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Last updated on October 21, 2025

Vector Equations

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A vector is a quantity that has both magnitude and direction. It is represented using an arrow. The length of the arrow reflects the magnitude, and the orientation indicates the direction.

Vector Equations for US Students
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What are Vector Equations?

Vector equations use direction vectors and variables to describe planes or lines in three-dimensional space. A vector with a magnitude of 1 is a unit vector. In a three-dimensional space, all positions are described using 3 axes, the x-axis, y-axis, and z-axis, and each axis has a unit vector. The unit vector for the x-axis is \(\hat {i}\), the unit vector for the y-axis is \(\hat {j}\), and the unit vector for the z-axis is \(\hat {k}\).


In a 3D space, a vector is written as: 
\(\vec{r} = {x {\hat {i}}} + {y {\hat {j}}} + {z {\hat {k}}}\)Where x, y, and z represent the scalar components of the vector.
The vector equation of a line in three-dimensional space is:  \(\vec{r} = \vec{a} + \lambda{{\vec{b}} }\) where \(λ∈R\)                                                                   
The vector equation of a plane in three-dimensional space is: \(\vec{r} \cdot {\vec n} = d\).       

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Vector Equations vs Cartesian Equations

A Cartesian equation is an algebraic expression that shows the relationship between variables (typically x, y, and z) using the Cartesian coordinate system. It is used to describe geometric figures such as lines, curves, and surfaces in terms of their positions on a coordinate plane or in space. Here are some key differences between vector and Cartesian equations.
 

 

Feature

Vector Equation

Cartesian Equation

Form

Uses vectors and vector units.

Uses x, y, and z coordinates directly.

Representation

Line : \({\vec r  = \vec a + \lambda \vec b}\)
Plane: \(\vec r \cdot \hat n = d\)
Line: \({{x - x_1} \over a} = {{y - y_1} \over b} = {{z-z_1} \over c} \)
Plane: \(ax + by + cz = d\)

Nature

Vector-based, compact, and geometric

coordinate-based, algebraic

Variables used

Vectors and scalars

Coordinates

Visualization

Easier to visualize in space using direction and position vectors

Useful for calculations and plotting on a coordinate grid

Used in

Physics and mechanics

Algebraic calculations and graphing

 

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What is the Vector Equation of a Line?

In a three-dimensional space, the vector equation of a line uses vectors to describe all the points that lie on a straight line.
The vector equation of a line that passes through a single point:
                           \(\vec r = \vec a + \lambda \vec b \)
Here,
\(\vec r\) represents the position vector of any point on the line
While \(\vec a\) represents the position vector of a fixed point through which the line passes
\(\vec b\) = direction vector of the line
and \(\lambda\) = scalar parameter that varies.

 

 


Vector equation for a line passing through two points:
        \(\vec r  = \vec a + \lambda(\vec b - \vec a)\)

 


                            
Here, 
\(\vec a\) (position vector of point A)
\(\vec a = x_1 \hat i + y_1 \hat j + z_1 \hat k \)
\(\vec b\) (position vector of point B)                                          
  \(\vec b = x_2 \hat i + y_2 \hat j + z_2 \hat k \)

 

 

The direction vector is \(\vec b - \vec a\), pointing from point A to point B.
\(λ∈R\) is a scalar parameter
 

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What are Vector Equations of a Plane?

The vector equation represents motion from a fixed point in a plane along two independent directions.
  \(\vec r = \vec a + s \vec u + t \vec v\)

Here, \(\vec r\) is the position vector of any point P(x, y, z) lying on the plane
\(\vec a\) is vector of a specific point on the plane
\(\vec u, \vec v\) are two non-parallel direction vectors that lie on the plane.
s and t are scalar parameters; they can be any real number.
 

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Tips and Tricks to Master Vector Equations

Vector equations help us represent lines, planes, and directions in space using vectors. In this section, we will discuss some tips and tricks to master vector equations. This help students to solve problems in physics and mathematics much more easily.

 

  • Always separate the components, that is, break the vectors into x, y, and z components before solving. 

     

  • use unit vectors, express the vectors as combinations of i, j, and k. It simplifies addition, subtraction, and scalar multiplication. 

