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298 LearnersLast updated on October 23, 2025

Each element of a square matrix has a minor, which is the determinant of the submatrix formed by removing its row and column. Minors are used to calculate the determinant, cofactors, adjoint, and inverse of a matrix.
The minor of an element in a matrix is the determinant of the submatrix obtained after the removal of its row and column. For an element aij, its minor is denoted by Mij. Let’s consider a matrix B:
\(B = \begin{bmatrix} b_{11} & b_{12} & b_{13} \\[0.3em] b_{21} & b_{22} & b_{23} \\[0.3em] b_{31} & b_{32} & b_{33} \end{bmatrix}\)
B12 is in row 1, column 2, so we will remove row 1 and column 2 from the given matrix.
The minor of b12 is:
\(M_{12} = \begin{bmatrix} b_{21} & & b_{23} \\ b_{31} & & b_{33} \end{bmatrix}\)
Similarly, the minor of each element bij in matrix B can be calculated and arranged to form a cofactor matrix M.
\(M = \begin{bmatrix} M_{11} & M_{12} & M_{13} \\[0.3em] M_{21} & M_{22} & M_{23} \\[0.3em] M_{31} & M_{32} & M_{33} \end{bmatrix}\)
We should find the minor of an element inside a matrix. To do that, follow the steps given below:
Step 1: Identify the row and column the element belongs to and remove them from the given matrix.
Step 2: From the remaining elements, form the submatrix and compute its determinant.
Step 3: Find the determinant of the submatrix to get the minor. Using minor values, form a new matrix called matrix of a minor.
For example, consider a 3 × 3 matrix:
\(B = \begin{bmatrix} 1 & 2 & 3 \\[0.3em] 0 & 4 & 5 \\[0.3em] 7 & 6 & 8 \end{bmatrix}\)
To find the minor of element b11 remove the first row and first column of the original matrix.
Minor of b11 = M11 = \( \Bigg | \begin{matrix} 4 & 5\\ 6 & 8 \end{matrix} \Bigg|\)
= (4 × 8) – (5 × 6) = 32 – 30 = 2
The minor of element b23 can be found by removing the second row and third column.
Minor of b23 = M23 = \( \Bigg | \begin{matrix} 1 & 2\\ 7 & 6 \end{matrix} \Bigg|\)
= (1 × 6) – (2 × 7) = 6 – 14 = – 8
To find the minor of element b32 remove the third row and second column.
Minor of b32 = M32 = \( \Bigg | \begin{matrix} 1 & 3\\ 0 & 5 \end{matrix} \Bigg|\)
= (1 × 5) – (3 × 0) = 5 – 0 = 5
We can find the minor of each element in this manner. By finding minors of elements, we can form a new matrix that will be the minor of matrix B.
\(M = \begin{bmatrix} M_{11} & M_{12} & M_{13} \\[0.3em] M_{21} & M_{22} & M_{23} \\[0.3em] M_{31} & M_{32} & M_{33} \end{bmatrix} = \begin{bmatrix} 2 & -35 & -28 \\[0.3em] 18 & 9 & -9 \\[0.3em] 11 & 5 & 8 \end{bmatrix}\)
A matrix’s cofactor, determinant, adjoint, and inverse can be determined by finding the minor of a matrix. Let us see the applications of the minor of a matrix.
Cofactor Matrix: Cij is used to denote the cofactor of an element in a matrix. Cij is determined by multiplying the minor Mij and (–1)i + j.
Therefore, Cij = (–1)i + j Mij
\(\text {Cofactor Matrix} = \begin{bmatrix} C_{11} & C_{12} & C_{13} \\[0.3em] C_{21} & C_{22} & C_{23} \\[0.3em] C_{31} & C_{32} & C_{33} \end{bmatrix}\)
We get cofactor matrix when we replace each element with its cofactor.
Determinant of a matrix: The determinant of a matrix is a single value that summarizes properties of a matrix. It is calculated using cofactor expansion. The determinant can be found by following these steps:
In a matrix D, the determinant is denoted by |d| or det D.
