequence
\(a_n = a_1 \times r^{\,n-1}\)
an= the nth term
‘
a = first term
r = common ratio
n = term number
2. Sum of the First n Terms (Finite Sum)
\(S_n = \frac{a_1 (1 - r^n)}{1 - r}, \quad \text{for } r \neq 1\)
3. Sum to Infinity (Infinite Geometric Series)
\(S_\infty = \frac{a_1}{1 - r}, \quad \text{for } |r| < 1\)

A geometric sequence is calculated by multiplying the previous one by a fixed number, known as the common ratio. The nth term formula is:
\(a_n = a_1 \times r^{\,n-1}\)
Where:
A recursive formula says that every term in a sequence is based on its preceding term(s). In a geometric sequence, every term is obtained by multiplying the previous term by a fixed number known as the common ratio. The recursive formula is:
\(a_n = r \times a_{n-1}, \quad \text{for } n \ge 2\)
Where:
Example: If a1 = 2 and r = 3, then the sequence is:
2, 6, 18, 54, …
Recursive formula:
The formula for the sum Sn of the first n terms of a finite geometric sequence is:
\(S_n = \frac{a(1 - r^n)}{1 - r}, \quad \text{for } r \neq 1\)
Where:
If the common ratio r = 1, the series becomes a constant sequence, and the sum is simply:
Sn= n × a
Derivation
To derive this formula, consider the geometric series:
\(S_n = a + a r + a r^2 + a r^3 + \dots + a r^{\,n-1} \)
Multiply both sides by the common ratio (r):
\(r S_n = a r + a r^2 + a r^3 + \dots + a r^n\)
Subtract the original series from this new equation:
\(r S_n - S_n = \bigl(a r + a r^2 + a r^3 + \dots + a r^n \bigr) - \bigl(a + a r + a r^2 + \dots + a r^{\,n-1} \bigr)\)
Simplifying the right-hand side:
\((r - 1) S_n = a r^n - a\)
Solving for Sn
\(S_n = \frac{a(1 - r^n)}{1 - r}, \quad \text{for } r \neq 1\)
Example: Consider a geometric series with the first term a = 4, the common ratio r = 3, and n = 6 terms.
Given:
First term a = 4
Common ratio r = 3
Number of terms n = 6
Using the formula:
\(S_6 = 4 \times \frac{1 - 3^6}{1 - 3}\)
First, calculate 36:
\(3^6 = 729\)
Now, we will substitute into the formula:
\(S_6 = 4 \times \frac{1 - 729}{1 - 3} = 4 \times \frac{-728}{-2}\)
\(S_6 = 4 \times 364 = 1456\)
The answer is 1456.
An infinite geometric series is a sum of terms, where each term is multiplied by the same common ratio (r) to get the next one.
The sum exists only if the absolute value of the ratio is less than 1 (|r| < 1).
Formula:
\(S_\infty = \frac{a}{1 - r}, \quad \text{for } |r| < 1\)
Where:
a = first term
r = common ratio
If |r| ≥ 1, the series doesn’t have a finite sum (it diverges).
Example:
Series: 2 + 1 + ½ + ¼ + ⅛ + …
a = 2
r = ½
\(S_\infty = \frac{2}{1 - ½} = \frac{2}{½} = 4\)
The sum of the series is 4.
Geometric sequences are number patterns where each term is obtained by multiplying the previous term by a constant ratio. With the right tips and tricks, you can quickly find terms, calculate sums, and solve problems efficiently without getting lost in lengthy calculations.
When learning geometric sequences, students often make small errors that can lead to wrong answers. Understanding these common mistakes, and knowing how to avoid them, can help you solve problems more confidently and accurately.
A geometric sequence is a pattern where each term is obtained by multiplying the previous term by a constant ratio. This concept is not just theoretical—it appears in many real-world scenarios:
Robotics: The lengths or angles of robotic arm segments can increase geometrically to reach higher points efficiently, with each segment following a fixed ratio for smooth motion.
Architecture: Architects often use geometric sequences when designing structures like spiral staircases or tiered platforms. The height and width of each step or level can follow a geometric pattern to ensure balance and aesthetics.
Art and Design: Artists use geometric sequences to create perspective and depth in drawings or designs. Objects may decrease in size geometrically as they appear further away, creating realistic visual effects.
Finance: Geometric sequences appear in compound interest calculations. Each term represents the total amount after successive periods, where the amount grows by a fixed ratio each time.
Engineering: The sizes of structural elements, like steps in a staircase or layers in a tower, can follow a geometric sequence to maintain balance, safety, and proper load distribution.
What is the 5th term of the sequence: 3, 6, 12, 24, ...?
The 5th term is 48.
First term (a₁): 3
Common ratio (r): \(6 ÷ 3 = 2\)
Now we will use the formula for the nth term of a geometric sequence.
\(a_n = a_1 \times r^{\,n-1}\)
For the 5th term:
\(a_5 = 3 \times 2^{5-1} = 3 \times 2^4 = 3 \times 16 = 48\)
Find the 8th term of the sequence: 2, 6, 18, 54, ...
The 8th term is 4374.
First term (a₁): 2
Common ratio (r): 6 ÷ 2 = 3. Using the nth term formula:
\(a_8 = 2 \times 3^{8-1} = 2 \times 3^7 = 2 \times 2187 = 4374\)
Determine the 6th term of the sequence: 2, 6, 18, 54, ...
The 6th term is 486.
First term (a₁): 2
Common ratio (r): \(6 ÷ 2 = 3 \)
Using the nth term formula:
\(a_6 = 2 \times 3^{6-1} = 2 \times 3^5 = 2 \times 243 = 486\)
What is the next term in the sequence: 48, 24, 12, 6, ...?
The next term is 3.
First term (a₁): 48
Common ratio (r):\( 24 ÷ 48 = 0.5\)
Using the nth term formula:
\(a_5 = 48 \times 0.55 - 1 = 48 \times 0.54 = 48 \times 0.0625 = 3\)
The first term of a geometric sequence is 𝑎 = 5 and the common ratio is 𝑟 = − 2 . Find the sum of the first 5 terms.
S5 = 55
\(S_n = a \frac{1 - r^n}{1 - r} \text{Substitute the values:}\)
\( \\ S_5 = 5 \frac{1 - (-2)^5}{1 - (-2)} = 55\)
\(5 \frac{1 - (-32)}{1 + 2} = 5 \frac{1 + 32}{3} = 5 \times \frac{33}{3} = 5 \times 11\)
\(= 55\)
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