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Last updated on September 26, 2025

Implicit Function

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An implicit function describes the relationship between independent variables and a dependent variable. In a single equation, like y - 3x2 + 2x + 5 = 0, an explicit function shows the output clearly, but an implicit function doesn’t. Like y = 3x + 2. Implicit differentiation uses the chain rule or product rule to find the derivative without solving for y.

Implicit Function for US Students
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What Is An Implicit Function?

An implicit function includes the dependent variable within an equation, like x2+y2=1, without solving for it. Instead of giving y explicitly as y = f(x). Implicit differentiation lets you find dy/dx by differentiating both sides using the chain rule without solving for y first. Implicit differentiation is useful when it’s hard or impossible to solve for y directly.
 

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Properties of Implicit Function

Cannot be written as y = f(x)

The dependent variable y isn't isolated; both x and y appear together in the same equation

Always in the form f(x, y) = 0

The equation combines x and y like x2+y2-1 = 0 for a circle

Frequently non-linear and multivariable

Many implicit functions are polynomials or complex relations, including many variables

Combines dependent and independent terms.

These cannot be easily solved for y because it stays within the equation with x.

It may not pass the vertical line test.

An implicit relation does not always pass the vertical line test because:
A vertical line might cross its graph more than once.
That means y is not a single-valued function of x.
 

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Derivative of Implicit Function

While solving an equation involving both x and y together f(x, y) = 0, you can't isolate y very easily, you directly differentiate both sides without solving a variable first. With respect to x treating y as a function of x and use the chain rule whenever you differentiate a term including y.

Differentiate each term in the equation with respect to x, adding dydx while differentiating anything with y
Collect all dydx, terms on one side
Solve for dydx, the result will usually involve both x and y

x2+xy+y=0

Differentiate both sides w.r.t.x:

ddx(x2)+ddx(xy)+ddx(y)=0

Becomes

2x+(xdydx+y1)+dydx=0

Combine dydx terms and isolate

(x+1)dydx+(2x+y)=0dydx=-2x+yx+1

You get dydx directly without needing to solve for y first.
 

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Implicit Function Theorem

The implicit function theorem helps to turn complicated relationships into simpler functions of real variables. It shows that, even if a relation doesn’t define a function globally, it can behave like a function locally. For example, given an equation like F(x, y)=0, the theorem ensures that we can solve for y as a smooth function of x. Certain partial derivatives are non-zero, indicating how the function changes as x changes.
 

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Real-Life Applications of the Implicit Function

Real life application is important in many fields such as economics, physics, chemistry, The uses are explained below;

  • Economics-marginal rate of substitution: Economists use implicit differentiation to analyze trade-offs between goods to find how much more of one good is needed to remain equally satisfied when consuming less of another, for example for utility equation U(x, y)=k, implicit differentiate gives dy/dx = -(Ux/Uy)
  • Ladder sliding problem: This is used by teachers and students to solve motion problems in physics. As a ladder slides down a wall, its top moves downward while the base slides outward. To relate the rates of change of these positions, we use implicit differentiation. For example, if the ladder has a fixed length h, and its position forms a right triangle, the relationship is: x2+y2=h2 
  • By differentiating both sides with respect to time t, we can find dydt (how fast the top is falling) in terms of dxdt (how fast the base is sliding).
  • Physics-motion with constraints: Physicists analyzing moving or constrained systems often deal with motion equations in implicit form. Implicit differentiation is used to find quantities ;like velocity and acceleration when dependent on multiple variables. For example, pendulum constraints x2+y2=l2; differentiate implicitly to find angular acceleration
  • Fluid dynamics/ engineering: This is used by engineers modeling pressure and flows, where equations relating to pressure, velocity, and geometry are often implicit. Implicit differentiation helps to find the gradients, such as in the Navier-stokes equation, to predict the fluid behavior.
  • Thermodynamics/ chemistry: Implicit differentiation is used in thermodynamics. This helps in finding how the pressure changes with volume or temperature in gas laws like the Van der Waals equation, where variables are interdependent. 
     
