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Last updated on October 21, 2025

Factored Form

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When planning your sister’s birthday, if each of 40 friends gets 6 snacks, the total is 6 × 40 = 240. Writing a number or expression as a multiplication of its factors, like 6 and 40, is called the factored form.

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What is Factoring?

The process of dividing a number or algebraic expression to its relevant factors is known as factoring. When you multiply these factors, it should give back the original expression.

 

For example: 
\(x²  – 7x + 12\)

We have to find two numbers whose product is 12 and sum is -7.
We have the numbers: -3 and -4. So,
\(x2 – 7x + 12 = (x - 3) (x - 4)\)

Verify the factoring by multiplying the factors together. 
\((x - 3) (x - 4) = x^2 – 4x -3x + 12 = x^2 - 7x + 12\).

Since we get back the original expression, the factorization is correct.

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What are the Methods of Factored Form?

Factoring plays a major role in algebra and is done through a series of steps. Let’s go through each steps in detail:

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Factoring Out the Greatest Common Factor (GCF)

The largest expression in an algebraic expression is the greatest common factor(GCF), which includes both the variables and numerical coefficients; they can divide each term exactly without leaving a remainder.  
 
For example:
Factor: \(12x^2y – 8xy^2 + 16xy\)

 

Solution:

To simplify an algebraic expression, we first need to simplify its GCF.

GCF of all terms = 4xy

Let’s now factor it out:

\(4xy(3x – 2y + 4)\)

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Factoring by Grouping

Factoring by grouping works well for polynomials that have four terms. In this, the terms are grouped into two pairs, and the common factor is taken out from each group. 

 

 

For example:

Factor: \(x³ + 2x² + 3x + 6\)

 

Solution:

Group the terms:

\((x³ + 2x²) + (3x + 6)\)

 

Take out the common factor from each group of terms.

\(x³(x + 2) + 3(x + 2)\)

 

Now, we factor out further:

\((x + 2)(x² + 3) \)

 

Here, \(x^2 + 3\) cannot be factorized more.

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Factoring Trinomials (AC Method)

A trinomial is an algebraic expression made up of three terms. Let’s explore how to factor a quadratic expression using the AC method. 

 

 

For example: 

Factor: \(x² + 7x + 10\)

 

Solution:

Find two numbers whose product is 10 and sum is 7.

2 and 5

 

Rewrite the middle term using the factors:

\(x² + 2x + 5x + 10\)

 

We then group the terms into pairs

\((x² + 2x) + (5x + 10)\)

 

Factor out each group:

\(x(x + 2) + 5(x + 2)\)

 

Factor out further for the common binomial:

\((x + 2)(x + 5)\)

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Factoring Difference of Squares

This method can be used only in cases where both terms are perfect squares separated by a minus sign. 

 

Formula: \(a² - b² = (a + b)(a - b)\)

 

For example: 

Factor: \(x² - 49\)

 

Solution:

Rewrite it as a difference of squares:

\(x² - 7² = (x + 7)(x - 7)\)

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Factoring Perfect Square Trinomials

An expression with three terms is called a perfect square trinomial. A perfect square trinomial will match any one of the following forms:

 

\(a² + 2ab + b² = (a + b)²\)

\(a² - 2ab + b² = (a - b)²\)

 

 

Example:

Factor: \(x² + 8x + 16\)

 

Solution:

Identify the pattern:

\(x² + 2·4·x + 4² = (x + 4)²\)

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Factoring Sum and Difference of Cubes

These expressions follow the specific formulas which are given below: 

 

\(a³ + b³ = (a + b)(a² - ab + b²)\)

\(a³ - b³ = (a - b)(a² + ab + b²)\)

 

For example: 

Factor: \( x³ + 64\)

 

Solution:

Identify it as a sum of cubes:

\(x³ + 64 = x³ + 4³\) 

The formula we use: \(a³ + b³ = (a + b)(a² - ab + b²)\)

Applying the formula:

\(x³ + 4³ = (x + 4)(x² - 4x + 16)\)

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Factoring by Substitution

This method applies to factor higher-degree polynomials. Here, we substitute a repeated power with a variable.

 

 

For example: 

Factor: \(x⁴ + 2x² – 15\)

 

Solution:

Let \(y = x²\)

So the expression becomes:

\(y² + 2y - 15\)

 

Now, write the expression as a multiplication of its factors:

\((y + 5)(y - 3)\)

 

Here, we substitute x² back for y:

\((x² + 5)(x² - 3)\)

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Tips and Tricks for Factored Form

Factored form represents an expression as a product of its factors. This method can be a little tricky for some students. We will now go through some simple tricks to help you master the concept effectively.

 

  • Always look for numbers or expressions that can be multiplied to get the original number or term.
     
  • Start with the smallest prime numbers when factoring numbers to make the process easier.
     
  • For algebraic expressions, identify common factors in all terms before factoring.
     
  • Use grouping to factor expressions with more than two terms efficiently.
     
  • Check your work by multiplying the factors to ensure they give back the original number or expression.
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Common Mistakes and How to Avoid Them in Factored Form

Factoring is a fundamental concept in mathematics. However, students often make mistakes when factoring. Here are a few common mistakes and tips to avoid them:

Mistake 1

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Not factoring out the GCF first

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Students often perform factoring directly without checking for the greatest common factor.

For example: \(6x2 + 12x = (x + 2) (x + 3)\) (incorrect)

Correct: \(6x^2 + 12x = 6x(x + 2)\)

Start by verifying whether all the terms share a common factor.

