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Last updated on October 14, 2025
Harmonic progression is the reciprocal of arithmetic progression. This progression does not contain any terms with zero. It is used in real-life situations, including financial calculations and problems involving speed, sound, and rates. In this article, we will discuss its definition, formulas, examples, and applications.
A harmonic progression is formed by taking the reciprocals of an arithmetic progression. In arithmetic progression, we add the same number each time, like a \((a + d), (a + 2d), (a + 3d)\). In a harmonic progression, we take the reciprocal of each term in an arithmetic progression, so we will get \(\frac{1}{a}, \quad \frac{1}{a + d}, \quad \frac{1}{a + 2d}, \quad \frac{1}{a + 3d} \).
Here, a = first term, d = common difference between the terms.
HP is fundamentally about inverse relationships. If the original AP grows linearly, its reciprocals decrease in a non-linear but systematic way. This creates a sequence where differences in reciprocals \(\left(\frac{1}{H_{n+1}} - \frac{1}{H_n}\right) \), are constant, and which is exactly the AP property.
To make sure the terms are defined and the sequence progresses, so ‘a’ and ‘d’ can never be zero. This pattern continues indefinitely, forming an infinite sequence.
Let’s understand this clearly using the following example:
Rahul rides a bicycle on a straight road. If he rides at different speeds over different parts of the journey, his travel time follows a harmonic pattern.
If he travels at a speed of 10 km/h, 20 km/h, 30 km/h, 40 km/h... these speeds are an arithmetic progression because he adds 10 km/h each time.
But if he calculates the time taken for each part of the journey, the values will be \(\frac{1}{10}, \quad \frac{1}{20}, \quad \frac{1}{30}, \quad \frac{1}{40} \),..., which forms a harmonic progression.
Harmonic progression is used in average speed calculations, especially when the distances are covered at different speeds and the total time follows a harmonic pattern.
The relationship among Arithmetic Mean (AM), Geometric Mean (GM), and Harmonic Mean (HM) is: AMGMHM
This means that the Arithmetic Mean is always the largest, followed by the Geometric Mean, and the Harmonic Mean is the smallest.
To understand this, consider any two numbers a and b. The formulas for the arithmetic mean, geometric mean, and harmonic mean are as follows.
\(AM = \frac{a + b}{2} \)
\(GM = \sqrt{ab} \)
\(HM = \frac{2ab}{a + b} \)
The relationship formula among AM, GM, and HM states that the product of the arithmetic mean and the harmonic mean equals the square of the geometric mean.
\(AM \times HM = GM^{2} \)
By deriving this formula, we are able to identify it better.
\(AM \times HM = \frac{a + b}{2} \times \frac{2ab}{a + b} = ab \)
Here, ab can be derived as \(ab = GM^{2} \)
Harmonic progression has some important formulas that help in calculations. These formulas help us find specific terms, the average value, and the total sum of a harmonic sequence.
The nth term in HP is the reciprocal of the nth term of an arithmetic progression. The formula for HP is:
\(H_n = \frac{1}{a + (n - 1)d} \)
Where, a is the first term of an arithmetic sequence.
d is the difference between the terms.
n is the position of the term to be determined.
Harmonic Mean: It is the type of average used in harmonic progression. It is useful when dealing with speed, distance, or rates.
\(HM = \frac{2ab}{a + b} \)
\(HM = \frac{3}{\frac{1}{a} + \frac{1}{b} + \frac{1}{c}} \)
\(S_n = \frac{1}{2d} \log \frac{2a + (2n - 1)d}{2a - d} \)
Harmonic Progression can seem tricky at first because it deals with the reciprocals of numbers. Here are some tips to help students grasp and remember HP effectively:
Harmonic progression involves working with reciprocals and fractions, which can sometimes cause mistakes. Here are some common mistakes and tips on how to avoid them.
Harmonic Progression is an important concept that can be applied to real-life situations where quantities are inversely related. Here are a few real-life applications of Harmonic Progression.
