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352 LearnersLast updated on December 2, 2025

When dividing numbers, there are rules used to determine whether a number is divisible by another. We call these divisibility rules. In this topic, we are going to learn about different divisibility rules.
A divisibility rule is a simple shortcut that helps us check whether a number can be divided by another number by looking at its digits, without doing long division. These rules, also called divisibility tests, make large calculations easier and help us determine whether one number is divisible by another quickly.
Example:
Every number is divisible by 1.
\(7 ÷ 1 = 7\)
\(245 ÷ 1 = 245\)
So any whole number we pick will always be divisible by 1.
Divisibility rules help us quickly check whether a number is divisible by another number without performing long division. These rules make large calculations easier and help us simplify numbers during problem-solving.
Below is a table of commonly used divisibility rules:
|
Number |
Rule |
|
Divisibility by 2 |
A number that is even or a number where the last digit is an even number, i.e., (0, 2, 4, 6, 8, …) |
|
Divisibility by 3 |
The sum of its digits is a multiple of 3. |
|
Divisibility by 4 |
The last two digits form a number that is divisible by 4. |
|
Divisibility by 5 |
The last digit of the number should be 0 or 5 |
|
Divisibility by 6 |
A number is divisible by 6 if it is divisible by both 2 and 3. |
|
Divisibility by 7 |
A number is divisible by 7 if you double the last digit, subtract it from the rest of the number, and the result is a multiple of 7. For example, 203 → 20 – (2×3) = 14, which is divisible by 7. |
|
Divisibility by 8 |
The last three digits form a number that is divisible by 8 |
|
Divisibility by 9 |
The sum of the digits should be divisible by 9 |
|
Divisibility by 10 |
The last digit should be 0. |
|
Divisibility by 11 |
The difference between the sum of its digits in odd places and even places is a multiple of 11. For example, in the number 7480, add the digits in the odd positions (from the left): 7 + 8 = 15. Then, add the digits in the even positions: 4 + 0 = 4. The difference between these sums is 15 - 4 = 11. Since 11 is a multiple of 11, the number 7480 is divisible by 11. |
|
Divisibility by 12 |
The number must be divisible by both 3 and 4. |
|
Divisibility by 13 |
Remove the last digit, multiply it by 9, and subtract the result from the remaining number. If the final value is a multiple of 13, the original number is divisible by 13 |
|
Divisibility by 14 |
The number should be divisible by both 2 and 7. |
|
Divisibility by 15 |
The number should be divisible by 3 and 5. |
|
Divisibility by 16 |
The last four digits form a number divisible by 16. |
|
Divisibility by 17 |
Remove the last digit, multiply it by 5, and subtract it from the remaining number. This result should be a multiple of 17. Example: For 221, remove 1, multiply by 5 → 5. Subtract from 22 → 17, which is divisible by 17. So 221 is divisible by 17. |
|
Divisibility by 18 |
A number is divisible by 18 if it meets both of these conditions: it is even (divisible by 2), and the sum of its digits is a multiple of 9 (divisible by 9). |
|
Divisibility by 19 |
A number is divisible by 19 if we remove the last digit, multiply it by 2, and add it to the remaining number, which should give a multiple of 19. Example: For 285, remove 5 → multiply by 2 = 10; add to 28 → 38, which is divisible by 19. So 285 is divisible by 19. |
Let’s check each number using the correct divisibility rule:


We already know the basic divisibility rules for 2, 3, 5, 7, and 11. Now let’s build on that and learn simple tests for prime numbers between 11 and 19, starting with 13 and 17.
Divisibility Rule for 13:
A number is divisible by 13 if it divides evenly, with no remainder. Here’s a quick method to test it without using long division:
If the final answer is divisible by 13, then the original number is also divisible by 13. There are three additional methods to check divisibility by 13, but this is the simplest one for learners.
Divisibility Rule for 17:
A number is divisible by 17 if it is entirely divided without leaving any remainder. Here’s a shortcut to check it:
If the final value is divisible by 17, then the original number is also divisible by 17.
Some tips and tricks for mastering in divisibility rules are given below.
When learning about divisibility rules, students may confuse them with other rules. Here are some common mistakes that students make and ways to avoid them:
Divisibility rules are used widely in various fields. Here are a few real-world applications of divisibility rules:
Is 4,678 divisible by 2?
Yes, it is divisible by 2.
A number is divisible by 2 if its last digit is even. The last digit of 4,678 is 8, which is even, so it is divisible by 2.
Is 5,217 divisible by 3?
Yes, 5,217 is divisible by 3.
To know if the number is divisible by 3, add the digits: \(5 + 2 + 1 + 7 = 15\). Since 15 is divisible by 3, the number 5,217 is also divisible by 3.
Is 6,890 divisible by 10?
Yes, 6,890 is divisible by 10.
A number is divisible by 10 if the last digit of the number ends in 0. Since 6,890 ends in 0, it is divisible by 10.
Is 91,483 divisible by 11?
No, it is not divisible by 11.
To find the divisibility of 11 we need to find the sum of the digits in the odd places and the sum of the digits in even places. We then need to find the difference between the odd and even places.
Odd positions: 9, 4, 3
Even positions: 1, 8
Hence, difference: \((9 + 4 + 3) - (1 + 8) = 16–9 = 7.\)
Since 7 is not a multiple of 11, the number is not divisible by 11.
Is 5,200 divisible by 13?
Yes, it is divisible by 13.
To check if 5,200 is divisible by 13, follow the divisibility rule for 13:
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.






