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Last updated on September 13, 2025
Simultaneous linear equations involving two variables help solve practical problems. They relate quantities like time, speed, distance, or cost, aiding in their analysis. We use simultaneous linear equations every day while making decisions.
A linear equation in algebra is an equation having the highest degree of 1. It represents straight-line relationships and does not include powers, roots, or products of variables. For example, x + y = 10 is a linear equation. In its standard form, it is written as ax + by = c.
Simultaneous linear equations are a set of two or more linear equations that have the same set of variables, like x and y. They are used to find the values of these variables that satisfy all equations simultaneously.
The general form of a system with two variables is,
a1x + b1y = c1
a2x + b2y = c2
Where x and y are variables and a, b, and c are constants.
There are three methods of solving simultaneous linear equations:
Substitution method
The substitution method is most suitable for simple equations or equations that can easily be rearranged. Any one of the equations is used to solve for a variable. That value is substituted into the other equation to find the value of the other variable.
For example, let's take two equations, (i) and (ii)
x + y = 10 (i)
x - y = 4 (ii)
We can find the value of x in terms of y using equation (i)
x + y = 10
x = 10 - y
Now, we can substitute this value of x in equation (ii) to find y
x - y = 4
(10 - y) - y = 4
10 - 2y = 4
2y = 6
y = 3
So, x = 10 - y = 10 - 3 = 7
Answer: x = 7, y = 3
Elimination method
This method requires addition or subtraction operations to cancel out one variable and solve for the other. It is useful for equations in standard form, i.e., ax + by = c, and quicker than the substitution method for equations that are not easily rearranged.
For example, for a set of two equations,
2x + 3y = 12 (i)
2x - y = 4 (ii)
We subtract (ii) from (i)
(2x + 3y) - (2x - y) = 12 - 4
2x - 2x + 3y + y = 8
Here, x is eliminated, so we get the value of y
4y = 8
y = 2
Now, we can use this value of y to find x using any equation
Substitute y = 2 in equations 2x - y = 4
2x - 2 = 4
2x = 6
x = 3
Answer: x = 3, y = 2
Graphical method
The graphical method helps visualize the position of the point of intersection between the two lines. The points where the two lines intersect on a graph are the solutions of the equations. If the lines intersect at one point, the system has one unique solution and is consistent and independent. If the lines are parallel, the system has no solution and is inconsistent. If the two lines completely overlap, then the system has infinitely many solutions, and is dependent.
For example,
x + y = 6 (i)
x - y = 2 (ii)
Convert both equations to the form y = mx + c
y = 6 - x
y = x - 2
Make a table of values of both variables x and y, then plot them on the graph. For these values of x, we find the value of y by substituting them in the equations.
Both the lines intersect at (4,2), so, x = 4 and y = 2.
Tip 1: Before choosing a method to solve the equation, always simplify both equations.
Tip 2: Substitution is useful when one of the variables is easily isolated.
Tip 3: Elimination is better when the coefficients are easily matched
Tip 4: For the standard form of equations, use the cross multiplication method.
Tip 5: Labelling each step helps avoid confusion during elimination and substitution.
Simultaneous linear equations are practical tools used in many real-life situations to analyze and solve multivariable problems efficiently.
Understanding some common errors that occur when solving simultaneous linear equations is crucial for accuracy in problem-solving. Below is a list of mistakes and how to avoid them for the students’ reference.
Solve x + y = 10, x - y = 4
x = 7, y = 3
Add both equations
(x + y) + (x - y) = 10 + 4
2x = 12
x = 7
Substitute x = 7 into the first equation
7 + y = 10 so y = 3
Solve y = 2x + 1, y = -x + 4
x = 1, y = 3
Set both equations equal to each other
2x + 1 = -x + 4
3x = 3
x = 1
Now, substitute x = 1 into any equation
y = 2(1) + 1 = 3
Solve using cross multiplication 3x + 4y = 10 2x - y = 3
x = 2, y = 1
The equations are in standard form, so;
a1 = 3, b1 = 4, c1 = 10, a2 = 2, b2 = -1, c2 = 3
Using the cross multiplication formula
xb1c2-b2c1=yc1a2-c2a1=1a1b2-a2b1
We get,
x(4)(-3)-(-1)(-10)=y(-10)(2)-(-3)(3)=1(3)(-1)-(2)(4)
x-12-10=y-20+9=1-3-8
x-22=y-11=1-11
Now we can find the value of x and y by equating them.
x-22=1-11x = 2
y-11=1-11y=1
What is the nature of the given system? 2x + 2y = 4 6x + 6y = 12
Infinitely many solutions, so the system is consistent and dependent
The second equation is a scalar multiple of the first
2(x + 2y) = 2 4 (i)
2x + 4y = 8 (ii)
Simplify both the equations,
2x + 2y2=42x + y = 2
6x + 6y6=126x + y=2
Both equations represent the same line. This means that the system has infinitely many solutions and is consistent and dependent.
Solve using cross multiplication 3x + 2y = 12 4x - y = 9
x = 30-11, y = -2111
Write the equations in standard form
3x + 2y = 12
a1 = 3, b1 = 2, c1 = 12
4x - y = 9
a2 = 4, b2 = -1, c2 = 9
Now, we use the cross multiplication formulaxb1c2-b2c1=yc1a2-c2a1=1a1b2-a2b1
Substituting the coefficient values in the formula gives us
x30=y21=1-11
Now, we solve for x and y
From x30=1-11
x = 30-11
From y21=1-11
y = 21-11
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.