Max Pointing Out Common Math Mistakes

Common Mistakes With Implicit Function and How to Avoid Them

While solving implicit function, students often forget that y depends on x in implicit differentiation. 
 

Mistake 1

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Forgetting chain rule

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Differentiating y2 as 2y instead of 2ydydx, to avoid this always treat y as y(x), for example: d/dx(y2) =2ydydx
 

Mistake 2

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Misapplying product rule
 

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 Differentiating xy incorrectly, always use product rule: d(xy)/dx=y+xdydx, for example from xy=1, you get y+x dy/dx=0

Mistake 3

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Forgetting to substituting point values early
 

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Delaying substitution of point coordinates until after isolating dydx can lead to errors. Substitute early when finding the slope at a point. 
 

Mistake 4

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Neglecting domain restrictions or sign issues
 

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Overlooking that some derivatives, like those of inverse functions, are only valid within certain domains or intervals. Particular domain, to avoid this always confirm variable ranges before differentiating
 

Mistake 5

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Overlooking zero on right side
 

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 Forgetting that derivative of constant 25 is 0, to avoid this always differentiate constants properly, for example In x2+y2=25, derivative of 25 is 0
 

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Solved Examples of the Implicit Function

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Problem 1

Differentiate the equation x2+y2=2.

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 dydx=-xy
 

Explanation

Here, we are given a relation involving both x and y. Since y is implicit of a function x, we apply the chain rule while differentiating y2. The derivative of the x2 is 2x, and the derivative of y2 is 2ydydx. After the differentiation, we only take dydx to get the final answer.
ddx(x2+y2)=ddx(2)
2x+2ydydx=0
dydx=-xy
 

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Problem 2

Differentiate the equation x2+y3=4

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dydx=-2x3y2
 

Explanation

Differentiate both the sides of the equation with respect to x. Apply the power rule to x2 and the chain rule to y3(since y is a function of x). After differentiating, we rearrange the equation to isolate dydx.
ddx(x2+y3)=ddx(4)
2x+3y2dydx=0
Then,
dydx=-2x3y2 
 

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Problem 3

Find the derivative dydx for the equation x . y3=1

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dydx=-y3x 
 

Explanation

Here, we use the product rule to differentiate x . y3. The derivative of x is said to be 1 and that of y3 is 3y2dydx. Now, simplify to separate dydx. Finally, reduce the expression.
ddx(xy3)=ddx(1)
y3+x . 3y2dydx=0
3xy2dydx=-y3
dydx=-y3x

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Problem 4

Differentiate the equation 2y3+4x2-y=x6

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 dydx=6x5-8x6y2-1
 

Explanation

 Here, differentiate each term of the equation. Use the chain rule for y3 and y, and the power rule for the x2 and x6. Now, group the terms containing dydx, factor it out, and solve for it.
Here,
ddx(2y3+4x2-y)=ddx(x6)
6y2dydx+8x-dydx=6x5
(6y2-1)dydx=6x5-8x
dydx=6x5-8x6y2-1 
 

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Problem 5

Differentiate x2+xy+y2=4

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dydx=-2x+yx+2y
 

Explanation

Here, to differentiate xy we need the product rule, which is derivative of x is 1, and derivative of y is dydx. After applying the derivative to each term, combine the like terms and isolate dydx.
Here,
ddx(x2+xy+y2)=ddx(4)
2x+(xdydx+y)+2ydydx=0
(x+2y)dydx=-2x-y
dydx=-2x-yx+2y
 

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FAQs of the Implicit Function

1. What is the implicit function?

A function that cannot be easily represented in the form y=f(x) is called an implicit function.
 

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2.What is an implicit type function?

An implicit type function is a function where the dependent variable is not isolated. But, both the dependent and independent variables appear together in a single equation.
 

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3.What is the explicit function?

 A function that is often written as one variable, or dependent variable, in terms of another variable, or independent variable.

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4.What is an example of implicit type?

Multiplying an integer by a float, the integer will be prompted to a float for the duration of the evaluation of the expression.
 

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5.What is called implicit differentiation?

Implicit differentiation is the process of finding the derivatives when the dependent variable is not isolated in the equation.
 

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