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Last updated on June 10th, 2025

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Algebraic Equations

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Suppose we are doing a puzzle, but we don’t know the last mystery number. We only know that if we add 3 to the mystery number, we can sort the puzzle. Here, algebraic equations help us find the number and we can solve the puzzle. A mathematical statement that has two equated algebraic expressions is known as algebraic equations. An equal to (=) sign joins these two algebraic expressions. An algebraic equation contains numbers, letters, and mathematical operations. In this topic, we are looking into algebraic equations in detail.

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What are Algebraic Equations?

Algebraic equations are like a secret code. By using letters like x and y we can identify the relationship between numbers and unknown values. An algebraic equation’s generic form is P = O or P = Q, here P and Q are polynomials. The equation’s right and left sides will always be identical and balanced. An algebraic equation shows the relationship between two expressions by connecting them. The main aim of an algebraic equation is to find the value of an unidentified variable. 
For example, 5 + x = 8 is an algebraic equation. Here, we need to find the unknown value of ‘x’. Also, the value of ‘x’ will make both sides equal. 
The value of x = 3
Now, we can substitute the value of ‘x’ in the equation.
5 + 3 = 8.
 

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History of Algebraic Equations

The history of algebraic equations dates back thousands of years. The term ‘Algebra” was introduced in the 9th century by a Persian mathematician, Al-Khwarizmi. He is known as the father of algebra. His book named “Al-Kitab al-Mukhtasar fi Hisab al-Jabr wal-Muqabala” contributed to the systematic solving of equations. Over time, algebra became widespread in Europe. In the 16th and 17th centuries, many mathematicians introduced new notations and methods of algebra. The foundation of modern algebra was established by mathematicians like Evariste Galois and Niels Henrik Abel. They made significant contributions to algebra. In mathematics, algebra is a fundamental concept that helps to find solutions for various calculations. 
 

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Properties of Algebraic Equations

Algebraic equations are one of the foundations of modern mathematics. Knowing this essential concept helps students understand and learn quickly about the algebraic principles. Learning the properties of algebraic equations is useful in finance, physics, engineering, and economics. 

 


The arrangement of the numbers, which we add or multiply, does not make any change in the outcome. For example, an algebraic equation is a + b = b + a 
2+ 3 = 3 + 2 = 5
Let us look into another illustration, (a + b) + c = a + (b + c)
Here the grouping of numbers does not affect the answer. Take a look at this,
(1 + 2) + 3 = 1 + (2 + 3) = 6

 


Addition and subtraction are distributed across multiplication. For instance, 
a × (b +c) = (a × b) + (a × c)
Now we can apply value to these variables. 
6 × (3 + 1) = (6 × 3) + (6 ×1) 
First, we can add 6 × (3 + 1):
6 × (3 + 1) = 6 × 4 = 24
Now, move on to the next set, i.e., (6 × 3) + (6 ×1) 
(6 × 3) + (6 ×1) = 18 + 6 = 24
Both ways give the same answer. Now, we know that multiplication distributes over addition and subtraction. 

 


In an equation, if we add zero or multiply by 1 does not make any change to the number. Let us look into this property in detail.
For example, a + 0 = a 
2 + 0 = 2
Likewise, if we multiply a number by 1, in an equation, the digit will remain unchanged.
b × 1 = b
8 × 1 = 8

 


We get identity values through the addition of the additive inverse or the multiplication by the reciprocal(multiplicative inverse). 
An additive inverse is the opposite of a number. For example, the additive inverse of 5 is -5. 
Multiplicative inverse refers to the number we used to multiply to get 1. For instance, the multiplicative inverse of 6 is ⅙.
6 × ⅙ = 1
 

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Types of Algebraic Equations

The various types of algebraic equations are determined by the structure and the nature of the numbers involved in the formula. Algebraic equations show the equality of two algebraic expressions. Understanding types of algebraic equations helps students easily point out the right methods for solving calculations effectively. The main types of algebraic equations are listed below:

 

 

  • Linear equations
  • Quadratic equations
  • Cubic equations
  • Polynomial equations
  • Rational equations 
  • Radical equations

 

Let us take a closer look at each type of algebraic equation.

