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Last updated on September 29, 2025

Quadratic Inequalities

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A quadratic inequality compares a quadratic expression ax² + bx + c (where a ≠ 0) to zero using >, <, ≥, ≤ signs. They allow us to analyze intervals between roots and help determine if a given condition holds. Students should rewrite the inequality in standard form for solving, find the roots of ax² + bx + c = 0, and test sign intervals.

Quadratic Inequalities for US Students
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What are Quadratic Inequalities?

A quadratic inequality involves comparing a quadratic expression ax2 + bx + c, where a ≠ 0 to a number or another polynomial (degree ≤ 2), using >, <, ≥, or ≤. Unlike a quadratic equation (which equals something), inequalities yield ranges of solutions. Examples are:

 

  • x2 + x − 1 > 0

 

  • 2x2 − 5x − 2

 

  • x2 + 2x − 1 < 0
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What are the Types of Quadratic Inequalities?

Quadratic inequalities compare a quadratic expression to zero, using inequality symbols: greater than, less than, greater than or equal to, and less than or equal to. They are solved by finding roots and testing the signs of the expression over different intervals.

 

Type General Form Name
Standard ax2 + bx + c ≷ 0 Positive/Negative/0m/0
No real roots <0 Always positive or negative
Repeated roots =0 Touches the x-axis once
Factored (simple/repeated) (x - a)(x - b) . . .≷0 Linear and repeated linear factors
Rational P(x)/Q(x)≷ 0 Rational quadratic inequalities
Compound quad ≷ m quad Two-sided/bounded inequality
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How To Solve Quadratic Inequalities

Step 1 -  Rewrite the equation to express the inequality:

Example: x2 − 5x + 6 > 0.

 

Step 2 - Find roots by factoring or formula:

(x−2)(x−3)>0 → roots: 2, 3.

 

Step 3 - Create intervals:

(−∞,2),  (2,3),  (3,∞).

 

Step 4 - Test each interval by plugging in a sample value:

  • x = 0: positive → true
     
  • x = 2.5: negative → false
     
  • x = 4: positive → true

 

Step 5. Write a solution:

All x∈ (−∞,2)  (3,∞).

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Notations Used In Quadratic Inequalities.

The symbols > and < (greater than, less than) replace “=” in a quadratic equation to form a quadratic inequality. The format is
ax² + bx + c > 0   or   ax² + bx + c < 0.

 

  • ( ) → Open brackets

 

  • [ ] → Closed brackets

 

  • o → Open value (x cannot take this value)

 

  • • → Closed value (x can take this value)

 

Examples:

  • (-1, 1) → x cannot take -1 and 1

 

  • [-1, 1) → x can take -1 but not 1

 

  • (-1, 1] → x cannot take -1 but can take 1

 

  • [-1, 1] → x can take both -1 and 1
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What are the methods to solve Quadratic Inequalities?

Different methods used to solve quadratic inequalities are listed below:

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Factoring + Test Intervals

  1. Rewrite as ax² + bx + c ≷ 0.
     
  2. Factor & find roots.
     
  3. Divide the number line into intervals.
     
  4. Test each interval.

 

Example:

X2 − 5x + 6 > 0  ⟹  (x − 2)(x − 3) > 0

(−∞,2), (2,3), (3,∞).

 

Testing the values in the expression, we get, x = 0: true; x = 2.5: false; x = 4: true.

Solution: x∈(−∞,2)∪(3,∞).

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Sign Chart (“Wavy Curve” Method)

  1. Factor the expression.
     
  2. Mark the roots on a number line.
     
  3. Determine the sign of each factor in each region (alternating sign from rightmost interval).
     
  4. Combine to find where the product matches the inequality.

 

Example:

(x − 3)(x + 2) < 0.

x - 3 = 0, x = 3

x + 2 = 0, x = -2

 

So, the expression changes sign between x = -2 and x = 3

Now, set intervals using roots to divide the number line:

(-∞,-2), (-2,3), (3,∞)

Test each interval

x = -3: (x - 3) (x + 2) = (+)

x = 0: (x - 3) (x + 2) = (-)

x = 4: (x - 3) (x + 2) = (+)

 

The only region where the expression is negative is (-2, 3).
So, x∈(-2,3)

Solution: x∈(-2,3)

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Graphical Method

  1. Rewrite as y = ax2 + bx + c and y ≷ 0.
     
  2. Sketch the parabola (upwards if a>0, down if a<0)
     
  3. Read off where the parabola is above/below the x-axis.

 

Example:

x2 + 5x + 6 ≥ 0.

The graph crosses at x = −2 and −3 and opens upward since the linear coefficient is positive.

So, the expression is ≥ 0 outside [−3,−2].

Solution: x∈(−∞, −3]∪[−2,∞).

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Real-Life Applications of the Quadratic Inequalities

The quadratic inequalities model helps us understand and solve real-world problems in the fields of physics, engineering, economics, and biology. Some of its applications are listed below:

 

  • Bridge design: This is useful to ensure the structural integrity of bridges. For example, civil engineers need to examine the maximum load a bridge can bear to determine the range of weight distribution that is safe. This helps in preventing breakdown.

