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1162 LearnersLast updated on October 9, 2025

Surd is a term that we use to refer to square roots of non-perfect squares. Surds also include higher roots, such as cube roots, that cannot be simplified into rational numbers. In this topic, we are going to learn more about surds and their various types.
Surd is a mathematical term used to describe irrational numbers that can be expressed as the root of an integer. When a root cannot be simplified further, we call that a surd. For example, √4 is not a surd because it can be simplified to 2. When we simplify √4, we get 2 because the square root of 4 is 2. Surds help in keeping calculations exact rather than using decimal approximations.
When calculating surds, there are a few key properties that you must follow:
We can classify surds into six different types:
There are 6 rules that we use for the calculation of surds:
Rule 1: \(\sqrt{a\times b} = \sqrt a \times \sqrt b\)
Example: \(\sqrt{36} = \sqrt{9×4} = \sqrt9 × \sqrt4 = 3 × 2 = 6\)
Rule 2: \({\sqrt a \over \sqrt b} = \sqrt{a \over b}\)
Example: \({\sqrt{18} \over \sqrt2} = {\sqrt{18\over2}} = \sqrt9 = 3\)
Rule 3: \({b\over \sqrt a} = {{b\over \sqrt a} \times {\sqrt a\over \sqrt a}} = {b \sqrt a \over \ a}\)
Example: \({3\over \sqrt 5} = {{3\over \sqrt 5} \times {\sqrt 5\over \sqrt 5}} = {3 \sqrt 5 \over \ 5}\)
Rule 4: \(a \sqrt c \space \pm \space b\sqrt c = (a \space \pm \space b)\times \sqrt c\)
Example: \(5 \sqrt 5 \space \pm \space 3\sqrt 5 = (5 \space \pm \space 3)\times \sqrt 5\)
Rule 5: \({c \over {a\space+\space b\sqrt n}} = {{c \over {a\space+\space b\sqrt n}}} \times {{a\space-\space b\sqrt n}\over {a\space-\space b\sqrt n}} = {c \times ({a\space-\space b\sqrt n)}\over {a^2\space-\space b^2 n}}\)
Example: \({5\over {4\space+\space 2\sqrt 3}} = {{5 \over {4\space+\space 2\sqrt 3}}} \times {{4\space-\space 2\sqrt 3}\over {4\space-\space 2\sqrt 3}} = {5 \times ({4\space-\space 3\sqrt 2)}\over {4^2\space-\space (2^2 \times 3)}} = {20-15 \sqrt 2\over 4}\)
Rule 6: \({c \over {a\space-\space b\sqrt n}} = {{c \over {a\space-\space b\sqrt n}}} \times {{a\space+\space b\sqrt n}\over {a\space+\space b\sqrt n}} = {c \times ({a\space+\space b\sqrt n)}\over {a^2\space-\space b^2 n}}\)
Example: \({5\over {4\space-\space 2\sqrt 3}} = {{5 \over {4\space-\space 2\sqrt 3}}} \times {{4\space+\space 2\sqrt 3}\over {4\space+\space 2\sqrt 3}} = {5 \times ({4\space+\space 3\sqrt 2)}\over {4^2\space-\space (2^2 \times 3)}} ={20+15 \sqrt 2\over 4} \)
When solving for surds, there are a few steps we need to look out during each operation:
These are some of the few ways we can solve for surds when using the basic arithmetic operations.
Performing operations of surds can be tough and confusing. Here are a few tips and tricks to simplify calculations:
Students tend to make mistakes while learning surds. Being aware of such mistakes can work in our favor. Take a look at some of the most common mistakes and ways to avoid them:
Surds are used in fields where precise calculations involving irrational numbers are required:
Simplify √72.
6√2
Factorize 72, and you will get \({\sqrt{36 \times 2}} = \sqrt{36} \times \sqrt 2\)
Since \(\sqrt{36}\) = 6 we get 6√2.
Add 3√5 +7√5
10√5
Since both terms have the same surd √5, we will add the coefficients: 3 + 7 = 10
So, 3√5 + 7√5 = 10√5
8√3 - 2√3
6√3
So, \(8√3 - 2√3 = 6√3\)
Divide: √48/√3
4
\({\sqrt {48} \over \sqrt {3} } = {\sqrt{48\over 3}} = \sqrt {16} = 4\)
Solve: (√18 + √8) / √2
5
\(\sqrt {18} = 3\sqrt 2, \sqrt8 = 2\sqrt 2\)
Sum of \(\sqrt {18} \space\text{and} \sqrt8 \) : 3√2 + 2√2 = 5√2
Dividing by √2: 5√2 ÷ √2 = 5
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.






