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Last updated on September 30, 2025
Zeros of a polynomial are the values of the variable that make the polynomial equal to zero. In other words, they are the solutions to the equation f(x) = 0. In this article, we will learn about the zeros of a quadratic polynomial and the methods to find them, such as factorization and the quadratic formula.
The value of x that makes a quadratic polynomial equal to zero is known as the zero of a quadratic polynomial. For a quadratic polynomial in the form f(x) = ax2 + bx + c, where a ≠ 0, the zeros of the quadratic polynomial are the values x for which f(x) = 0. The zeros of a quadratic polynomial are also known as roots or solutions of the polynomial.
Polynomials of degree 2 are known as quadratic polynomials. The general form of a quadratic polynomial is ax2 + bx + c, where a ≠ 0, a and b are the coefficients, x is the variable, and c is the constant.
A quadratic polynomial can have a maximum of two zeros because its highest degree is 2. Now, let’s learn how to find the zeros of a quadratic polynomial. The common methods used to find the zeros of a quadratic polynomial are:
Factorization Method
In the factorization method, to find the zeros of a quadratic polynomial, we set the equation as the product of two linear polynomials by factoring them. For example, find the zeros of a quadratic polynomial x2 - 7x + 12 = 0
Step 1: Arrange the polynomial in standard form (ax2 + bx + c = 0)
Here, the given polynomial is in standard form: x2 - 7x + 12 = 0
Here, a = 1, b = -7, and c = 12
Step 2: Finding two numbers
Now find two numbers whose product is ac and sum is b
Here, the numbers are -3 and -4, as -3 × -4 = 12 and -3 + -4 = -7
Step 3: Splitting the middle term
Here, we split 7x as 3x and 4x, then the quadratic polynomial becomes:
x2 - 3x - 4x + 12 = 0
Step 4: Grouping and factoring
Now we factor, x2 - 3x - 4x + 12 = 0 as:
(x2 - 3x) - (4x - 12) = 0
x(x - 3) - 4(x - 3) = 0
(x - 3)(x - 4) = 0
Step 5: Solve the equation
To find the value of x, we solve the equation:
x - 3 = 0 → x = 3
x - 4 = 0 → x = 4
Quadratic Formula
The quadratic formula to find the value of zeros of a quadratic polynomial in the form: ax2 + bx + c = 0 is: x = -b ± b2 - 4ac2a.
For example, find the zeros of a quadratic polynomial 3x2 - 5x + 2 = 0
Here, a = 3
b = -5
c = 2
Substituting the values in the formula: x = -b ± b2 - 4ac2a
x = - -5 ± (-5)2 - 4 × 3 × 22 × 3
x = 5 ± 25 - 246
x = 5 ± 16
x = 5 ± 16
x = 5 + 16 and x = 5 - 16
x = 6/6 = 1
x = 4/6 = ⅔
The zeros of the quadratic polynomial are 1 and 2/3
The nature of zeros of a quadratic polynomial refers to the nature of zeros, that is, whether the zeros are real, distinct, or complex numbers. The nature of zeros is determined using the discriminant(D) of the quadratic polynomial: D = b2 - 4ac.
Value of discriminant |
Nature of zeros |
If D < 0 |
The zeros are complex |
If D > 0 |
The zeros are real and distinct |
If D = 0 |
The zeros are real and equal |
The sum and product of the zeros of a quadratic polynomial show the relationship between its coefficients and roots of a quadratic equation. Let α and β be the zeros of the quadratic polynomial ax2 + bx + c = 0.
The sum of zeros: α + β = -b/a
The product of zeros: αβ = c/a
Let’s now learn how to find the zeros of a quadratic polynomial using a graph. The graph of a quadratic polynomial forms a parabola. The x-intercepts of this graph are the points where the graph intersects the x-axis, and they represent the real zeros of a quadratic polynomial.
The zeros of a quadratic polynomial are used in fields like physics, engineering, architecture, finance, etc. We will explore how the quadratic formula is applied in real-life applications.
When finding the zeros of a quadratic polynomial, students make errors. Here are some common mistakes students make when finding the zeros of a quadratic polynomial, and the tips to avoid them.
Find the zeros of a quadratic polynomial: x2 -5x + 6
Here, x = 2 and x = 3
To find the zeros of the polynomial x2 - 5x + 6, we factor the polynomial
x2 - 5x + 6 = (x -2)(x - 3)
The factors used are -2 and -3 because their product is 6 (which equals ac) and their sum is -5 (which equals b)
Solving the equations:
x - 2 = 0 → x = 2
x - 3 = 0 → x = 3
Find the zeros of x2 - 4x + 4
The polynomial has one real zero, x = 2.
To find the root of the polynomial x2 - 4x + 4, we use the factorization method.
x2 - 4x + 4 = (x -2)2
So, x - 2 = 0
x = 2
Find the sum and product of the quadratic polynomial: x2 + 2x + 5
The sum of the quadratic polynomial is -2, and the product of the quadratic polynomial is 5
Here, a = 1, b = 2, and c = 5
To find the sum of its zeros, we use the formula: -b/a
-b/a = -2/1 = -2
To find the product of the zeroes, we use the formula: c/a
c/a = 5/1 = 5
Find the zeros of x2 + x - 6
x = 2 and x = -3
: To find the zeros of a quadratic polynomial, we use the formula: x = -b ± b2 - 4ac2a
Here, a = 1, b = 1 c = -6
x = -1 ± 12 - 4(1)(-6)2(1)
x = -1 ± 1 + 242
x = -1 ± 252
x = -1 ± 52
So, x = -1 + 52 and x = -1 - 52
x = 42 = 2
x = -1 - 52 = -62 = -3
Find the zeros of x2 + 6x + 9 and verify the relationship between zeros and coefficients of the polynomial.
x = -3 and x = -3. The relationship between zeros and coefficients holds.
To find the zeros of a quadratic polynomial, we use the formulas: x = -b ± b2 - 4ac2a
Where, a = 1, b = 6, c = 9
x = -6 ± 62 - 4(1)(9)2(1)
x = -6 ± 36 - 362
x = -6 ± 02
x = -6 2 = -3
So, the value of zeros are x = -3 and x = -3
The sum of zeros = -3 + -3 = -6
The product of zeros = -3 × -3 = 9
To verify the relationship between zeros and coefficients, for a quadratic polynomial ax2 + bx + c:
Sum of zeros = -b/a = -6/1 = -6
Product of zeros = c/a = 9/1 = 9
So, the relationship between zeros and coefficients of the polynomial is verified.