 


Linear Equations


The highest degree of a variable in a linear equation is 1. Linear equations are also known as first-order equations. When we graph this equation, it forms a straight line. It is the simplest type of equation. The linear equations consist of constants like numbers and variables like x or y. 
The general form of linear equations is:
a1x1  + a2x2 +... + anxn + c = 0
In this, at least one of the coefficients is not zero. Take a look at this example,
ax + b = 0
ax + by + c =0 
In the first equation, x is only one variable. In the second equation, x and y are the two variables. 
For instance, 
2x + 3 = 0 
This is a linear equation in one variable. Here, we have to find the value of ‘x’. To get the balance over two sides of the equation, we need to do the same thing on both sides.
Now, let us subtract 3 from both sides. 
Subtract 3 from 2x + 3, it gives 0(+3 -3)
Subtract 3 from 0, it gives -3. 
We get, (2x + 3) - 3 = 0 -3 
So, 2x = -3  
Here, 2x means two times x. Now, we have to divide both sides of the equation by 2.
2x/2 = -3/2
x = -3/2 = -1.5
Hence, the value of x is -1.5. 
2 × -1.5  + 3 = 0 

 


Quadratic Equations


In a quadratic equation, the highest power of a variable is 2. This equation is also known as the second-degree equation.  When we graph this equation, it forms a U-shaped curve. The general form of a quadratic equation is:
ax2 + bx + c = 0
Here, x is the variable that is squared. The numbers are a, b, and c. The value of a is not equal to zero. For example,  
3x2 + 5x + 7 = 0
Now we can find the coefficients:
a = 3
b = 5
c = 7
To figure out the value of ‘x’, we need to apply the quadratic formula
x = -b ± √b2- 4ac / 2a
Let us substitute the values:
x = -5 ± √52- 4 × 3 × 7 / 2× 3
Now, we can simplify each element:
52 = 25 
4 × 3 × 7 = 84
2 × 3 = 6
Now, we can subtract 4ac - b2
25 - 84 = -59
x =  -5 ± √-59 / 6
√-59 is a negative number, so we use an imaginary number denoted by ‘i’.
√-59 = i√59
The final equation will be:
x = -5 ± i √-59 / 6

 


Cubic Equations

 

The highest power of the variable in a cubic equation is 3. Cubic equations are also known as third-degree equations. These equations have real or complex numbers that depend on the coefficients. 
The general form of a cubic equation is:
ax3 + bx2 + cx + d = 0
Another example of cubic equations is:
2x3 + 3x2 - 5x + 4 = 0
a = 2 
b =3 
c = -5
 d = 4

 


Polynomial Equations


A polynomial equation has a polynomial expression. The value of the polynomial is equal to zero. A polynomial equation is made up of variables, coefficients, and non-negative integer exponents. These equations have several terms with different powers, such as x2, and x3. These variables can be added or subtracted together.  The general form of a polynomial equation is:
anxn + an-1xn-1 + ….+a1x = a0 = 0
To understand the polynomial equation better, look at these examples,
3x3 - 5x2 + 2x - 7 = 0
2x2 - 3x +1 = 0
Here, x is the variable, an, an-1, a1, and a0 are the coefficients. The degree of the polynomial is ‘n’ which is a non-negative integer.

 


Rational Equations


An equation containing fractions that have a variable in the numerator or denominator is known as a rational equation. By removing the fractions, these equations can be solved. Usually, the variable is in the denominator. These types of equations have two sides and have rational expression terms on each side. The general form of a rational equation is:
f(x) / g(x) = h(x)
Here,  g(x) is the denominator.
f(x),  g(x) and h(x) are the fractional variables. 
For a better understanding, take a close look at these examples of rational equations,
3/x + 5 = 7 
2/x + 3 = 5
When we solve rational equations, first, isolate the fraction. Next, multiply both sides by the denominator. After that, solve for the variable. 

 


Radical Equations


In radical equations, a variable has a radical sign, such as a square root (√), cube root (³√), or any other root. The variable will be inside the root. The general form of the radical equation is:
n√f(x) = g(x)
The radical term in the equation is n√f(x).
f(x) is inside the root. 
g(x) can be a constant.
Some examples of radical equations are:
√x + 4 = 6. This is an example of a square root radical equation.
∛x + 2 = 3. This is an example of a cube root equation.
 

