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108 LearnersLast updated on October 24, 2025

The arrangement of binomial coefficients in a triangular form is known as Pascal’s Triangle. It is named after the French mathematician Blaise Pascal. Pascal's triangle is widely used in combinations, algebra, and probability theory. In this article, we will learn more about Pascal’s triangle, its construction, pattern, and applications.
Pascal’s triangle is an arrangement of numbers in a triangular pattern. It is an infinite array of numbers arranged in rows, and each row corresponds to the coefficients found in the expansion of a binomial.
It begins with 1, and each entry is obtained by adding the two numbers directly above it from the previous row.
Each entry in Pascal’s triangle can also be found using the binomial coefficient triangle formula:
kn = n!/k! (n - k)!, where n is the row number and k is the position in the row.
For constructing Pascal’s triangle, follow the steps given below:
Step 1: Begin the table with 1. The first row consists of only 1.
Step 2: To draw each new row, increment the start and end by 1. Each interior number is the sum of the two numbers directly above it. For example, 1 + 1 = 2, 2 + 1 = 3, etc.
Step 3: Repeat the same process to create as many rows as you want, as shown below.
Pascal's Triangle Binomial Expansion
Pascal’s triangle provides the coefficients in the expansion of a binomial expression. For example, (x + y)2 expands to x2 + 2xy + y2. The numbers 1, 2, 1 are taken from the second row of Pascal’s triangle. The same rule works for higher powers, so you can quickly find coefficients without expanding each term manually.
Pascal’s triangle gives us the number we need for the binomial expression of (x + y)n. We can calculate (x + y)n using,
(x + y)n = a0xny0 + a1xn-1y1 + a2xn-2y2 + … + an - 1x1yn - 1 + anx0yn.
The coefficients a0, a1, a2, etc., come from row n of Pascal’s triangle.
In probability, Pascal’s triangle is used to find the number of combinations. It helps us find out how many ways something can happen.
If we are flipping two coins, the possible outcomes are HH, HT, TH, and TT. Now, let us count how many times we get those chances.
1 head: TH, HT (2 possible ways)
2 heads: HH (1 possible way)
Now we get the chances as: 1, 2, 1, which matches the 2nd row of Pascal’s triangle.
0 head: TTT (1 way)
1 head: HTT, THT, TTH (3 ways)
2 heads: HHT, HTH, THH (3 ways)
3 heads: HHH (1 way)
So we get 1, 3, 3, 1, which is the third row in Pascal’s triangle.
Pascal’s triangle has various patterns; a few of the patterns are explained below.
The sum of the values in the n row is equal to 2n. Here, ‘n’ represents the row index starting from row 0.
Row 0: 1 = 20 = 1
Row 1: 1 + 1 = 21 = 2
Row 2: 1 + 2 + 1 = 22 = 4
Row 3: 1 + 3 + 3 + 1 = 23 = 8
Row 4: 1 + 4 + 6 + 4 + 1 = 24 = 16
In Pascal’s triangle, if the second number in a row is a prime, then every number between the two 1s in that row is divisible by that prime.
Example:
Row 5: 1, 5, 10, 10, 5, 1
Here, 5 is a prime number, and all the numbers between the 1s are divisible by 5.
When we add the numbers in a diagonal slanting down to the left, we will get a Fibonacci series.
1
1
1 + 1 = 2
1 + 2 = 3
1 + 3 + 1 = 5
1 + 4 + 3 = 8
1 + 5 + 6 + 1 = 13 and so on.
Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21,...
Other diagonal patterns: Pascal’s triangle contains several diagonal patterns, such as:
The first diagonal is 1s.
The second diagonal is the counting numbers 1, 2, 3,...
The third diagonal is the triangle numbers 1, 3, 6, 10, 15,...
Pascal’s Triangle is a fascinating number pattern that not only helps in combinatorics but also in algebra, probability, and number theory. Here are some useful tips and tricks for students to easily understand Pascal’s triangle.
Mistakes are common when working with Pascal’s triangle. Here are some of the common mistakes and the ways to avoid them in Pascal’s triangle.
Pascal’s triangle is used to solve many problems. Below are some applications of Pascal’s triangle across various fields.
What is the 5th row of Pascal’s triangle?
1, 5, 10, 10, 5, 1
Pascal's Triangle starts from row 0,
The 5th row of Pascal’s triangle is: 1, 5, 10, 10, 5, 1
Expand (x + y)3 using Pascal’s triangle.
x3 + 3x2y + 3xy2 + y3
Use row 3 of Pascal's triangle: 1, 3, 3, 1.
Use the coefficients for: x3, x2y, xy2, y3
So, (x + y)3 = x3 + 3x2y + 3xy2 + y3
Show how to find the Fibonacci number 5 in Pascal’s Triangle.
1 + 1 + 3 = 5
Fibonacci numbers can be formed by adding the slanted diagonals.
Start adding from the left edge, move diagonally downward left.
1
1
1 + 1 = 2
1 + 2 = 3
1 + 3 + 1 = 5
What is the sum of the numbers in the 7th row of Pascal’s triangle?
128
The sum of the numbers in the 7th row of Pascal’s triangle is:
Row 7: 1, 7, 21, 35, 35, 21, 7, 1
Now add the numbers: 1 + 7 + 21 + 35 + 35 + 21 + 7 + 1 = 128
This matches with,
27 = 2 × 2 × 2 × 2 × 2 × 2 ×2 = 128
Therefore, the sum of the 7th row is 128, which is equal to 27.
Given row 5 = 1, 5, 10, 10, 5, 1, find the 6th row?
1, 6, 15, 20, 15, 6, 1
Each inner number is the sum of the two numbers above. So,
1 (edge)
1 + 5 = 6
5 + 10 = 15
10 + 10 = 20
10 + 5 =15
5 + 1 = 6
1 (edge)
Therefore, row 6 = 1, 6, 15, 20, 15, 6, 1
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
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