The determinant formula for the elements of the first row of matrix D will be:
|d| = d11C11 + d12C12 + d13C13
Here, Cij = (–1)i+j Mij. So, the determinant of matrix D is:
\(|D| = {{d_{11}(-1)^{1+1} \space \bigg| {\begin{matrix} d_{22} & & d_{23} \\ d_{32} & & b_{33} \end{matrix} } \bigg |} \space + \space {d_{12}(-1)^{1+2}\space \bigg| {\begin{matrix} d_{21} & & d_{23} \\ d_{31} & & b_{33} \end{matrix} } \bigg |} \space + \space {d_{13}(-1)^{1+3} \space \bigg| {\begin{matrix} d_{21} & & d_{21} \\ d_{31} & & b_{32} \end{matrix} } \bigg |}}\)
Adjoint of a matrix: To find the adjoint of a 3 × 3 matrix:
Let us consider matrix B:
\(B = \begin{bmatrix} b_{11} & b_{12} & b_{13} \\[0.3em] b_{21} & b_{22} & b_{23} \\[0.3em] b_{31} & b_{32} & b_{33} \end{bmatrix}\)
\(\text {Cofactor (B)} = \begin{bmatrix} C_{11} & C_{12} & C_{13} \\[0.3em] C_{21} & C_{22} & C_{23} \\[0.3em] C_{31} & C_{32} & C_{33} \end{bmatrix}\)
The adjoint of matrix B is equal to the transpose of cofactor matrix
i.e., adj(B) = transpose of cofactor matrix of B
\(adj(B) = [\text {Cofactor (B)}]^T = \begin{bmatrix} C_{11} & C_{21} & C_{31} \\[0.3em] C_{12} & C_{22} & C_{32} \\[0.3em] C_{13} & C_{23} & C_{33} \end{bmatrix}\)
Inverse of a matrix: We should divide the adjoint matrix by the determinant to find the inverse of a matrix.
For a matrix D:
\(D = \begin{bmatrix} d_{11} & d_{12} & d_{13} \\[0.3em] d_{21} & d_{22} & d_{23} \\[0.3em] d_{31} & d_{32} & d_{33} \end{bmatrix}\)
The inverse is \(D⁻¹ = {{1 \over det (D)} \times adj(D)}\)
Determinant: |d| = d11C11 + d12C12 + d13C13
Where, Cij is the cofactor of element dij .
Adjoint:
\(adj(D) = \begin{bmatrix} C_{11} & C_{21} & C_{31} \\[0.3em] C_{12} & C_{22} & C_{32} \\[0.3em] C_{13} & C_{23} & C_{33} \end{bmatrix}\)
Using inverse formula, If \(\text {det D} \neq 0\) the inverse of D is:
\(D⁻¹ = {{1 \over det (D)} \times adj(D)}\)
Knowing how to find minors is essential because they lead to cofactors, determinants, and matrix inverses, which are key concepts in algebra and linear algebra. Here are some tips and tricks for students to master in minor of a matrix.
It is possible for students to make avoidable errors while solving for the minor of a matrix. Understanding these commonly occurring errors can help avoid incorrect results.
A minor is a building block for the calculation of determinants, cofactors, and matrix inverses. It can be applied to the following real-life applications:
Find the minor a11 = 4
M11 = 3
Given Matrix:
\(A = \begin{bmatrix} 4 & 5 \\ 2 & 3 \end{bmatrix}\)
Delete row 1 and column 1
Only a22 remains.
\(M_{11} = \begin{bmatrix} a_{22} \end{bmatrix} = 3\)
Find the minor of a12 = 2
M12 = – 6
Given matrix:
\(A = \begin{bmatrix} 1 & 2 & 3 \\[0.3em] 4 & 5 & 6 \\[0.3em] 7 & 8 & 9 \end{bmatrix}\)
Delete row 1 and column 2
\(M_{12} = \begin{bmatrix} 4 & 6 \\ 7 & 9 \end{bmatrix}\)
M12 = (4 × 9) – (6 × 7) = 36 – 42 = – 6
Find the minor of b22
M22 = – 10
Given matrix:
\(B = \begin{bmatrix} 2 & 1 & 4 \\[0.3em] 0 & 3 & 5 \\[0.3em] 6 & 2 & 7 \end{bmatrix}\)
Delete row 2, column 2:
\(M_{22} = \begin{bmatrix} 2 & 4 \\ 6 & 7 \end{bmatrix}\)
M22 = (2 × 7) – (4 × 6) = 14 – 24 = – 10
Find the minor of C13 = 2
M13 = – 20
Given matrix:
\(C = \begin{bmatrix} 3 & -1 & 2 \\[0.3em] 0 & 5 & 1 \\[0.3em] 4 & 6 & -2 \end{bmatrix}\)
Delete row 1 and column 3
\(M_{13} = \begin{bmatrix} 0 & 5 \\ 4 & 6 \end{bmatrix}\)
M13 = (0 × 6) – (5 × 4) = 0 – 20 = – 20
Find the minor of d21, = 4
M21 = – 65
Given matrix:
\(D_{21} = \begin{bmatrix} 1&0 & 2 & 3 \\ 4&5&6&1 \\ 7&8 & 9 & 0 \\ 2&3&4&5 \end{bmatrix}\)
Delete row 2 and column 1:
\(M_{21} = \begin{bmatrix} 0 & 2 & 3 \\ 8 & 9 & 0 \\ 3&4&5 \end{bmatrix}\)
M21 = {0 × (9 × 5 – 0 × 4)} – {2 × (8 × 5 – 0 × 3)} + {3 × (8 × 4 – 9 × 3)}
= 0 – {2 × (40)} + {3 × (32 – 27)}
= 0 – 80 + {3 × (5)}
= – 80 + 15
= – 65
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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