 

  • Profit Margins in Business: Businesses use Quadratic Inequalities for modelling and analyzing the business profit margins. For example, a company uses it to decide the range of product prices that will create a desired profit level.

 

  • Radio Telescope Design: Radio telescopes use parabolic mirrors to focus incoming radio waves. This helps design the shape and dimensions of these mirrors to ensure optimal signal reception and focusing. 

 

  • Determining Safe Speed: This is useful in transportation, as it helps to find the Maximum safe speed on a curved and dangerous road map. Making sure that the vehicle can navigate the curve without skidding or losing control.

 

  • Area Calculation: This can be used to find the dimensions of a shape, like a rectangle, that meets a specific area requirement. For example, to find the dimensions of a garden or a plot that has the minimum required area.
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Common Mistakes of the Quadratic Inequalities and How to Avoid Them

Quadratic inequalities are challenging for some students, and common mistakes can create incorrect answers. Recognizing and avoiding these errors is important for perfect problem-solving.

Mistake 1

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Students don't flip the inequality sign while multiplying/dividing by a negative.

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When multiplying or dividing by a negative number, students should always flip < to >. They should reverse the inequality direction because it preserves the true inequality.  

 

Example: −2x > 4-. Divide by −2 → flip sign → x < −2.

Mistake 2

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Testing at boundary (root) points

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Plugging in roots gives zero, not the correct sign. To avoid this, we need to choose test values inside intervals between roots.

 

For example, (x − 1)(x − 3) > 0.

Roots are x = 1 and x = 3

The intervals are (−∞,1), (1,3), (3,∞)

 

Test values;

x = 0 → (0 − 1)(0 − 3) = (+)

x = 2 → (2 − 1)(2 − 3) = (−)

x = 4 → (4 − 1)(4 − 3) = (+)

 

The inequality is true in x∈(−∞,1)∪(3,∞)

Mistake 3

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Misunderstanding the parabola direction

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Wrong sign assumption based on parabola orientation, to avoid this, we need to follow that if a > 0, the parabola opens up → positive outside roots; if a < 0, the opposite.

 

For example, x2 − 5x + 6 > 0. Since a = 1 > 0, the solution is x < 2 or x > 3.

Mistake 4

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Wrong endpoint inclusion

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While solving, students use open intervals while inequality is ≤ or ≥, for a clear result, we can also use closed brackets, also filled dots for ≤/≥, open for < or >.

 

For example, x2 − 4x + 3 ≤ 0 → (x − 1)(x − 3) ≤ 0 → solution is [1, 3].

Mistake 5

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Ignoring discriminant (Δ) = no real roots

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Assuming that roots do not exist when Δ < 0 is incorrect. The quadratic has complex roots that are complex or not real and do not exist on the number line. For real number inequalities, if Δ < 0, the quadratic expression never crosses the x-axis. If a > 0, the expression will always be positive, and if a < 0, the expression will always be negative.

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Solved Examples of the Quadratic Inequalities

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Problem 1

For which values of x is x² − 4x + 3 > 0?

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x∈ (-∞,1) ∪ (3,∞).

Explanation

(x - 1)(x - 3) 3 > 0. Roots: x = 1, 3.

 

(-∞,1), (1,3), (3,∞).

 

x = 0: (0 - 1)(0 - 3) = (-1)(-3)  3 > 0, true

 

x = 2: (2 - 1)(2 - 3) = 1 · (-1) = -1 > 0, false

 

X = 4: (4 - 1)(4 - 3) = 3·1 = 3 > 0, true

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Problem 2

Solve x² + 2x − 15 ≤ 0.

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−5 ≤ x ≤ 3.

Explanation

Factor to (x + 5)(x − 3).

 

The quadratic is non-positive between the roots.

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Problem 3

Determine x such that 3x² − 12 ≤ 0.

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−2 ≤ x ≤ 2

Explanation

Rewrite as 3(x2 − 4) ≤ 0.

 

Hence, −2 ≤ x ≤ 2.

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Problem 4

Find all x satisfying 2x²+ 7x + 6 < 0

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−2 < x < −3/2

Explanation

Factor (2x + 3)(x + 2) < 0.

 

The product is negative between the roots: −2 < x < −1.5.

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Problem 5

Solve 4x² − 4x+ 1 ≥ 0.

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All real x.

Explanation

This is (2x − 1)2, which is always ≥ 0 for every x.

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FAQs of the Quadratic Inequalities

1.What is a quadratic inequality?

A quadratic inequality is an inequality involving a quadratic expression, such as ax2 + bx + c, where the inequality symbol is <, ≤, >, or ≥.

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2.How do I solve a quadratic inequality?

To solve, factor the quadratic expression, find the roots, determine intervals, test points within those intervals, and identify where the inequality holds.

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3.What is the significance of the sign of a in ax² + bx + c?

The sign of a determines the direction of the parabola: if a > 0, it opens upwards; if a < 0, it opens downwards.

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4.How do I handle strict inequalities < or >?

For strict inequalities, the solution does not include the boundary points; use open intervals to represent the solution set.

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5.How do I express the solution set?

Solution sets can be expressed in interval notation, such as (−∞,−3)∪(2,∞), or in set-builder notation.

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