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Last updated on September 29, 2025

Polynomial Identity

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The mathematical expressions or equations involving polynomials that hold for all values of the variables are the polynomial identities. The polynomial identities are used to simplify the expressions and solve the equations. In this article, we will explore polynomial identities, their types, formulas, and methods for proving these identities.

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What are Polynomial Identities?

Polynomial identities are algebraic expressions involving polynomials that are true for all values of the variables. These identities are used to simplify complex expressions and solve equations efficiently. A polynomial can include one or more variables, each raised to a positive integer power. Polynomial identities are equations that remain valid for all values of the variables involved.

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What Are the Types of Polynomial Identities?

Polynomial identities can be classified into different types based on the degree of the polynomials. The main types of polynomial identities are:

 

  • Second Degree Polynomial Identities 

 

  • Third Degree Polynomial Identities 

 

  • n-Degree Polynomial Identities 
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Second-Degree Polynomial Identities:

The polynomial identities have the highest degree of two. The second-degree polynomial identities are:

 

  • (a + b)2 = a2 + 2ab + b2
     
  • (a - b)2 = a2 - 2ab + b2
     
  • (a + b + c)2 = a2 + b2 + c2 + 2ab + 2bc + 2ca
     
  • (a - b - c)2 = a2 - b2 - c2 - 2ab + 2bc - 2ca
     
  • (x + a)(x + b) = x2 + (a + b)x + ab
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Third-Degree Polynomial Identities:

The third-degree polynomial identities include the polynomials with the highest degree of 3. Some examples of third-degree polynomial identities are:

 

  • (a + b)3 = a3 + b3 + 3ab(a + b)
     
  • (a - b)3 = a3 - b3 - 3ab(a - b)
     
  • a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ca) 
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n-Degree Polynomial Identities:

The polynomial with the highest power of the variable n is the n-degree polynomial. The formula for all n-degree polynomial identities is:

 

If n is a natural number: 

an - bn = (a - b)[(an - 1) + (an - 2)b + … + (bn - 2)a + (bn - 1)]

 

If n is an even number (n = 2k):

an + bn= (a + b)[(an - 1) - (an -2 )b + …. + (bn - 2)a - (bn - 1)]

 

If n is an odd number (n = 2k + 1)

an + bn = (a + b)((an - 1) - (an - 1) - (an - 2)b + …. - (bn - 2)a + (bn - 1))

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What are the Formulas for a Polynomial?

The polynomial identities are used to solve, simplify, and expand the polynomial expressions. Here are some formulas for polynomials:

 

  • a2 - b2 = (a + b)(a - b)

 

  • a3 - b3 = (a - b)(a2 + ab + b2)

 

  • a3 + b3 = (a + b)(a2 - ab + b2)

 

  • a4 - b4 = (a+ b)(a - b)[(a + b)2 - 2ab]

 

  • 2(a2 + b2) = (a + b)2 + (a - b)2

 

  • (a + b)2 - (a - b)2 = 4ab
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How to Prove Polynomial Identities

Now, let’s learn how to prove some commonly used polynomial identities. By learning these, students can easily understand how these identities work. In this section, we will learn the proofs for the given identities:

 

  • (a + b)2 = a2 + 2ab + b2 
     
  • (a - b)2 = a2 - 2ab + b2
     
  • (a + b)(a - b) = a2 - b2
     
  • (x + a)(x + b) = x2 + x(a + b) + ab

 

Identity 1: (a + b)2 = a2 + 2ab + b2 

Expanding the expression using distributive property: (a + b)2 = (a + b) × (a + b)
= a2 + ab + ba + b2 

ab = ba, since multiplication is commutative 
= a2 + 2ab + b2

Therefore, (a + b)2 = a2 + 2ab + b2 

 

Identity 2: (a - b)2 = a2 - 2ab + b2

Using distributive property to prove (a - b)2 = a2 - 2ab + b2

So, (a - b)2 = (a - b)(a - b)

= a2 - ab - ba + b2 

= a2 - 2ab +b2, as ab = ba

Thus, (a - b)2 = a2 - 2ab + b2

 

Identity 3: (a + b)(a - b) = a2 - b2

To multiply two expressions, we use the distributive property. 

That is a(a - b) + b(a - b) = a2 - ab + ab - b2
= a2 - b2

So, (a + b)(a - b) = a2 - b2

 

Identity 4: (x + a)(x + b) = x2 + x(a + b) + ab

To prove (x + a)(x + b) = x2 + x(a + b) + ab

We expand, (x + a)(x + b) using the distributive property:
(x + a)(x + b) = x2 + xa + xb + ab

Factoring out the common term (x) from xa + xb
So, x2 + xa + xb + ab becomes:

x2 + x(a + b) + ab

Hence, proved (x + a)(x + b) = x2 + x(a + b) + ab

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How to Solve Questions Faster Based on Polynomial Identities?

Students usually find problems involving polynomial identities difficult, but these identities are used in various ways to simplify and solve polynomial expressions. Here are a few tips to solve polynomial equations. 

 

Tip 1: When solving a problem, first check what information is given and what the question is asking for. This helps students identify the identity to be used.

 

Tip 2: Next, identify the degree of the equation and check for the related identities. For example, if the degree of the equation is 3, check for the identities related to the third-degree polynomial. 

