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1266 LearnersLast updated on December 2, 2025

Equations are significant components in mathematics. The equations use the "=" sign to indicate that both sides of an expression are equal. They are widely utilized in finding unknown values. In this topic, we will talk more about simple equations and their applications.

A simple equation is a mathematical statement that shows the equality of two expressions and contains one variable whose value must be found. It is usually a linear equation in one variable, meaning the variable has a degree of 1.
The simple equations are based on the idea of balance. The equal to sign (=) acts like the center of a weighing scale, where both sides must remain equal. So whatever operation is performed on one side, be it addition, subtraction, multiplication, or division, we must perform the same operation on the other side to keep the equation balanced.
Simple Equation Definition
A simple equation is a linear equation in one variable that shows equality between two expressions and can be solved using basic arithmetic operations to find the value of the unknown variable.
Simple equation example:
Let us consider the simple equation \(2y + 10\).
Here, y is the variable, 2 and 10 are the constants, and + is the operator.
We can solve the equation by keeping both sides balanced:
\(2y + 10 = 12\)
\(2y = 12 - 10\); here, we subtracted 10 from both sides.
\(2y = 2\)
Divide both sides by 2:
\(y = \frac{2}{2}\)
\(y = 1\).
The transposition method involves shifting terms across the equal sign while changing their signs accordingly. For example, positive becomes negative and vice versa. Also, arithmetic operations change when transposing terms.
For example, addition becomes subtraction, and division becomes multiplication (and vice versa). This technique helps us in finding the unknown variable by isolating it.
Take a look at this example for better understanding:
Find the value of p
\(3p – 3 = 12\)
\(3p = 12 + 3\)
\(3p = 15 \)
\(p = \frac{15}{3}\)
\(p = 5\)
Hence, p is 5.
A linear equation is another term for a simple equation that involves one or more variables. Solving linear equations is straightforward and can be done using simple methods like graphing. Linear equations can also be solved by transposing the terms or by balancing the LHS and RHS.
Note that, when a number is transposed, its preceding sign changes.
For example:
Prove LHS = RHS for \(8x + y = 24\), given x = 2 and y = 8.
\(8 × 2 + 8 = 24\)
\(16 + 8 = 24\)
\(24 = 24\)
Therefore, LHS = RHS.
What is the Difference Between Variables and Constants in a Simple Equation?
In simple equations, variables and constants play a vital role. Variables are values that can change, whereas constants are values that remain the same. Let us explore other significant differences between a variable and a constant from the table below:
|
Variables |
Constants |
|---|---|
|
Variables are symbols that represent an unknown value, that may change and are represented commonly using letters like x, y, and z. |
Constants are fixed values that does not change in a simple equation. They are usually any real numbers. |
|
By solving the equation, the value of the variable can be found. |
Constants help to define the equation, but remain the same. |
|
It can be varied depending on the solution of the equation. |
It will not be varied. It will always stay the same. |


Solving simple equations determines the values of the unknown variable in the given equation. In a simple equation, the LHS and RHS should be equivalent. There are different methods for solving simple equations, as mentioned below:
Trial and Error Method
In a trial and error method, we substitute random values for the variable to check if it satisfies the equation LHS = RHS.
For example: x + 5 = 15
Where:
LHS = x + 5
RHS = 15
Let’s now perform the trial and error method by substituting values starting from 1 to check if LHS = RHS.
| x | LHS (x + 5) | RHS | Is LHS = RHS? |
| 1 | 1 + 5 = 6 | 15 | No |
| 2 | 2 + 5 = 7 | 15 | No |
| 3 | 3 + 5 = 8 | 15 | No |
| 4 | 4 + 5 = 9 | 15 | No |
| 10 | 10 + 5 = 15 | 15 | No |
Therefore, LHS = RHS for x = 10.
Systematic Method
The systematic method, also known as the balance method, is used to balance the equation by performing the mathematical operations on both sides of the equation. This systematic approach compares both sides of the equation to a weighing balance. It maintains equality by adding or removing values from each side of the equation.
For example: \(y - 2 = 8\)
We add 2 to both sides to isolate y
\(y – 2 + 2 = 8 + 2\)
Thus, \(y = 10\).
Transposition Method
The transposition method simplifies the equation by shifting terms across the equal sign. Below is a table exhibiting both systematic and transposition methods for the same equation.
| Adding or subtracting on both sides (systematic method) |
Transposing |
|---|---|
| \(2x – 8 = 4\) Adding 8 to both sides, \(2x – 8 + 8 = 4 + 8\) \(2x = 12\) |
\(2x – 8 = 4\) Transposing –8 from LHS to RHS, (When transposing, –8 becomes +8) \(2x = 12\) |
Therefore, we can apply the transposition method to solve simple equations.
Here are some effective tips and tricks to help in mastering simple equations.
Simple equations help students find unknown variables easily without complex formulas. However, there are a few common mistakes that students should watch out for. Here’s a list of such mistakes along with steps to avoid them:
Simple equations are widely used in problem-solving in various real-life situations. They are used in different fields beyond mathematics. Let’s look into some:
The sum of Roy’s age and his father’s age is 66. If Roy is 20 years old, calculate his father’s age.
Roy’s father is 46 years old.
Consider Roy’s father’s age to be y
The equation for the given problem: 20 + y = 66
Now, subtract 20 from both sides,
y = 66 – 20
y = 46
Therefore, Roy’s father is 46 years old.
A teacher asked her students: “If a number is added to 12, the result is 24. Find the number.”
The unknown number is 12.
Consider the unknown number as x
The equation for the given problem:
x +12 = 24
We find the value of x by subtracting 12 from both sides:
x = 24 – 12
x = 12
Therefore, the unknown number is 12.
A shopkeeper has 6 boxes of pencils. Each box contains the same number of pencils. If there are 30 pencils in total, how many pencils are in each box?
There are 5 pencils in each box.
Consider the number of pencils in each box to be y
6 × x = 30
We find x by dividing both sides by 6:
6 × x = 30 ⇒ x = 30 ÷ 6 ⇒ x = 5
So, there are 5 pencils in each box.
Find the value of x in the equation: 5x – 10 = 40
x = 10.
We have:
5x – 10 = 40
To isolate the term with x, we add 10 to both sides:
5x = 50
x = 50/5
x = 10.
Assume a number is subtracted from 60 and the result is 15. Find the number.
The number is 45.
Consider the number to be y
The equation for the given problem:
60 – x = 15
Solving for x:
60 - x = 15 ⇒ x = 60 - 15 ⇒ x = 45.
x = 45.
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.






