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112 LearnersLast updated on November 14, 2025

Systems of linear equations are solved using matrices and determinants. Matrices are used to organize data in rows or columns, while determinants help check the invertibility of square matrices and determine if their solutions exist.
Systems of linear equations are solved using matrices and determinants. Matrices are used to organize data in rows or columns, while determinants help check the invertibility of square matrices and determine if their solutions exist.
A matrix is a rectangular collection of numbers arranged in rows and columns. These numbers are referred to as elements. Meanwhile, a determinant is a single value calculated using a square matrix.
The determinant of a matrix provides key information about the matrix, including whether it has an inverse and how it transforms space.
Matrices and determinants are often associated with each other, but are significantly different from each other in the following ways:
| Matrices | Determinants |
|---|---|
| Structurally, matrices are a rectangular collection of elements in rows and columns. |
A determinant is a single value obtained from a square matrix. |
| They can be of any order (m × n). |
They are only applicable for square matrices of order (n × n). |
|
The elements in a matrix are arranged in [ ] or () brackets. |
The determinant of a matrix A is written as det(A) or |A|. |
|
They are used for storing data and solving systems. |
They are used for storing data and solving systems. |
|
An example of a matrix is |
For the same matrix, \(A = \begin{bmatrix} 4 & 7 \\ 2 & 6 \end{bmatrix}\) det(A) = (ad - bc) |
When working with matrices, we should know some important properties of matrices that are useful in matrix operations.
Understanding how to solve problems using matrices and determinants helps deal with systems of linear equations.
Matrices and determinants organize complex data and simplify it.
Depending on the matrix, we can choose the most suitable methods to solve for them.
Any linear equation Ax + By = C is written as AX = B in matrix form.
Where A is the coefficient matrix, X is the column matrix of variables, and B is the constant matrix.
Such an equation can be solved using the following methods:
Method 1: Inverse matrix method
If a matrix is non-singular and invertible, we use the inverse matrix method to find its solution. We can find the solution using X = A-1B.
Step 1 - Find the inverse of matrix A
Step 2 - Multiply the inverse by matrix B
The result containing the values is the solution matrix X.
This method is most suitable for small square matrices of order 2 × 2 or 3 × 3 because of computational complexity.
Method 2: Gauss Elimination Method
The Gauss elimination method simplifies a matrix one step at a time using elementary row operations.
Step 1 - Convert the augmented matrix [A|B] using row operations.
Step 2 - Get the zeroes below the diagonal to form an upper triangular matrix.
Step 3 - Use back-substitution to solve the resulting system.
This method is more preferable for larger systems.
Method 3: Gauss-Jordan Elimination
This method is an extension of Gaussian elimination and reduces the matrix to reduced row-echelon form (diagonal form). This removes the need for back substitution.
Step 1 - Perform row operations till the identity matrix is found on the left side of the augmented matrix.
Step 2 - The right side is the solution.
This method gives a direct solution and is useful in programming and numerical software.
Cramer’s Rule is a determinant-based method used to solve systems of n linear equations in n variables for square systems, provided that the coefficient matrix A is square and det(A) 0.
For a given system;
a1x + b1y = c1
a2x + b2y = c2
Its matrix form is written as AX = B
Where A is the coefficient matrix, X is the variable matrix, and B is the constant matrix.
Follow these steps to apply Cramer’s rule:
Step 1 - Find the determinant of the coefficient matrix det(A).
Step 2 - Replace the first column of A with B and find the new determinant, Dx.
Step 3 - Replace the second column of A with B and find Dy.
Step 4 - Apply the formulas, x=Dxdet(A), y =Dydet(A)
Where det(A) is the determinant of the coefficient matrix, Dx and Dy are the determinants formed by replacing columns x and y with constants.
Cramer’s rule is useful for smaller systems.
When we simplify a determinant, the matrix is reduced to a single number or scalar value. To find these values, we can compute the determinant in the following ways:
For a 2 × 2 matrix A
\(\begin{bmatrix} a & b \\ c & d \end{bmatrix} \)
The determinant is det(A) = ad - bc
To find a 3 × 3 determinant
Let matrix A,
\(A = \begin{bmatrix} a & b & c \\ d & e & f \\ g & h & i \end{bmatrix}\)
Using cofactor expansion along the first row, det(A) = a(ei-fh)-b(di-fg)+c(dh-eg)
We can also use Sarrus’ rule to calculate the determinant of a 3 × 3 matrix. It is considered a shortcut method and is limited only to 3 × 3 matrices.
Follow these two steps to use the Sarrus’ rule:
Step 1 - Repeat the first two columns next to the matrix.
Step 2 - Multiply diagonals from top-left to bottom-right and subtract the sum of diagonals from bottom-left to top-right.
There are two conditions of solvability to keep in mind while solving for matrices and determinants:
Students often make common errors while working with matrices and determinants due to confusion over operations, properties, and notation. Here are five frequent mistakes and ways to avoid them.
Matrices and determinants are important in solving complex systems across various fields. Some of their applications are listed below.
Multiply the matrices
\(\begin{bmatrix} 4 & 6 \\ 10 & 12 \end{bmatrix} \)
To multiply matrices A and B, we take the dot product of the rows of A with the columns of B
\(AB = \begin{bmatrix} 1 \times 2 + 2 \times 1 & 1 \times 0 + 2 \times 3 \\ 3 \times 2 + 4 \times 1 & 3 \times 0 + 4 \times 3 \end{bmatrix} = \begin{bmatrix} 4 & 6 \\ 10 & 12 \end{bmatrix} \)
Find
19
We use cofactor expansion along the first row.
Each element in the first row is multiplied by the determinant of the 2 × 2 minor left after removing that element's row and column. Also, we apply alternating signs (+, –, +) to these cofactors.
Calculating each cofactor and summing, we get:
2(−8) − 1(−20) + 3(5) = − 16 + 20 + 15 = 19
Solve 2x + 3y = 8, 4x + y = 10
x = 2.2, y = 1.2
We use Cramer’s Rule, which solves systems using determinants
Determinant of the coefficient matrix det(A)=-10
Replace one column with constants to compute new determinants Ax and Ay.
det(AX) = -22, det(Ay) = -12
x=det(Ax)/det(A)= 2.2, y=det(Ay)/det(A)=1.2
Find the inverse of
\(\begin{bmatrix} -0.5 & 1.5 \\ 1 & -2 \end{bmatrix} \)
To find the inverse, compute the determinant, 4 × 1 - 2 × 3 = -2
Swap the diagonal elements and change the signs of all other elements, and multiply the result by 1det(A)
\(\text{Inverse}(A) = \frac{1}{-2} \cdot \begin{bmatrix} 1 & -3 \\ -2 & 4 \end{bmatrix} = \begin{bmatrix} -0.5 & 1.5 \\ 1 & -2 \end{bmatrix} \)
Determine if the given matrix is invertible.
No, this matrix is not invertible.
To determine whether a matrix is invertible, we calculate its determinant.
det = 1 × 4 - 2 × 2 = 0
Since the determinant is zero, the matrix is singular and has no inverse.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.






