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137 LearnersLast updated on October 23, 2025

The adjoint (or adjoint) of a square matrix is a fundamental concept in linear algebra. It is also called the transpose of the cofactor matrix of the given matrix. The adjoint of a matrix plays a very important role in calculating its inverse, provided the matrix is invertible. This concept is essential for solving systems of linear equations and analyzing matrix properties
The adjoint of a square matrix is a core concept used in various applications, like solving systems of linear equations and computing matrix inverses.
This concept is fundamental in linear algebra and has applications in solving systems of linear equations and matrix theory.
The adjoint or adjugate of a matrix is the transpose of the matrix of the corresponding cofactors. It is used for calculating the inverse of a matrix. Here, we will be learning the properties of adjoint of a matrix:
These properties are fundamental in matrix theory and solve linear equations, computing determinants, and finding inverses of matrices.
The following chart gives the properties of adjoint of a matrix in a structured table:
The adjoint of a square matrix is a new matrix that assists us in finding the inverse of the original matrix. To find the adjoint of a matrix, we follow these steps:
Hence, for every square matrix A of order n × n, the adjoint of A, indicated as adj(A), is given by:
\(Adj(A) = [Cofactor(A)]^T\)
The minor of an element in a matrix is the determinant of the sub-matrix formed by deleting the row and column that contain that element. The matrix containing the minors of all elements is called the minor of the matrix. The matrix, which gives the minor of an element aij is denoted as mij and is calculated as:
\(m_{ij} = det(A_{ij})\)
Where Aij is the sub-matrix obtained by deleting the i-th row and j-th column of A.
Example
Given matrix:
\(A = \begin{bmatrix}{11} & {12} &{13} \\ {21} & {22} &{23} \\{31} & {32} &{33} \end{bmatrix}\)
The minor of the element a11 is the determinant of the sub-matrix obtained by removing the first row and first column:
\(M_{11} = \begin{bmatrix} {22} & {23} \\ {32} &{33} \end{bmatrix}\)
The cofactor of an element in a matrix is a signed value calculated by multiplying its minor by (−1)i + j, where i and j are the row and column indices of the element. The matrix formed by combining the cofactors of all the elements of a matrix is called its cofactor matrix.
Cofactor Formula
\(C_{ij} = (−1)^{i+j} × M_{ij}\)
Where:
The transpose of a matrix is a matrix where the elements of row and column of the original matrix get interchanged. If the matrix A of order m × n, its transpose, denoted as AT, will have dimensions n × m
How to Find the Transpose
To compute the transpose of a matrix, convert each row of the original matrix into a column in the new matrix.
For example, for a matrix A:
\(A = \begin{bmatrix}a_{11} & a_{12} &a_{13} \\ a_{21} & a_{22} &a_{23} \\a_{31} & a_{32} &a_{33} \end{bmatrix}\)
The transpose AT is:
\(A = \begin{bmatrix}a_{11} & a_{21} &a_{31} \\ a_{12} & a_{22} &a_{32} \\a_{13} &a_{23} &a_{33} \end{bmatrix}\)
To find the adjoint of a matrix, follow the steps mentioned below:
1. Compute the Minor of each element:
For each component aij in the matrix, remove the i-th row and j-th column to form a sub-matrix. Compute the determinant of this sub-matrix; this value is the minor mij of the element aij
For example, a11 = 1
Now we need to remove the first row and first column
\( \begin{bmatrix} {4} & {5} \\ {0} &{6} \end{bmatrix}\)
The determinant will be
det = (4)(6) − (5)(0) = 24
M11 = 24
2. Determine the Cofactor: The cofactor cij is given by
\(c_{ij} = (-1)^{i+j}. m _ {ij}\)
This accounts for the sign change based on the position of the element.
