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Last updated on September 22, 2025
Simultaneous equations involve solving two or more algebraic equations with common variables at the same time. In the equations x + y = 2 and x - y = 7, x and y are unknown variables that can be solved together. In this article, we will learn more about simultaneous equations and the ways to solve them.
Simultaneous equations are two or more mathematical equations that have the same unknown variables, such as x, y, etc. These equations are linked, and we determine the values of variables that satisfy all equations simultaneously. The simultaneous equations have a common solution. Given below are some examples of simultaneous equations.
(i) 2x - 4y = 4
5x + 8y = 3
(ii) 2a - 3b + c
= 9 a + b + c
= 2 a - b - c
= 9
While solving simultaneous equations, we have to choose the right method depending on the type of equations we have. The two common types of equations involved in simultaneous systems are:
Linear Equations: Variables like x and y that do not have powers greater than one are called linear variables. Equations with such variables are linear equations. When we have two linear equations together, it is called a system of linear simultaneous equations. Examples of linear equations include x + y = 10, x - y = 2. We can solve these equations using the elimination or substitution method.
Quadratic Equations: The equation in which the power of the variable is raised to two or squared is known as a quadratic equation. x2 + x + 2 is an example of a quadratic equation. When we have one quadratic equation and one linear equation, it is called a quadratic simultaneous equation.
Finding the exact values of the variables that make both equations true at the same time is simultaneous equations. There are three main methods for solving simultaneous equations, they are:
In the substitution method, we choose one equation and make one variable the subject; we will find out the value of the other variable, like x = something. Put that x into another equation to find the value of the second variable, and then find the value of the first variable.
Example: Solve x + y = 4 and 2x - 3y = 9
Solution: We can derive the value of x from the first equation.
x + y = 4
x = 4 - y
Put the value of x in the second equation,
2x - 3y = 9
2(4 -y) - 3y = 9
8 - 2y - 3y = 9
8 - 5y = 9
-5y = 9 - 8
-5y = 1
y = -⅕
Now put y = -⅕ in the first equation,
x + y = 4
x - ⅕ = 4
x = 4 + ⅕
x = 21/5
Therefore, the value of x = 21/5, y = -⅕.
In the elimination method, we make the coefficients the same and then add or subtract the equations to cancel one variable. Then, solve for one variable and substitute to get the value for the other variable.
Example: Solve 2x - 5y = 3 and 3x - 2y = 5
Solution: We can make the coefficient of y the same.
Multiply 2 by the first equation
4x - 10y = 6
Multiply 5 by the second equation
15x - 10y = 25
Now subtract both
(15x - 10y) - (4x - 10y) = 25 - 6
11x = 19
x = 19/11
Now, substitute the value of x into any of the original equations.
2x - 5y = 3
2 (19/11) - 5y = 3
38/11 - 5y = 3
-5y = 3 - 38/11
-5y = 33 - 38 /11
-5y = -5/11 → y = (-5/11)/(-5) → y = 1/11
The values are, x = 19/11, y = 1/11
In the graphical method, we draw both equations as lines on a graph, and the point of intersection is the solution. There are three possible outcomes in a graphical method: they are
Example: Solve x + y = 10, x - y = 4
Solution: For x + y = 10 For x + y = 10:
If x = 0, y = 10
If x = 10, y = 0
Points are: (0, 10) and (10, 0)
For x - y = 4
If x = 0, y = -4
If x = 4, y = 0
Points are: (0, -4) and (4,0)
When we draw both the lines on the graph, they meet at (7, 3)
The solution is x = 7, y = 3.
Simultaneous equations are not only used in math problems and equations, but also it is used in many real-life applications. Here are a few real-life applications.
Students often make mistakes while solving simultaneous equations. Here are some common mistakes that students make, along with the tips to avoid those mistakes.
Solve x + y = 10 and x - y = 4
x = 7, y = 3.
We can use the elimination method to find the solution to the given equations. While adding both equations, both the y terms will get eliminated.
Adding x + y = 10 and x - y = 4
(x + y) + (x - y) = 10 + 4
x + x = 14
2x = 14
x = 14/2
x = 7
Apply the value of x in the first equation,
x + y = 10
7 + y = 10
y = 10 - 7
y = 3
The value of x = 7 and y = 3
Solve x = 2y and x + y = 9.
x = 6, y = 3
We can use the substitution method to solve these equations. We can use the value of x = 2y in the second equation.
x + y = 9
2y + y = 9
3y = 9
y = 9/3
y = 3
Substitute the value of y in the first equation,
x = 2y
x = 2 × 3
x = 6
Therefore, the values are x = 6, y = 3
Solve x + y = 4 and 2x - 3y = 9
x = 21/5, y = -1/5
From the first equation, we get the value of x.
x + y = 4
x = 4 - y
Substitute this into the second equation,
2x - 3y = 9
2(4 - y) - 3y = 9
8 - 2y - 3y = 9
8 - 5y = 9
-5y = 9 - 8
-5y = 1
y = -1/5
Now substitute the y value into the equation,
x = 4 - y
x = 4 - (-1/5)
x = 20/5 + 1/5
x = 21/5
Solve x + y = 6 and x - y = 2
x = 4 and y = 2.
Add both equations
(x + y) + (x - y) = 6 + 2
2x = 8
x = 8/2
x = 4
Substitute x = 4 in the first equation
X + y = 6
4 + y = 6
y = 6 - 4
y = 2
Solve x = 5 and x + y = 12.
x = 5 and y = 7
Here, the value of x is already given; we have to substitute it to the second equation.
X + y = 12
5 + y = 12
y = 12 - 5
y = 7.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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