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Importance of Algebraic Equations for Students

Algebraic equations are mathematical statements that show the relationship between two algebraic expressions. They are the fundamental concepts that pave the way for modern mathematical concepts. Knowing algebraic equations helps students to focus more on advanced math and its complicated calculations. Proper knowledge of these equations improves kids' problem-solving and logical reasoning skills. Knowing the concepts of algebra is essential for understanding calculus, statistics, and linear algebra. Algebraic equations help students to approach real-life problems such as budgeting, decision-making, and so on. 

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Key Concepts in Algebraic Equations

Various key concepts made up the foundation of algebraic equations. Expressions and equations of algebra contain variables, coefficients, constants, and mathematical operations. Knowing these key concepts will help us to solve real-life problems as well as mathematical calculations.

 


Variables and Constants


Variables are the symbols in algebraic equations, that denote an unknown value. Variables are denoted as x, y, or any other letter. The value of constants will remain unchanged.  Constants have a fixed value. 
For example, 2x + 4 = 10 
Here, ‘x’ is the unknown value.
4 and 10 are constants.

 


Terms and Coefficients


A term in an algebraic equation is a component that is divided by addition and subtraction. A number that multiples the variable is known as a coefficient. Each term has a coefficient. 
For example, 
3x + 5 = 11
Here, 3x and 5 are the terms. 3 is the coefficient, which multiplies x. 

 


Expressions vs. Equations


An expression is a phrase in mathematics, without an equal sign, and may contain operations, variables, and numbers. An equation is a mathematical statement that includes an equal sign, and it states the two expressions are equal. 
Let us take a look at an example of expressions:
4x + 2
It does not have an equal sign(=).
An example of an equation is:
4x + 2 = 22
In the example above, both sides are equal and it has an equal sign. 

 


Solving Equations


Solving equations is a process of finding the answer or the unknown value of variables. It makes the equation true. We substitute the value with the equations and find the answer. 
For example, 3x + 4 = 10
While we solve this problem, we come to know that, the value of x is 2. 
Now, let us look at how we get the value of x as 2. 
The given equation is 3x + 4 = 10
To isolate 3x, we rearrange the equation as:
3x = 10 - 4
3x = 6
Next, divide 6 by 3 to get the value of x.
x = 6 / 3 = 2
Now, we get x = 2. 
3 × 2 + 4 = 10.
 

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Tips and Tricks to Solve Algebraic Equations

If we properly understand the concepts of algebraic equations, the solving process of calculations becomes much easier. There are some tips and tricks that should help students to get mastery over algebraic equations. They are listed below:

 

 

  • Knowing about the structure of equations helps kids to solve calculations efficiently.  An equation contains constants, coefficients, and variables. Also identifying which type of equation will enhance the overall performance. 

     
  • Always remember to keep a balance for the equation. For example, 2x + 4 = 10. x = 3. 2 × 3 + 4 = 6 + 4 = 10. If we apply any operations on one side, do the same operation on the other side. 

     
  • If we are performing a quadratic equation use the quadratic formula. The general form of a quadratic equation is ax2 + bx + c = 0. To apply the formula x = -b ± √b2- 4ac / 2a will help to solve operations straightforward. 

     
  • When we solve rational equations, first we need to isolate the fraction, then multiply both sides by the denominator. 
     
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Real-World Applications of Algebraic Equations

The uses of algebraic equations are not only subjected to the mathematical classes; they also apply to various industries such as science, finance, engineering, economics, and so on.  The real-world applications of algebraic equations are countless. In finance and economics, algebra plays a vital role in calculating expenditure, savings, and profit, as well as in planning new strategies. To build machines, bridges, and any other constructions, professionals apply algebraic equations. For example, when we build a bridge, we use algebraic equations to find the dimensions of the architecture. 
 

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Common Mistakes and How to Avoid Them in Algebraic Equations

Mistakes are common when performing algebraic equations. Sometimes, algebraic equations seem tricky and complex. Understanding the common errors and their solutions helps students solve calculations correctly. 
 

Mistake 1

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Not applying the same operation to both sides
 

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Always remember to apply the same operation to both sides of the equation. Ensure the proper balance when simplifying or solving calculations. If we forget to do identical operations, it will lead to wrong answers. For example, 2x + 3 = 0 
Subtract 3 from both sides. 
We get, (2x + 3) - 3 = 0 -3 
So, 2x = -3  
Now, we have to divide both sides of the equation by 2.
2x/2 = -3/2
x = -3/2 = -1.5
Hence, the value of x is -1.5. 
 