 

Tip 3: After identifying the identity, substitute the values of the variable in the identity and solve the expression. 

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Real-World Applications of Polynomial Identity

Polynomial identities are used in different fields like computer science, physics, engineering, etc. Here are some applications of the polynomial identity 

 

  • In computer graphics and animation, the polynomial identities are used to model curves, shapes, and animations. 

 

  • In finance, to calculate compound interest and investment growth, we use polynomial identities. For example, the identity (1 + r)2 is used to calculate compound interest. 

 

  • In construction, to estimate the cost or area when adding extra units to the base plan, we use polynomial identities. 

 

  • In mathematics, to factor equations, find the roots of quadratic equations, simplify expressions, and solve systems of equations, we use polynomial identities. 
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Common Mistakes and How to Avoid Them in Polynomial Identity

When using the polynomial identities, students often make mistakes. In this section, we will learn some common mistakes and tips to avoid them in polynomial identities. 

Mistake 1

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Confusing polynomial identity with polynomial equation

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Students confuse polynomial identities with polynomial equations. To avoid confusion, students should understand what a polynomial identity and equation are. The polynomial identities are always true for all values of the variables, while polynomial equations have specific solutions.

Mistake 2

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Assuming (a + b)2 = a2 + b2

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Ignoring the middle term when expanding the binomial expression is common among students.

 

For example, assuming (a + b)2 = a2 + b2 instead of a2 + 2ab + b2. So, when expanding the binomials, always use the distributive property. 

Mistake 3

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Applying the wrong identity

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Using the wrong identity is a common error among students;

 

For example, using (a + b)3 to expand (x + 2)2 can lead to an error. So, always identify the correct polynomial structure before using the identities.

Mistake 4

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Confusing a3 + b3 with (a + b)3

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Students often assume that a3 + b3 = (a + b)3, but it is wrong as a3 + b3 = (a + b)(a2 - ab + b2). To avoid confusion, students should memorize a few polynomial identities and use them based on their structures.

Mistake 5

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Sign errors while simplification or expanding the identities 

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A common error students make when simplifying or expanding the identities or expressions is a sign error, especially in (a - b)2 and (a - b)3. To avoid confusion, always give special attention to negative signs. 

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Solved Examples on Polynomial Identity

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Problem 1

Expand (3x - 2)²

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(3x - 2)2 = 9x2 - 12x + 4

Explanation

using the identity (a - b)2 = a2 - 2ab + b to expand (3x - 2)2

Here, a = 3x and b = 2

So, (3x - 2)2 = (3x)2- (2 × 3x × -2) + (-2)2

= 9x2 -12x + 4

So, (3x - 2)2 = 9x2 -12x + 4

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Problem 2

Simplify (a + b)(a - b)

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(a + b)(a - b) = a2 - b2

Explanation

Using distributive property to simplify (a + b)(a - b)

(a + b)(a - b) = a2 - ab + ba - b2

As -ab + ba = 0

(a + b)(a - b) = a2 - b2

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Problem 3

Factor 8x³+ 27

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8x3 + 27 = (2x + 3)(4x2 - 6x + 9)

Explanation

As 8x3 + 27 is the sum of a cube, it can be expressed as:

8x3 + 27 = (2x)3 + 33

As the expression is in the form a3 + b3, we use the identity a3 + b3
= (a + b)(a2 - ab + b2)

Here, a = 2x and b = 3

So, (2x)3 + 33 = (2x + 3)((2x)2 - (2x × 3) + 32)

= (2x + 3)(4x2 - 6x + 9)

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Problem 4

Factor x² - 49

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x2 - 49 = (x +7)(x - 7)

Explanation

Here, x2 - 49 is in the form a2 - b2

a2 - b2 = (a + b)(a - b)

Here, a = x 

b2 = 49, so b = 7

So, x2 - 49 = x2 - 72

= (x + 7)(x - 7) 

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Problem 5

Expand (x - 2)(x + 2)

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(x - 2)(x + 2) = x2 - 4

Explanation

Here, (x - 2)(x + 2) is in the form a2 - b2 = (a + b)(a - b)

Here, a = x and b = 2

So, (x - 2)(x + 2) = x2 - 4

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FAQs on Polynomial Identity

1.What is a polynomial identity?

Polynomial identities are equations that hold for every value of the variables they involve. It is used to solve polynomial expressions.

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2.What are polynomials?

Polynomials are mathematical expressions or equations that are made up of variables, constants, and exponents, which are combined using the arithmetic operations. 

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3.What are the types of polynomial identities?

There are various types of polynomial identities, including second-degree polynomials, third-degree polynomials, and n-degree polynomials. 

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4.What is the difference between polynomial identities and polynomial equations?

The polynomial identities are expressions that are always true for all values of the variables, and the polynomial equations are expressions that are only true for specific values. 

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5.List a few polynomial identities.

A few polynomial identities are:

 

  • (a + b)2 = a2 + 2ab + b2 

 

  • (a - b)2 = a2 - 2ab + b2

 

  • (a + b)(a - b) = a2 - b2

 

  • (x + a)(x + b) = x2 + x(a + b) + ab

 

  • (a + b)3 = a3 + b3 + 3ab(a + b)

 

  • (a - b)3 = a3 - b3 - 3ab(a - b)

 

  • a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ca) 

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