Mistake 2

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Using incorrect formulas

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Students often mix up identities like the difference of squares and perfect square trinomials, which can result in using the wrong formulas. Learn the basic factoring formulas, which can help you in understanding the pattern of algebraic expressions.

Mistake 3

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Mixing up signs

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When factoring the expressions, students might mix up the signs.

For example: \(x^2 – 5x + 6 = (x – 3) (x – 2)\) is incorrect

Correct: \( x^2 – 5x + 6 = (x – 2) (x – 3)\)

To check for errors, apply the FOIL method (First, Outer, Inner, Last).

Mistake 4

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Inconsistent factoring

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Some students tend to stop factoring in the process, leaving it incomplete.

For example: \(x^2 – 4 = x^2 – 4\) (no factoring done)

Correct: \(x^2 – 4 = (x – 2) (x + 2)\) (factored using the difference of squares formula) 

It is important to check if the expression can be factored further.

Mistake 5

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Ignoring substitution in higher degree polynomials

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Factoring higher-degree polynomials without simplifying first can result in mistakes. Substitution can help rewrite the expression in a standard, more manageable form.

For example:

\(x⁴ - 5x² + 4 \)

Let y = x²

= \(y² - 5y + 4 = (y - 4)(y - 1)\)

= \((x² - 4)(x² - 1) = (x - 2)(x + 2)(x - 1)(x + 1)\).

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Real-Life Applications of Factored Form

The factored form is a useful method for representing algebraic expressions as a product of their factors. This concept is not confined to mathematics; it has widespread practical applications in real life.  Let’s now learn how it can be applied in real-world situations.

 

 

  • Algebraic simplification: Factored form is used to simplify complex algebraic expressions and solve equations efficiently.
     
  • Polynomial division: Factoring polynomials allows easier long division and helps identify roots of equations.
     
  • Optimization problems: In calculus and economics, factored forms help find maximum or minimum values by analyzing critical points.
     
  • Physics calculations: Factored expressions simplify formulas for motion, energy, and force, making computations faster.
     
  • Cryptography and coding: Factoring large numbers is fundamental in encryption algorithms and secure digital communication.
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Solved Examples of Factored Form

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Problem 1

Factor: 12x + 8

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Okay, lets begin

\(4(3x + 2)\)

Explanation

First identify the greatest common factor (GCF) of both terms:

12x and 8 → GCF = 4

Let’s now factor out the GCF:

\(12x ÷ 4 = 3x\)

\(8 ÷ 4 = 2\)

Therefore, the simplified expression is:

\(12x + 8 = 4(3x + 2)\)

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Problem 2

Factor: x² - 25

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Okay, lets begin

\((x + 5)(x - 5)\)

Explanation

Identify that the given expression represents a difference of squares.

x² is (x)² and 25 is (5)²

Using the formula:

\(a² − b² = (a + b)(a − b)\)

Now, apply the formula:

\(x² − 25 = (x + 5)(x − 5)\)

So, the final expression we get is:

\(x² - 25 = (x + 5)(x - 5)\).

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Problem 3

Factor: x³ + 3x² + x + 3

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Okay, lets begin

\((x + 3)(x² + 1)\)

Explanation

Let’s first group the terms:

\((x³ + 3x²) + (x + 3)\)

We now factor each group:

\(x²(x + 3) + 1(x + 3)\)

Factor further for the common binomial:

\((x + 3)(x² + 1)\)

Simplifying the expression: 

\(x³ + 3x² + x + 3 = (x + 3)(x² + 1)\)

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Problem 4

Factor: 3x² - 12x

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Okay, lets begin

\(3x(x - 4)\)

Explanation

Start by finding the greatest common factor(GCF): 

GCF of 3x² and \(12x = 3x\)

Now, we factor out the GCF:

\(3x² ÷ 3x = x\)

\(12x ÷ 3x = 4\)

So the simplified expression is:

\(3x² - 12x = 3x(x - 4)\).

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Problem 5

Factor: x³ - 27

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Okay, lets begin

\((x - 3)(x² + 3x + 9)\)

Explanation

Identify that the given expression is a difference of cubes:

\(x³ = (x)³, 27 = (3)³\)

Using the formula:

\(a³ - b³ = (a - b)(a² + ab + b²)\)

Substitute the values into the formula:

\(x³ - 27 = (x - 3)(x² + 3x + 9)\)

Factoring the expression:

\(x³ - 27 = (x - 3)(x² + 3x + 9)\).

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FAQs on Factored Form

1.What do you mean by the term factored form?

The factored form is a simplified method of writing a number or algebraic expression as a multiplication of its factors. 

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2.How can we check if the factoring is correct?

To check, we multiply the factors. If the original expression is obtained after multiplying the factors, then the factoring is accurate.

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3.What is the greatest common factor (GCF)?

The GCF is the greatest factor that evenly divides every term in an expression.

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4.Why do we need to factor expressions?

Factoring enables us to simplify expressions and solve equations quickly.

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5.Is it possible to factor every expression?

No, some expressions cannot be factored and are called irreducible polynomials.

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6.What is factored form, and why is it important for my child to learn?

Factored form shows a number or algebraic expression as a product of its factors. It helps children understand how numbers and equations are built, making it easier to simplify and solve problems.

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7.How can I explain factored form to my child in simple terms?

You can use real-life examples, like splitting 12 cupcakes equally among 3 friends (12 = 3 × 4), to show how a number can be expressed as a multiplication of its factors.

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8.My child finds factoring hard. How can I help?

Encourage practice with small numbers and use tools like factor trees or multiplication tables. Gradually move to algebraic expressions once they are confident with numbers.

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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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