Mistake 2

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Wrong factorization
 

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If we perform factorization, be careful to start with the smallest prime factors. It is a process of breaking an expression into small, according to its factors. For example, if we factorize x2 + 6x + 8:
First, we have to figure out two numbers that multiply 8 and sum up to 6.
(x + 4) (x + 2) = x2 + 6x + 8
We can start with the quadratic expression, to properly factorize:
 x2 + 6x + 8
Next, we factorize it:  x2 + 6x + 8 = (x + 4) (x + 2) 
Thus the factorization is x2 + 6x + 8 = (x + 4) (x + 2).
 

Mistake 3

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Neglecting variable restrictions
 

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Identify the restrictions on variables before performing the equations. When we substitute certain numbers for an equation, it has undefined values. So, set the denominator not equal to zero to find the restrictions. Because if we divide by zero, there is no solution. 
For example, 
5/0 = no answer.
 

Mistake 4

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Mistakenly place negative signs
 

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Be careful when we place negative signs in the equations. If we incorrectly handle the signs, the outcome will be wrong. 
For example, 
-(x -4) = -x + 4
In the above example, the negative signs are distributed properly. 
 

Mistake 5

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 Forgetting to distribute multiplication over addition and subtraction

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Always remember to apply multiplication over addition and subtraction. We should apply the same operations to the variable and constant. 
For example, 
2(x+3) = 10 
Here we should not forget to multiply the number 2 by variable and constant. 
2(x+3) = 10 
2x + 6 = 10
Next, we have to subtract 6 from both sides:
2x = 10 - 6 = 4
2x = 4
Now, we can divide both sides by 2:
x = 4 / 2 = 2
Hence, the value of x is 2. 
 

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Solved Examples of Algebraic Equations

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Problem 1

Find the value of ‘x’ in the equation x + 3 = 2x.

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 x = 3
 

Explanation

First, we need to subtract x from both sides of the equation
x + 3 -x = 2x - x 
On the left side of the equation: x - x +3 = 3 
3 = x
The next side of the equation: 2x - x = x
Hence, the final result is x= 3. The value of x is 3. 
 

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Problem 2

Antony has x oranges. His friends gave him 3 more, and now he has 8 oranges. How many oranges did Antony have at first?

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5 oranges
 

Explanation

To find the number of oranges he had at first, we can apply this equation:
x + 3 = 8
To find the value of x, subtract 3 from both sides:
x + 3 - 3 = 8 - 3
x = 5. 
 

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Problem 3

Donald had 15 toys. He gave some of his toys to his friend and now has 7 toys left. How many did he give away?

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9 toys.
 

Explanation

To find the value of x we can apply this equation:
x = 15 - 7
X = 8. Donald gave 8 toys to his friend. 
 

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Problem 4

A shop has x cakes in each row. There are 4 rows, and in total, there are 20 cakes. How many cakes are in each row?

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Each row has 5 cakes.
 

Explanation

To find this, we can use the equation:
4x = 20
Now, we have to divide both sides by 4:
x = 20 ÷ 4 
x = 5.
Each row has 5 cakes. 
 

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Problem 5

Lora has 30 flowers. She shares them equally with 5 friends. How many flowers does each of her friends get?

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 Each of Lora’s friends gets 6 flowers.
 

Explanation

30  ÷ x = 5
Let us multiply both sides by x:
30 = 5x
Now, we can divide 5 by both sides:
30 ÷ 5 = x
x = 6
Each friend gets 6 flowers. 
 

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FAQs on Algebraic Equations

1.What is an algebraic expression?

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2.What do you mean by algebraic equation?

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3.Define variable.

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4.What are the different types of algebraic equations?

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5.What is the general form of an algebraic equation?

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6.Define the linear equation.

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7.What are the real-life applications of algebraic equations?

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8.What do you mean by a coefficient?

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9.Define an inverse operation.

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10.What is a constant in an algebraic equation?

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11.How does learning Algebra help students in United States make better decisions in daily life?

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12.How can cultural or local activities in United States support learning Algebra topics such as Algebraic Equations ?

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13.How do technology and digital tools in United States support learning Algebra and Algebraic Equations ?

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14.Does learning Algebra support future career opportunities for students in United States?

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