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115 LearnersLast updated on October 30, 2025

A pair of complex numbers that, when squared, give the original complex number, is known as a square root of a complex number. The square root of a complex number(a + ib) is expressed as √(a + ib) = ±(x + iy), where x and y are real numbers. We will explore more about the square root of complex numbers in this article.
Complex numbers consist of two parts, namely a real number and an imaginary part. The number on the number line is the real number, and the imaginary unit is the multiple of i, where i = √-1.
The general form of the complex number is z = a + bi,
where
i2 = -1. 3 + 2i, -5 - 4i are examples of complex numbers.
The square root of a complex number is another complex number that, when squared, gives the original complex number. If the square root of a complex number is √(a + ib) = ±(x + iy), then (x + iy)2 = a + ib.
The simplest way to find the square root of a complex number in the form of x + iy, square it, and then compare the real and imaginary parts to determine the values of x and y.
Rectangular to Polar Form:
Modulus (r) = √(a2 + b2)
Argument (θ) = tan-1ba
Polar to rectangular Form:
Real part (a) = r × cosθ
Imaginary part (b) = r × sinθ
The Square root of a complex number is found in a pair, similar to the square root of real numbers. When either of these values is squared, the result is the original complex number.
The general representation of the square root of (x + iy) is:
\(√(x + iy) = ±[√(√(x2 + y2) + √x2) + i.y/|y|. √(√(x2 + y2) - √x2)] \ or \ \\ √(x + iy) = ±[√(|z| + √x2) + i.y/|y|. √(|z| - √x2)]\)
Here, z = x + iy and y ≠ 0
A complex number can be written in polar form as:
z = r(cosθ + isinθ)
Where
To find the nth root of z, we use:
\(z1/2 = r1/ncos θ + 3600kn + isin θ + 3600k n\\ \ Or\ \\ z1/2 = r1/ncos θ + 2kn + isin θ + 2k n\)
Here, k = 0, 1, 2, …, n - 1, which means n has different roots.
For the square root (when n = 2), the formula becomes:
\(z1/2 = r1/2cos θ + 3600k2 + isin θ + 3600k 2\\ \text{Or in radians:} \\ z1/2 = r1/2cos θ + 2k2 + isin θ + 2k 2\)
Where k = 0 or 1 because a square root always has two values.
If a complex number is written in polar form as:
z = r(cosθ + isinθ)
Then the n-th roots of z are given by:
\(z^k = r^{1/n} [cos ({θ + 2\pi k \over n}) + isin({ θ + 2k \over n})]\)
Here,
Finding the square root of a complex number z = a + ib can be done in two easy ways: using the direct formula or using the polar form. Given below are the tips to remember.
1. Using the Direct Formula:
The direct formula is quicker if we already know the values of a and b.
Write z = a + ib, where a is the real part and b is the imaginary part.
The modulus is |z| = a2 + b2
Use the formula:
a + ib = |z| + a2 + i b|b||z| - a2
2. Using Polar Form:
Polar form is better when you know the modulus and angle, or want to see the geometric meaning.
Convert z = a + ib into a polar form:
z = r(cosθ + isinθ)
where, r = |z| and θ = tan-1(ba)
Use the formula:
\(z^{1/2} = r^{1/2}[cos ((θ + 2k)/ 2) + isin ((θ + 2k)/ 2)]\)
With k = 0, 1, to get the two roots.
When finding the square root of complex numbers, students often make an error that leads to incorrect answers. Here are some of the common mistakes and the ways to avoid them helps them.
The concept of square roots of complex numbers is widely used in various scientific and engineering fields. It often appears when solving differential equations, calculating impedances in electrical circuits, or when analyzing wave functions. Given below are some of the real-life applications and how they are used.
Find the square roots of -9.
-9 = 3i
We know -9 is a negative real number.
Since i = -1
The square root of -9 is:
-9 = 9 × -1 = 3i
Include both roots: + 3i and - 3i
Find the square root of 2i
2i = (1 + i)
Let z = 0 + 2i
Here, a = 0 and b = 2
So, 2i = 2cos π2 + i sin π2
z = 2i = r[cos π4 + isinπ4
= 2 12 + i12
= 1 + i
Find the square root of -4
-4 = 2i
We know that -4 is negative, so it will have an imaginary root.
-4 = 4 × -1 = 2i
The answers are: ± 2i.
Find the square root of 4i
4i = (2+ 2i)
4i = 4[cos 450 + isin450]
4 = 2, cos 450 = sin 450 = 2 2
Find the square root of -1.
-1 = i
We know -1 = -1 × 1
By definition, i = -1
The square root of -1 is defined as i.
So, the two roots are + i and -1.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.






