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Last updated on October 16, 2025
An nth degree polynomial refers to a polynomial whose variable has the highest power of n and can have up to n roots. Its standard form ends with a constant and lists terms in decreasing order of exponents.
The greatest power of the variable in a polynomial is known as its degree. Therefore, any polynomial with the highest power of the variable of n is a nth degree polynomial. Thus, the polynomial is in the following form:
P(x)=anxn+an-1xn-1+an-2xn-2+...+a0
It is a real-coefficient, nth degree polynomial function with the variable denoted by x and the highest power n.
For example, expressions such as √x+2x+7 are not polynomials because the variable x has a fractional exponent, and all of the exponents in a polynomial must be whole numbers. The coefficients, such as an, an-1, an-2, ...., a0 are the constants that multiply the variable terms. This is also the standard method of representing various types of polynomials, and their coefficients an, an-1, an-2,...,a0, and the power n can have numerical values depending on the types of polynomials they represent.
The degree of a polynomial in one variable is the highest power of the variable in the polynomial. It is said to be the highest exponent value of the variable in the given polynomial.
Example:
Degree of (x4+4x2+3x)=4
Degree of (x)=1
Degree of (x2+2x+1)=2
What is the Degree of a Polynomial with More than One Variable
When a polynomial contains multiple variables, we find the degree of each term by adding the powers of each variable that is present in the term.
In other words, to find the degree of a polynomial having more than one variable, add the exponents in each term, this gives you the degree of that term. After adding exponents, the exponent of the term having the highest exponent is considered as the degree of that polynomial,
For example, 5x5+4xy2+3xy
5x5 is 5, is the degree of the term.
The degree of 4xy2 is 3 (Sum of exponents = 1+2=3)
The term 3xy has a degree of 2 (Sum of exponents =1+1=2)
5 is the highest degree. Therefore, the polynomial’s degree is 5
Combine all like terms (terms with the same variables and exponents) before determining the degree. This simplifies the polynomial. Then the highest exponent determines the degree of the polynomial.
Finding a polynomial’s degree with one variable
Step 1: Write the polynomial expression in the correct form. The correct form of a polynomial refers to arranging the terms in descending order of the degrees.
Step 2: Find which term has the variable’s highest power. The coefficient of this term must be non-zero. The leading term in the correct form is said to be the one with the highest power.
Step 3: The polynomial’s degree is the same as the highest power term’s degree.
For example, 7x3+5x2-3x-4x3+2-3x3
When we combine similar terms, we obtain
p(x)=(7x3-4x3-3x3)+5x2-3x+2
p(x)=5x2-3x+2... the term x3 is eliminated due to the 0 coefficient.
The standard form of this expression already exists.
The term with the highest power of x in this case is 5x2
Therefore, the polynomial’s degree is 2.
Degree of Zero Polynomial
The expression p(x)=0 or the number 0 is typically used to represent the zero polynomial. Non-zero terms do not exist in the zero polynomial. A polynomial that has zero coefficients is referred to as a zero polynomial. There are no terms with coefficients that are not zero.
Why is the degree of zero polynomial regarded as undefined? We can rewrite p(x)=0 as p(x)=0.xn
p(x)=0.x1
p(x)=0.x2
p(x)=0.x3
…
As a zero polynomial doesn’t have any non-zero terms, its degree is undefined.
Zeros of Nth Degree Polynomial
The values of a variable for which the nth degree polynomial equals zero are known as their zeros. There is a maximum of n zeros in a polynomial of degree n. These zeros might be complex or real.
For example,
The zeros of x3-6x2+11x-6=0 are:
x=1, 2, 3
The zeros of x2+4=0 are:
x=2i,-2i(complex)
The zeros of x4=0 are:
x=0 (with multiplicity 4)
Let us see how nth degree polynomials help in real life.
Let us look at the common mistakes students make when working with nth degree polynomials, and let's see how to avoid them.
Find the zeros of the polynomial f(x)=x3-6x2+11x-6
f(x)=(x-1)(x-2)(x-3)
To verify that 1 is a zero, we first attempt to substitute x = 1 into the polynomial, resulting in f(1)=1-6+11-6=0. Here, the quotient x2-5x+6 is now obtained by using long division or synthetic division method to divide the polynomial by (x - 1). Another way to factor this quadratic is as (x - 2)(x - 3). Thus, the zeros are x = 1, 2, and 3, and the polynomial can be expressed as (x - 1)(x - 2)(x - 3).
Find the zeros of the polynomial f(x)=x3+2x2-x-2
f(x)=(x-1)(x+1)(x+2)
We consider x = 1 is a zero. We can verify that x = 1 is a zero by substituting, which results as 1+2-1-2=0. The quotient x3+3x+2 is obtained by dividing the polynomial by (x - 1). This quadratic can be factored to get (x + 1)(x + 2). Therefore, the zeros will be x = -2, -1, and 1, and the polynomial’s full factorized form is (x - 1)(x + 1)(x + 2).
Find the zeros of the polynomial f(x)=x3-2x2-5x+6
f(x)=(x-1)(x-3)(x+2).
We verify that this x = 1 is a zero by testing it and substituting it into the polynomial: 1-2-5+6=0. Here, the polynomial is then divided by (x - 1) to get x2-x-6. (x - 3)(x + 2) where the result of factoring x2-x-6. Thus, the zeros are x = -2, 1, and 3, and the polynomial’s complete factorization is (x - 1)(x - 3)(x + 2).
Find the zeros of the polynomial f(x)=x3+3x2-4x-12
f(x)=(x-2)(x+2)(x+3)
We test x = 2. Since 8+12-8-12=0 is obtained by substitution, x = 2 is a zero. The quotient obtained by dividing the polynomial by (x - 2) is x2+5x+6. This quadratic can be factored to get (x + 2)(x + 3). As a result, the zeros are x = -3, -2, and 2, and the polynomial’s fully factorized form is (x - 2)(x + 2)(x + 3).
Find the zeros of the polynomial f(x)=x4-5x2+4
f(x)=(x-2)(x+2)(x-1)(x+1).
Since this polynomial appears to be quadratic in form, we change it to y=x2, which results in the expression y2-5y+4. y = 1 or y = 4 can be obtained by solving the quadratic equation y2-5y+4=0. We now return x2=1 and x2=4. The results of solving these are x = ±1 and x = ±2. Thus, x = -2, -1, 1, and 2 are the polynomial’s four zeros.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.