Summarize this article:
267 LearnersLast updated on October 29, 2025

If a square matrix becomes a zero matrix when raised to a certain power, then it is called a nilpotent matrix. In this article, we will learn how to find a nilpotent matrix, its properties, and applications.
A square matrix is called nilpotent if it becomes the zero matrix when raised to a specific power.
For example: \(A = \begin{bmatrix} 0 & 1 \\0 &0\end{bmatrix}\)
\(A^2 = \begin{bmatrix} 0 & 1 \\0 &0\end{bmatrix} \cdot \begin{bmatrix} 0 & 1 \\0 &0\end{bmatrix} = \begin{bmatrix} 0 & 0 \\0 &0\end{bmatrix}\)
Since we get A2 = 0, A is nilpotent with index 2.
To check whether a matrix is nilpotent or not, we need to confirm if it's a square matrix (n × n). The next step is to raise the power of the base in ascending order to check if the result is a zero matrix.
In other words, calculate the successive powers like A2, A3, .… up to An. If any power k makes the matrix zero (Ak = 0), then it's nilpotent.
Let's understand it with an example.
Example; \(A = \begin{bmatrix} 0 & 3&1 \\0 &0&3 \\ 0&0&0 \end{bmatrix}\)
Nilpotent matrices have rules that make them behave in certain ways. Understanding these properties makes it easier for us to work with them. Some of their properties are:
If a square matrix A turns into the zero matrix when raised to some power k (Ak = 0), so each eigenvalue \(\lambda \) of A satisfies \(\lambda^k\) = 0. Each \(\lambda \) should be zero. Also, if all the eigenvalues of a matrix are zero, its characteristic polynomial will be xn.
By the Cayley-Hamilton Theorem, if all eigenvalues are zero, the characteristic polynomial is \(\lambda ^n\), so An = 0, confirming nil potency.
For Example: \(A = \begin{bmatrix} 0 & 1 \\0 &0\end{bmatrix}\)
We will check the eigenvalue by solving \( {\text{det(A }– \lambda I) = \lambda^2 = 0, \lambda = 0}\).
A2 = 0, defining that it's nilpotent, and all eigenvalues are zero.
To make the learning easy for students from smaller grades, here a some effective tips and tricks:
Parent Tip: You can relate nilpotent matrix with real world situations. Like lighting a matchstick, the flame extinguishes after a few seconds. When it does, it is nilpotent. Similarly, you can use many examples. Encourage your child to practice with example and to ask questions when stuck.
A nilpotent matrix is not an easy concept to understand; this could cause confusion and mistakes. However, with practice and perseverance, we can strive for excellence while dealing with nilpotent matrices. Let’s start by going through some common mistakes students make while handling nilpotent matrix, so that we can avoid these mistakes in the future:
There are many uses of nilpotent in our real world in the fields of nature, architecture, biology, art, and design. Here are some examples of real-life applications of nilpotent matrices:
Does a 2 × 2 matrices with zero on the diagonal and one above it become zero when squared?
Yes, such a matrix becomes zero when squared.
While squaring this matrix gives the zero matrix, so it's a nilpotent with index 2.
Let take an example of such matrix
\(A = \begin{bmatrix} 0 & 1 \\0 &0\end{bmatrix}\)
\(A^2 = \begin{bmatrix} 0 & 1 \\0 &0\end{bmatrix} \cdot \begin{bmatrix} 0 & 1 \\0 &0\end{bmatrix} = \begin{bmatrix} 0 & 0 \\0 &0\end{bmatrix} \)
Is the 2 × 2 matrices with [2, -4: 1, -2] nilpotent?
Yes, it's nilpotent.
Given matrix: \(A = \begin{bmatrix} 2 & -4 \\1 &-2\end{bmatrix}\)
Squaring matrix A:
\(A = \begin{bmatrix} 2 & -4 \\1 &-2\end{bmatrix} \times \begin{bmatrix} 2 & -4 \\1 &-2\end{bmatrix} = \begin{bmatrix} 0& 0 \\0 &0\end{bmatrix}\)
Squaring this produces the zero matrix, so it goes to the power of 2.
Is the 3 × 3 strictly upper-triangular matrix (zeros on diagonal, numbers above) nilpotent?
Yes, the 3 × 3 strictly upper-triangular matrix is nilpotent.
Such a matrix will always be zero when raised to the third power.
Example: \(M = \begin{bmatrix} 0 & a & b \\0 &0&c \\ 0 & 0 & 0\end{bmatrix}\)
Is the 2 × 2 matrix with entries [2, -1: 4, -2] nilpotent?
Yes, the matrix is nilpotent of index 2, since the square matrix A2 = 0.
Given matrix: \(A = \begin{bmatrix} 2 & -1 \\4&-2 \end{bmatrix}\)
Do a 3 × 3 strictly upper-triangular matrices (zeros below and diagonal, numbers above) become zero at the third power?
Yes, it becomes zero at the third power.
When we multiply it three times gives the zero matrix, so yes, it's nilpotent with index 3.