For example, a11 = 1
C11 = (−1)1 + 1 × 24 = 24
3. Form the Cofactor matrix: Arrange all the cofactors cij into a matrix.
Cofactor matrix = \( \begin{bmatrix} {24} & {-20} &{5}\\ {-5} &{6} &{-1}\\{-4} &{4} &{4} \end{bmatrix}\)
4. Transpose the Cofactor matrix: Take the transpose of the cofactor matrix to obtain the adjoint matrix.
Adj(A) = \( \begin{bmatrix} {24} & {-5} &{-4}\\ {-20} &{6} &{4}\\{-5} &{-1} &{4} \end{bmatrix}\)
Adjoint of a 2 × 2 matrix
The adjoint of a square matrix is gained by first calculating its cofactor matrix and then taking the transpose of that matrix. This adjoint is specifically useful in computing the inverse of the original matrix, provided its determinant is non-zero.
Steps to Find the Adjoint of a 2 × 2 matrix
The matrix given is:
\(A= \begin{bmatrix} {a} & {b} \\{c} &{d} \end{bmatrix}\)
c11 = d
c12 = -c
c21 = -b
c22 = a
So, the cofactor matrix is:
\(C= \begin{bmatrix} {d} & {-c} \\{-b} &{a} \end{bmatrix}\)
Transpose the Cofactor matrix:
The adjoint is the transpose of the cofactor matrix:
adj(A) = CT = \(C= \begin{bmatrix} {d} & {-b} \\{-c} &{a} \end{bmatrix}\)
Example
Given the matrix:
\(C= \begin{bmatrix} {3} & {-6} \\{-4} &{8} \end{bmatrix}\)
Adjoint of 3 × 3 matrices
Every adjoint of a square matrix is the transpose of its cofactor matrix. It is essential for calculating the inverse of a matrix, provided the determinant is non-zero.
Step-by-Step Process
The matrix given is:
\(A = \begin{bmatrix}{a_{11}} & {a_{12} }&{a_{13}} \\ a_{21} & a_{22} &a_{23} \\a_{31} & a_{32} &a_{33} \end{bmatrix}\)
1. Compute the minors of all elements:
Calculate mij of all elements by deleting the i-th row and j-th column of A, and finding the determinant of the sub-matrix.
2. Compute the cofactors of all elements:
For each element, aij calculate its cofactor cij using the formula:
\(c_{ij}=(-1)^{i+j} . det(m^{ij})\)
3. Form the Cofactor matrix:
Arrange all the cofactors cij into a matrix.
4. Transpose the Cofactor matrix:
The adjoint (adjoint) is the transpose of the cofactor matrix:
adj(A) = CT
The following chart gives the steps in summarized form for calculating adjoint of a matrix:
Practice Problem:
Given the matrix:
\(A = \begin{bmatrix}{1} & {2}&{3} \\ 4 & 5&6 \\7 & 8 &9\end{bmatrix}\)
1. Compute the minors:
\(M_{11} = 5 \times 9 - 6\times 8 = 45 - 48 = -3\\ M_{12} = 4 \times 9 - 6\times 7 = 36 - 42 = -6\\ M_{13} = 4 \times 8 - 5 \times 7 = 32 - 35 = -3 \\ M_{21} = 2 \times 9 = 3 \times 8 = 18 - 24 = -6\\ M_{22} = 1 \times 9 - 3 \times 7 = 9 - 21 = -12\\ M_{23} = 1 \times 8 - 2\times 7 = 8 - 14 = 6\\ M_{31} = 2 \times 6 - 5 \times 3 = 12 - 15 = -3\\ M_{32} = 1 \times6 - 4 \times 3 = 6 - 12 = -6\\ M_{33} = 1 \times 5 - 4 \times 2 = 5 - 8 = -3\)
2. Calculate the cofactors off all elements:
\(C_{11} -3\\
C_{12} = 6\\
C_{13} = -3 \\
C_{21} = 6\\
C_{22} = -12\\
C_{23} = - 6\\
C_{31} = -3\\
C_{32} = 6\\
C_{33} = -3\)
3. Form the Cofactor matrix:
\(A = \begin{bmatrix}{-3} & {6}&{-3} \\ 6 & -12&-6 \\-3 & 6 &-3\end{bmatrix}\)
4. Transpose the Cofactor matrix:
\(A = \begin{bmatrix}{-3} & {6}&{-3} \\ 6 & -12&6 \\-3 & -6 &-3\end{bmatrix}\)
To make understanding of adjoint matrix easy and simple, here are a few essential tips to solve problems effectively:
Understanding the adjoint (or adjoint) of a matrix is crucial in linear algebra, especially for computing inverses. However, several common mistakes can hinder accurate calculations. This guide highlights these errors and offers strategies to avoid them.
