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Last updated on January 10th, 2025
The cube root of 128 is the value that, when multiplied by itself three times (cubed), gives the original number 128. Do you know? Cube roots apply to our real life also, like that for measuring dimensions, density and mass, field of engineering etc.
The cube root of 128 is 5.03968419958. The cube root of 128 is expressed as β128 in radical form, where the ββ" sign is called the βradicalβ sign.
In exponential form, it is written as (128)β
. If βmβ is the cube root of 128, then, m3=128. Let us find the value of βmβ.
The cube root of 128 is expressed as 4β2 as its simplest radical form,
since 128 = 2Γ2Γ2Γ2Γ2Γ2Γ2
β128 = β(2Γ2Γ2Γ2Γ2Γ2Γ2)
Group together three same factors at a time and put the remaining factor under the β .
β128= 4β2
We can find cube root of 128 through a method, named as, Halleyβs Method. Let us see how it finds the result.
Now, what is Halleyβs Method? It is an iterative method for finding cube roots of a given number N, such that, x3=N, where this method approximates the value of βxβ.
Formula is βaβ
x((x3+2a) / (2x3+a)), where
a=given number whose cube root you are going to find.
x=integer guess for the cubic root
Let us apply Halleyβs method on the given number 128.
Step 1: Let a=128. Let us take x as 5, since, 53=125 is the nearest perfect cube which is less than 128.
Step 2: Apply the formula. β128β
5((53+2Γ128) / (2(5)3+128))= 5.039β¦
Hence, 5.039β¦ is the approximate cubic root of 128.
some common mistakes and their solutions are given below:
Find (β128/ β64) Γ (β128/ β64) Γ (β128/ β64)
(β128/ β64) Γ (β128/ β64) Γ (β128/ β64)
= (β128Γ β128Γ β128) / (β64Γ β64Γ β64)
=((128)β
)3/ ((64)β
)3
=128/64
= 2
Answer: 2
We solved and simplified the exponent part first using the fact that, β128=(128)β
and β64=(64)β
, then solved.
If y = β128, find y^3.
y=β128
β y3= (β128)3
β y3= 128
Answer: 128
(β128)3=(1281/3)3=128.
Using this, we found the value of y3.
Subtract β128 - β125
β128-β125
= 5.039β5
= 0.039
Answer: 0.039
We know that the cubic root of 125 is 5, hence subtracting β125 from β128.
What is β(128^6) ) ?
β(1286)
= ((128)6))1/3
=( 128)2
= 16384
Answer: 16384
We solved and simplified the exponent part first using the fact that, β128=(128)β
, then solved.
Find β(128+(-3))
β(128-3)
= β125
= 5
Answer: 5
Simplified the expression, and found out the cubic root of the result.
Jaskaran Singh Saluja is a math wizard with nearly three years of experience as a math teacher. His expertise is in algebra, so he can make algebra classes interesting by turning tricky equations into simple puzzles.
: He loves to play the quiz with kids through algebra to make kids love it.