     

  • Memorize the basic formulas like: 
    Angle between vectors: \(cos{\theta} = {{{\vec a \cdot \vec b} \over  |\vec a| |\vec b|}}\)
    Perpendicular vectors: Dot product = 0 \({(\vec a \cdot \vec b = 0 )}\)Magnitude: \({{|\vec v| = \sqrt {x^2 + y^2 + z^2}}}\)

     

  • If a vector is a multiple of another vector, then the vectors are parallel. For example, (2, 4) is parallel to (1, 2).

     

  • Students can draw a simple diagram to visualize how the vectors look, where they point, and how they relate to each other. This help students to understand if they are parallel, perpendicular, or intersecting.

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Common Mistakes and How to Avoid Them in Vector Equations

Vector equations are crucial in solving 3D geometry problems and various subjects like physics and engineering. To ensure a better understanding and precise results, avoid the following frequent errors that get overlooked:

Mistake 1

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Confusing position vectors and direction vectors
 

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Always remember that the point gives you a starting location, and the direction vector tells you where the line or plane goes. Do not interchange them.

Mistake 2

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Using only one direction vector when defining a plane
 

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A plane requires two non-parallel direction vectors; using only one direction vector means the movement is only across a line and not the plane.

Mistake 3

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 Forgetting the parameter
 

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If the parameter is omitted, the equation describes only a single point rather than the entire line.
 

Mistake 4

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Mixing scalar and vector quantities

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Vectors can only be added to vectors, not to plain numbers, so be sure to check vector operations.
 

Mistake 5

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Using parallel direction vectors for planes
 

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Direction vectors that are parallel or scalar multiples do not have independent directions. Hence, it results in a line being spanned and not a plane.
 

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Real-Life Applications of Vector Equations

Vector equations represent quantities having both magnitude and direction. They play a crucial role in various real-life, direction-based calculations:

 

  • Force and motion analysis: Vector equations describe the position, velocity, and acceleration of moving objects in space. This helps analyze trajectories, forces, and dynamics in mechanics.

     
  • Graphics and Animations: Vectors represent object positions, directions, and transformations in 2D or 3D space. They are used in calculations for moving graphic objects and rendering in games or simulations.

                         \(\vec p_{new} = \vec p _{original} + \vec v \cdot  t \)
 

  • GPS and Navigation Systems: GPS uses vector math to compute displacement, direction, and distance between two points on Earth, determining shortest paths.


 

  • Robotics: Vector equations are used in machinery like robotic arms to reach a point in 3D space. Movement and orientation are modeled using vector equations for precise positioning. 

     
  • Engineering- structural analysis: Engineers use vectors to model forces acting on structures such as bridges and buildings. Vector equations help in calculating stress, strain, and stability.
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Solved Examples of Vector Equations

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Problem 1

Find the vector equation of a line passing through a point A(1,2) and having a direction vector d = 34

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\(\vec r (\lambda) = \begin{bmatrix} 1 + 3\lambda \\ 2 + 4\lambda \end{bmatrix} \)

Explanation

The vector equation of a line is:
               \(\vec r (\lambda) = \vec a + \lambda \vec d\)
Where:
\(\vec a\) = \(\begin{bmatrix} 1 \\ 2 \end{bmatrix} \) position vector of A
\(\vec d = \begin{bmatrix} 3 \\ 4 \end{bmatrix} \)
\(\vec r (\lambda) = \begin{bmatrix} 1 \\ 2 \end{bmatrix} + \lambda\begin{bmatrix} 4 \\ 3 \end{bmatrix} \)
\(= \begin{bmatrix} 1 + 3\lambda \\ 2 + 4\lambda \end{bmatrix} \)

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Problem 2

Let u = [2, -1, 4] and v = [-3, 0, 1]. Find u + v

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\(\vec u + \vec v = {{\begin{bmatrix} -1 \\ -1 \\ 5 \\ \end{bmatrix} }}\)

Explanation

\(\vec u + \vec v = \begin{bmatrix} 2 \\ -1 \\ 4 \\ \end{bmatrix} + \begin{bmatrix} -3 \\ 0\\ 1\\ \end{bmatrix} \)

\(\begin{bmatrix} 2 - 3 \\ -1 + 0\\ 4 + 1 \\ \end{bmatrix} \)

\(\begin{bmatrix} -1 \\ -1\\ 5 \\ \end{bmatrix} \)

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Problem 3

Let a = [3 4] and b = [4 3]. Find the angle Θ between them

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\(\theta = 16.26 ^\circ\)

Explanation

Finding \(\vec a \cdot \vec b\) to find the angle \({{{\theta }}}\),

\({{\vec a \cdot \vec b }} = {3 \times 4} + {4 \times 3}\\ = 12 + 12 \\ = 24\)