The adjoint or adjoint of a matrix is a core rule in linear algebra with diverse real-life applications. It plays a crucial role in solving systems of linear equations, computing matrix inverses, and analyzing linear transformations. Here are a few such applications:
Find the adjoint of the given matrix.
\(adj(A) = \begin{bmatrix}{{3} }&{-4} \\ {-1} &{2} \end{bmatrix}\)
Given Matrix: \(A = \begin{bmatrix}{{2} }&{3} \\ {1} &{4} \end{bmatrix}\)
For a 2 × 2 matrix, \(A = \begin{bmatrix}{{-4} }&{-3} \\ {-1} &{2} \end{bmatrix}\)
\(adj(A) = \begin{bmatrix}{{d} }&{-b} \\ {-c} &{a} \end{bmatrix}\)
Substituting the values from the matrix A:
\(adj(A) = \begin{bmatrix}{{3} }&{-4} \\ {-1} &{2} \end{bmatrix}\)
For the given 2 × 2 matrix, find the adjoint.
\(\begin{bmatrix}{{1} }&{-5} \\ {-2} &{-4} \end{bmatrix}\)
Given Matrix : \(A = \begin{bmatrix}{{-4} }&{5} \\ {2} &{1} \end{bmatrix}\)
1. Find the Cofactor matrix:
2. Cofactor matrix:
\(C = \begin{bmatrix}{{1} }&{-2} \\ {-5} &{-4} \end{bmatrix}\)
3. Transpose the Cofactor matrix (Adjoint):
adj(A) = CT = \(\begin{bmatrix}{{1} }&{-5} \\ {-2} &{-4} \end{bmatrix}\)
Find the cofactor of the given 2 × 2 matrix
\(\begin{bmatrix}{{4} }&{-3} \\ {-2} &{1} \end{bmatrix}\)
Given Matrix: \(\begin{bmatrix}{{1} }&{2} \\ {3} &{4} \end{bmatrix}\)
Calculation for cofactor:
Cofactor matrix = \(\begin{bmatrix}{{4} }&{-3} \\ {-2} &{1} \end{bmatrix}\)
Find the adjoint of the given 3 × 3 matrix
\(\begin{bmatrix}{{24} }&{6} &{-4}\\ {-18} &{-3} &{2} \\{4} &{2} &{4} \end{bmatrix}\)
Given Matrix: \(\begin{bmatrix}{{1} }&{2} &{3}\\ {0} &{4} &{5} \\{1} &{0} &{6} \end{bmatrix}\)
Transpose the Cofactor matrix (Adjoint):
adj(A) = CT = \(\begin{bmatrix}{{24} }&{6} &{-4}\\ {-18} &{-3} &{2} \\{4} &{2} &{4} \end{bmatrix}\)
For the given 3 × 3 matrix, find the adjoint.
\(\begin{bmatrix}{{-4} }&{6} &{-2}\\ {-33} &{-9} &{16} \\{32} &{4} &{-10} \end{bmatrix}\)
Given Matrix: \(\begin{bmatrix}{{1} }&{-1} &{2}\\ {2} &{3} &{5} \\{1} &{0} &{3} \end{bmatrix}\)
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