Last updated on May 26th, 2025
Factors are the numbers that divide any given number evenly without a remainder. In daily life, we use factors for tasks like sharing items equally, arranging things, etc. In this topic, we will learn about the factors of 2010, how they are used in real life, and tips to learn them quickly.
The numbers that divide 2010 evenly are known as factors of 2010.
A factor of 2010 is a number that divides the number without a remainder.
The factors of 2010 are 1, 2, 3, 5, 6, 10, 15, 30, 67, 134, 201, 335, 402, 670, 1005, and 2010.
Negative factors of 2010: -1, -2, -3, -5, -6, -10, -15, -30, -67, -134, -201, -335, -402, -670, -1005, and -2010.
Prime factors of 2010: 2, 3, 5, and 67.
Prime factorization of 2010: 2 × 3 × 5 × 67.
The sum of factors of 2010: 1 + 2 + 3 + 5 + 6 + 10 + 15 + 30 + 67 + 134 + 201 + 335 + 402 + 670 + 1005 + 2010 = 4896.
Factors can be found using different methods. Mentioned below are some commonly used methods:
To find factors using multiplication, we need to identify the pairs of numbers that are multiplied to give 2010. Identifying the numbers which are multiplied to get the number 2010 is the multiplication method.
Step 1: Multiply 2010 by 1, 2010 × 1 = 2010.
Step 2: Check for other numbers that give 2010 after multiplying
2 × 1005 = 2010
3 × 670 = 2010
5 × 402 = 2010
6 × 335 = 2010
10 × 201 = 2010
15 × 134 = 2010
30 × 67 = 2010
Therefore, the positive factor pairs of 2010 are: (1, 2010), (2, 1005), (3, 670), (5, 402), (6, 335), (10, 201), (15, 134), and (30, 67).
For every positive factor, there is a negative factor.
Dividing the given numbers with the whole numbers until the remainder becomes zero and listing out the numbers which result in whole numbers as factors. Factors can be calculated by following a simple division method
Step 1: Divide 2010 by 1, 2010 ÷ 1 = 2010.
Step 2: Continue dividing 2010 by the numbers until the remainder becomes 0.
2010 ÷ 1 = 2010
2010 ÷ 2 = 1005
2010 ÷ 3 = 670
2010 ÷ 5 = 402
2010 ÷ 6 = 335
2010 ÷ 10 = 201
2010 ÷ 15 = 134
2010 ÷ 30 = 67
Therefore, the factors of 2010 are: 1, 2, 3, 5, 6, 10, 15, 30, 67, 134, 201, 335, 402, 670, 1005, and 2010.
The factors can be found by dividing it with prime numbers. We can find the prime factors using the following methods:
Using Prime Factorization: In this process, prime factors of 2010 divide the number to break it down in the multiplication form of prime factors till the remainder becomes 1.
2010 ÷ 2 = 1005
1005 ÷ 3 = 335
335 ÷ 5 = 67
67 ÷ 67 = 1
The prime factors of 2010 are 2, 3, 5, and 67.
The prime factorization of 2010 is: 2 × 3 × 5 × 67.
The factor tree is the graphical representation of breaking down any number into prime factors. The following step shows
Step 1: Firstly, 2010 is divided by 2 to get 1005.
Step 2: Now divide 1005 by 3 to get 335.
Step 3: Then divide 335 by 5 to get 67.
Step 4: 67 is a prime number, so it cannot be divided further.
So, the prime factorization of 2010 is: 2 × 3 × 5 × 67.
Factor Pairs: Two numbers that are multiplied to give a specific number are called factor pairs. Both positive and negative factors constitute factor pairs.
Positive factor pairs of 2010: (1, 2010), (2, 1005), (3, 670), (5, 402), (6, 335), (10, 201), (15, 134), and (30, 67).
Negative factor pairs of 2010: (-1, -2010), (-2, -1005), (-3, -670), (-5, -402), (-6, -335), (-10, -201), (-15, -134), and (-30, -67).
Mistakes are common while finding factors. We can identify and correct those mistakes using the following common mistakes and the ways to avoid them.
There are 3 teams and 2010 points. How will they distribute the points equally?
They will get 670 points each.
To divide the points equally, we need to divide the total points by the number of teams.
2010/3 = 670
A garden is rectangular, the length of the garden is 5 meters and the total area is 2010 square meters. Find the width?
402 meters.
To find the width of the garden, we use the formula,
Area = length × width
2010 = 5 × width
To find the value of width, we need to shift 5 to the left side.
2010/5 = width
Width = 402.
There are 15 buses and 2010 passengers. How many passengers will be in each bus?
Each bus will have 134 passengers.
To find the passengers in each bus, divide the total passengers by the buses.
2010/15 = 134
In an office, there are 2010 chairs, and 30 rooms. How many chairs are there in each room?
There are 67 chairs in each room.
Dividing the chairs by the total rooms, we will get the number of chairs in each room.
2010/30 = 67
2010 apples need to be packed in 10 boxes. How many apples will go in each box?
Each of the boxes has 201 apples.
Divide total apples by boxes.
2010/10 = 201
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.