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Last updated on October 17, 2025
An arithmetic sequence or arithmetic progression is a set of numbers where the common difference between any two consecutive terms is constant. For example, an AP series like 1, 6, 11, 16,... has a common difference of five. There are formulas to help us determine the nth term and the sum of the first n terms in an arithmetic sequence. In this article, we will discuss arithmetic sequences in detail.
An arithmetic sequence is a list of numbers where the difference between any two successive terms is the same. This constant difference is called common difference.
For example, in the arithmetic sequence given below, every term is obtained by adding 4 to its previous term.
4, 8, 16, 20, . . .
Here, the common difference, denoted by (d), is 4.
To continue an arithmetic sequence, follow the given steps.
Step 1: Look at two consecutive terms. Pick any pair neighboring each other.
Step 2: Find the common difference (d).
Step 3: Check whether the sequence is rising \((d > 0)\), steady \((d = 0)\) or falling \((d < 0)\).
Step 4: Find the next term by adding the common difference to the last term.
Step 5: Repeat the addition to continue the sequence.
The formula for an arithmetic sequence is as follows:
\(a_n = a_1 + (n - 1) \times d \)
Here,
To understand the formula better, let’s take an example:
2, 8, 14, 20, 26, ....
In the above sequence, d is 6.
The value at a specific position in an arithmetic sequence is represented by the nth term. The following formula can be used to find it:
\( a_n = a_1 + (n - 1) × d \)
Where,
For example, a sequence like 5, 9, 13, 17,..... each number rises by 4. Hence, the first term a1 is 5, and the common difference (d) is 4. Let’s substitute the equation to determine the seventh term, a7:
\(a_7 = 5 + (7 - 1) × 4 \)
\( = 5 + (6 × 4) \)
\( = 5 + 24\)
\(= 29 \)
An arithmetic sequence's recursive formula is written as:
\(a_n = a_{n-1} + d\)
Where,
The initial term (a1) must be utilized to apply the recursive formula. In the sequence 2, 5, 8, 11, and so on, for instance, the first term is 2, and the common difference is 3.
The recursive formula then is \(a_1 = 2 \) and \(a_n = a_{n-1} + 3\) for n > 1. It means that to calculate a new term, we have to add 3 to the previous term.
The sum of an arithmetic sequence is resulted by adding all the terms of the sequence. The formula to calculate the sum of an arithmetic sequence is given below:
\(S_n = \frac{n}{2} \times (a + l) \)
Where,
Alternatively, we can also use the below-mentioned formula if we know the first term 𝑎, the common difference 𝑑, and the number of terms 𝑛:
\(S_n = \frac{n}{2} \times [2a + (n - 1)d] \)
Where,
Understanding arithmetic sequences is easier when you know the right techniques. Use these helpful tricks to find common differences, calculate terms, and confidently tackle sequence-based math problems with ease.
Arithmetic sequences show up in a lot of real-life scenarios. Knowing how they work will help us make accurate decisions in a structured and mathematical way.
It is not uncommon for students to make mistakes while working on an arithmetic sequence. This section talks about some of those mistakes and the solutions to avoid them:
Find the 12th term in the arithmetic sequence: 5, 9, 13, 17, …
49
In the first step, we identify the common difference and the first term
Step 2: Use the formula find out the nth term.
Step 3: Substitute the values into the formula:
\(a_{12} = 5 + (12 - 1) × 4\)
\( = 5 + (11 × 4)\)
\( = 5 + 44 = 49\)
Therefore, the final answer will be 49.
Add up the first 10 numbers in this list: 2, 6, 10, 14,...
200
Step 1: List the known parameters
Step 2: Use the formula \(S_n = \frac{n}{2} \times [2a + (n - 1)d] \), for the sum of n terms.
Step 3: Substitute the values:
\(S_{10} = \frac{10}{2} \times [2 \times 2 + (10 - 1) \times 4] \)
\( = 5 × (4 + 36)\)
\( = 5 × 40\)
\( = 200\)
Therefore, the final answer will be 200.
How many terms are there in this list: 7, 12, 17,..., 97?
19
First, list the numbers that are known.
Step 2: Use the nth term formula and solve for n:
\( l = a + (n - 1) d ⇒ 97\)
\( = 7 + (n - 1) × 5\)
Step 3: Solve the equation:
\(97 - 7 = 5 + (n - 1) \)
\( ⇒ 5 + (n - 1) = 90\)
\( ⇒ 5n = 90 + 5\)
\( ⇒ 5n = 95\)
⇒ n = 19
Therefore, the sequence has 19 terms.
The 20th number in a sequence is 95, and the difference between them is 4. Find the first term.
19
First, use the following method to find the nth term:
Step 2: Substitute the values:
\(95 = a + (20 - 1) × 495\)
\(95 = a + 76\)
Step 3: Solve for the value of a:
\(a = 95 -76 = 19\)
The first term will be 19.
There are 10 terms in an arithmetic sequence, with 10 being the first term and 100 being the last. Find the sum of these terms.
550
Step 1: If the first and last terms are known, use the sum formula:
\(S_n = \frac{n}{2} \times (a + l) \)
Step 2: Substitute the values:
\(S_{10} = \frac{10}{2} \times (10 + 100) \)
\(= 5 × 110 = 550\)
The final answer will be 550.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.