\(HM = \frac{2 \times 10 \times 20}{10 + 20} = \frac{400}{30} = 13.333 \)
The 2nd and 4th terms of a harmonic progression are 2 and 4. Find the 5th term.
8
In H.P., take reciprocals to form an A.P.
Reciprocals: \(\frac{1}{2} \) and \(\frac{1}{4} \) (these are the 2nd and 4th terms of the A.P.)
Let’s find the common difference (d):
Difference between positions = \(4–2 = 2\)
So,\(d = \frac{\frac{1}{4} - \frac{1}{2}}{2} = \frac{-\frac{1}{4}}{2} = -\frac{1}{8} \)
Now find the 5th A.P. term:
2nd term = \(\frac{1}{2} \)
3rd term = \(\frac{1}{2} + \left(-\frac{1}{8}\right) = \frac{3}{8} \)
4th term = \(\frac{3}{8} + \left(-\frac{1}{8}\right) = \frac{1}{4} \)
5th term = \(\frac{1}{4} + \left(-\frac{1}{8}\right) = \frac{1}{8} \)
So, 5th H.P. term = Reciprocal of \(\frac{1}{8} = 8 \)
In a harmonic progression, the 1st term is 1 and the 3rd term is 1/3. Find the 2nd term.
\(\frac{1}{2} \)
In an H.P, take the reciprocals to form an AP:
1st H.P. term = 1 → reciprocal = 1
3rd H.P. term = 1/3 → reciprocal = 3
So, in A.P., Middle term =\(\frac{1 + 3}{2} = 2 \)
Taking the reciprocal of 2→ \(\frac{1}{2} \).
The 3rd and 5th terms of a harmonic progression are 3 and 6. Find the 4th term.
4
We first take reciprocals to form an A.P:
3rd H.P. term = 3 → reciprocal = \(\frac{1}{3} \)
5th H.P. term = 6 → reciprocal = \(\frac{1}{6} \)
Now, we find the 4th term:
4th term of A.P. = average of 3rd and 5th:
\(\frac{\frac{1}{3} + \frac{1}{6}}{2} = \frac{\frac{1}{2}}{2} = \frac{1}{4} \)
Take the reciprocal of \(\frac{1}{4}=4 \).
In a harmonic progression, the 2nd term is 5 and the 5th term is 2. Find the 3rd term.
\(\frac{10}{3} \) or 3.33
Reciprocals give an A.P:
2nd H.P. term = 5 → reciprocal = \(\frac{1}{5} \)
5th H.P. term = 2 → reciprocal = \(\frac{1}{2} \)
Common difference d = \(\frac{\frac{1}{2} - \frac{1}{5}}{5 - 2} \) \(=\frac{\frac{5}{10} - \frac{2}{10}}{3} = \) \(\frac{\frac{3}{10}}{3} = \frac{1}{10} \)
To find the 3rd A.P. term:
\(\frac{1}{5} + \frac{1}{10} = \frac{2}{10} + \frac{1}{10} = \frac{3}{10} \)
Take reciprocal of \(\frac{3}{10} \) → H.P. term = \(\frac{10}{3} \) or approx. 3.33
The 1st and 4th terms of a harmonic progression are 10 and 5. Find the 2nd term.
7.5
Reciprocals form A.P.:
1st H.P. term = 10 → reciprocal = \(\frac{1}{10} \)
4th H.P. term = 5 → reciprocal =\(\frac{1}{5} \)
Steps between 1st and 4th = 3
Common difference (d):
\(d = \frac{\frac{1}{5} - \frac{1}{10}}{3} = \frac{2-1}{10} \div 3 = \frac{1}{10} \div 3 = \frac{1}{30} \)
Now, we find the 2nd A.P. term = 1st + d = \(\frac{1}{10} + \frac{1}{30} \) \(=\frac{3 + 1}{30} = \frac{4}{30} = \frac{2}{15} \)
reciprocal of \(\frac{2}{15} = \frac{15}{2} = 7.5 \)
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.