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122 LearnersLast updated on October 30, 2025

An involutory matrix is an invertible square matrix. This means that when an involutory matrix is squared, the result is equal to the identity matrix. This article discusses the definition, properties, and examples of an involutory matrix.
The inverse of an involutory matrix is the matrix itself. Involutory matrices must be square and always have an inverse.
A square matrix is involutory when it gives the identity matrix of the same order upon multiplication by itself. A square matrix A is involutory if it is equal to its inverse, i.e., A = A-1.
For example; \(A = \begin{bmatrix} 0&1\\1& 0 \end{bmatrix}\)
is an involutory matrix because it satisfies both conditions mentioned.
\(A^2 = \begin{bmatrix} 0&1\\1& 0 \end{bmatrix} \cdot \begin{bmatrix} 0&1\\1& 0 \end{bmatrix} = I\)
Here are some other examples of involutary matrix.
Consider a 2 × 2 matrix, \(A = \begin{bmatrix} a&b\\c& d \end{bmatrix}\)
Practice Problem: Now, find whether \(A = \begin{bmatrix} 2&1\\5& 0 \end{bmatrix}\) is an involutary matrix by yourself.
Involutory matrices have unique characteristics that set them apart from other matrices:
For students in smaller grades, here are some tips and tricks to help you understand involutory matrix better:
Parent Tip: Encourage your child to practice squaring of matrices. You can use visual aids for better explanation and calculators to verify your child's answer.
Differentiating between involutory matrices and other matrices can be challenging in the beginning, especially when students aren’t clear on their properties. Listed below are some common mistakes that students can avoid by being aware.
Involutory matrices have several real-life applications in various fields. Some of them are given below:
Is the given matrix involutory?
Yes.
Given Matrix: \(A = \begin{bmatrix} 0&1\\1& 0 \end{bmatrix}\)
Finding A2
\(A^2 = \begin{bmatrix} 0&1\\1& 0 \end{bmatrix} \cdot \begin{bmatrix} 0&1\\1& 0 \end{bmatrix} = I\)
It satisfies the equation.
Find the value of a, if the given matrix is involutory?
\(a = \pm 1\)
Given Matrix: \(A = \begin{bmatrix} a&0\\0& -a \end{bmatrix}\)
Finding A2
\(A^2 = \begin{bmatrix} a&0\\0& -a \end{bmatrix} \cdot \begin{bmatrix} a&0\\0& -a \end{bmatrix} = \begin{bmatrix} a^2&0\\0& a^2 \end{bmatrix} = a^2I\)
So, \(a^2 = \pm 1\)
Is the given matrix involutory?
Yes
Given Matrix: \(A = \begin{bmatrix} 0&2\\0& -1\end{bmatrix}\)
Finding A2
\(A^2 = \begin{bmatrix} 0&2\\0& -1\end{bmatrix} \cdot \begin{bmatrix} 0&2\\0& -1\end{bmatrix} = I\)
It satisfies the equation.
Show that the eigenvalues of the given matrix are 1
Yes, the eigenvalues are +1 and -1.
Suppose A is involutory; this means that A2 = I.
If is an eigenvalue of A and v is its eigenvector, then Av = v
Applying A again, A2v = A(Av) = A(v) = Av = 2v
We know that A2 = I, so
A2v = Iv = v 2v = v 2 = 1 = 1
So, eigenvalues of any involutory matrix are either +1 or -1.
Show that if A is involutory, the An is also involutory for all integers n.
Yes, An is involutory.
A1 = A
A2 = I
\(A^3 = A^2 \cdot A = I \cdot A = A\\ A^4 = A^2 \cdot A^2 = I \cdot I = I\)
. . .
So, for any even power, An = I and I2 = I
And for any odd power, An = A and A2 = I
So all powers An are involutory.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.