Finding the magnitudes of \(\vec a {\text { and }} \vec b\)
\(|\vec a| = \sqrt {3^2 + 4^2} = 5,\\ |\vec b| = \sqrt {4^2 + 3^2} = 5\\ \)

To find the value of  \({{{\theta }}}\), we use the formula: 

\({{\vec a \cdot \vec b }} = {{|\vec a| |\vec b| cos {\theta}}}\)

​​​​​​\({{\vec a \cdot \vec b }} = {{|\vec a| |\vec b| cos {\theta}}} \implies 24= 5 \times 5 cos {\theta} \\\implies cos {\theta } = {24 \over 25}\\ \implies {\theta } = cos^{-1} {{({24\over 25})}} \approx 16.26 ^\circ\)

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Problem 4

Project vector a = [2 4] onto vector b = [1 2]

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\({{{\text { Proj} _ {\vec b} {\vec a}}}} = \begin{bmatrix} 2 \\ 4 \\ \end {bmatrix} \)

Explanation

\( \text{Proj}_{\vec{b}} \vec{a} = {({\vec a \cdot \vec b \over \vec b \cdot \vec b})} \vec b \)

Finding \({\vec a \cdot \vec b} = {2 \times 1 + 4 \times 2} = 10\\ {\vec b \cdot \vec b} = {1^2 + 2^2} = 5\\ \)

\( \text{Proj}_{\vec{b}} \vec{a} = {{({10 \over 5})}} \begin{bmatrix}1 \\ 2\\ \end {bmatrix}\\ = 2 \begin{bmatrix}1 \\ 2\\ \end {bmatrix} \\ = \begin{bmatrix}2 \\ 4\\ \end {bmatrix}\)

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Problem 5

Find the vector equation of a plane passing through point A(1,0,2) with direction vectors

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\(\vec r (s, t) = \begin {bmatrix} 1 + s \\ 2s + t\\ 2 + 3t\\ \end {bmatrix}\)

Explanation

The vector equation for the palne is: 

\(\vec r (s, t) = \vec a + s \vec u + t \vec v\)

Here, a = (1, 0, 2)

\(\vec u = \begin {bmatrix} 1\\ 2\\ 0\\ \end {bmatrix}\)
\(\vec v = \begin {bmatrix} 0\\ 1\\ 3\\ \end {bmatrix}\)

So, \(\vec r (s, t) = \begin {bmatrix} 1\\ 0\\ 2\\ \end {bmatrix} + s \begin {bmatrix} 1\\ 2\\ 0\\ \end {bmatrix} + t \begin {bmatrix} 0\\ 1\\ 3\\ \end {bmatrix}\)

\(= \begin {bmatrix} 1 + s\\ 2s + t \\ 2s + 3t\\ \end {bmatrix}\)

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FAQs on Vector Equations

1.How to find a vector?

A vector is found by subtracting the coordinates of two points. On the other hand, if we know the magnitude and direction, multiplying the magnitude by a unit vector in the given direction gives us the vector.
 

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2.How to find symmetric equations?

To find symmetric equations of a line in 3D, start with its vector or parametric form 
                                                 
             Eliminate parameter t: x-x0a=y-y0b=z-z0c                                                          
                                                             
We assume that a, b, and c are not zero. So, this is the symmetric form of the line.
 

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3.Parametric vs symmetric equations

Parametric Equations

Symmetric equations

Step-by-step movement along the line

full line describing coordinate dependency without a parameter.

Parameters, like t, are involved 

No parameter, all variables are related directly

represents the position of a specific point on a line

Represents the full line in a compact form

Derived from a point and a direction vector

Derived from eliminating t from parametric equations

Requires parameter substitution for use

Symmetric equations are not required if any direction vector component is 0 (division by zero)

Good for motion/path modeling

Good for algebraic manipulation or solving systems

 

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4.Can vector equations describe curves?

Yes. For example, the position of a basketball’s path during a game can be described using a vector function of time: r (t)=❰x(t), y(t), x(t)❱
 

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5.How to find the intersection of two vector equations?

 Make sure both sides of the vector are equal. Then solve for the parameters. If a solution exists, the lines intersect.
 

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Jaskaran Singh Saluja

About the Author

Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.

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Fun Fact

: He loves to play the quiz with kids through algebra to make kids love it.

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