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Last updated on October 16, 2025

Subtracting Mixed Fractions

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A mixed fraction has two components: a whole number and a proper fraction. A few examples of these numbers are 2 1/2, 3 4/5, 5 4/7. The subtraction of mixed fractions involves finding the difference between two of these fractions. Subtracting mixed fractions has many real-life applications, especially in construction and culinary arts. In this article, we will learn how to subtract mixed fractions.

Subtracting Mixed Fractions for US Students
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What is Subtracting Mixed Fractions?

The subtraction of mixed fractions is a fundamental arithmetic operation that finds the difference between two mixed fractions. A mixed fraction consists of a whole number and a proper fraction.

 



For example, \(3\frac{1}{2}\) and \(2\frac{3}{5}\) can be subtracted to know the difference between these two numbers. 

In fractions, there can be like and unlike denominators, and the method of subtraction is different for each. Let us now learn how to subtract mixed fractions with like denominators.

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Subtracting Mixed Fractions With Like Denominators

Fractions that have a common denominator are known as like fractions. The mixed fractions also have the same denominators, such as \(2\frac{1}{4}\) and \(3\frac{2}{4}\). When we subtract mixed fractions with like denominators, we have to keep some points in mind. 

 

  • Mixed fractions can be represented as \(a\frac{b}{c}\) and written as \(a + \frac{b}{c}\).
     
  • The standard procedure while subtracting mixed numbers is to subtract the whole number first before subtracting the fractional part.
     
  • A mixed number can be converted into an improper fraction by multiplying the denominator by the whole number. The product should then be added to the numerator and the denominator must be retained. 


    For example, a mixed fraction \(1 + \frac{6}{13}\) can be converted to an improper fraction as follows: 

    Multiply the whole number by the denominator:
    \(1 × 13 = 13\)

    Add the product to the numerator:
    \(13 + 6 = 19\)

    Keep the denominator the same and write the improper fraction as: 
    \(19 \over 13\)
     
  • We can convert an improper fraction into a mixed fraction by dividing the numerator by its denominator. Now, the resulting quotient is the whole number, the remainder is the numerator, and the denominator is retained. It can be expressed as:

    \(Q {R \over D}\)


    For instance, an improper fraction \(25 \over 3\) can be converted to a mixed fraction as follows:

    Divide the numerator by the denominator: 

    \(25 ÷ 3 \)

    Quotient = 8

    Remainder = 1 

    Hence, the mixed fraction will be: 

    \(\frac{25}{3} = 8 \frac{1}{3}\)


Now, let us subtract \(2 \frac{1}{5}\) from \(4 \frac{2}{5}\)

Step 1: Subtract the whole numbers. 
\(4 - 2 = 2\)


Step 2: Subtract the fractional parts. 
\({2 \over 5} - {1 \over 5} = {1 \over 5}\)

Step 3: Combine the whole number and the fractional part from the answers obtained in step 1 and step 2.


Therefore, the final answer is \(2 {1 \over 5}\)

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Subtracting Mixed Fractions With Unlike Denominators

Fractions that have different denominators are known as unlike fractions. If the mixed fractions have unlike denominators, we can follow two methods to find the difference.

 

Method 1: Use the least common denominator (LCD) of the unlike denominators.

For example, subtract \(2 {3 \over 4}\) from \(4 {5 \over 6}\)

 

 

Step 1: Subtract the whole numbers of the mixed fractions. 
            \(4 - 2 = 2\)

 

Step 2: If the fractions have a different denominator, then we must find the LCD.

The LCD of 4 and 6 is 12. 

 

Step 3: Convert the two fractions into fractions with a common denominator of 12. 
 

  • To convert 5/6, multiply both numerator and denominator by 2.
    \(\frac{5}{6} = {5 × 2 \over {6 × 2}} = {10 \over 12}\)
     
  • Now, to convert 3/4, multiply both the numerator and the denominator by 3:
    \({3 \over 4} = \frac{3 × 3}{4 × 3} = {9\over 12}\)

 

Step 4: Now that both fractions have a common denominator, we can just subtract the numerator and retain the denominator. 
\({10 \over 12} - {9 \over 12} = {1 \over12}\)

 

 

Step 5: Write the difference by combining the results. 2 is the difference of whole numbers, and \(1 \over12 \)is the difference of the fractional part. Therefore, the final result is \(2 {1 \over12}\)

So, \(4 {5 \over 6} - 2 {3 \over 4}  = 2 {1 \over 12}\)

 

Method 2: Convert the mixed fractions into improper fractions.

For instance, subtract \(3 {1 \over 4} \space \text{from} \space 6 {3 \over5}\)

 

Step 1: Convert the mixed fractions to improper fractions: 
           \(\begin{align*} 6 {3 \over 5}  &= \frac{(6 × 5) + 3}{5} = \frac{30 + 3}{5} = \frac{33}{5}  \\  6 {3 \over 5}  &= \frac{33}{5} \end{align*}\)
   
    Next,

\(\begin{align*}3 {1 \over 4}  &= \frac{(3 × 4) + 1}{4} \\ &= \frac{12 + 1}{4} = {13 \over 4} \end{align*}\)

 

Step 2: Make the denominators the same by finding the LCD. 
          The LCD of 5 and 4 is 20. 

 

Step 3: Write the fractions with the common denominator. 
        \(\frac{33}{5} = \frac{(33 × 4)} { (5 × 4)} = \frac{132}{20} \)

        \(\frac{13}{4} = \frac{(13 × 5)} { (4 × 5)} = \frac{65}{20}\)

 

Step 4: Now, subtract the fractions:
         \({132 \over 20} - {65 \over 20} = {67\over 20}\)

 

Step 5: Convert the fraction into a mixed number.
 

  • To convert, let’s divide the numerator by the denominator.
     
  • The quotient and remainder after dividing \(67 \over 20\) are 3 and 7 respectively.
     
  • Write the quotient as the whole number and the remainder as the numerator. 
     
  • The denominator of the fractional part will be the same.  
     
  • Hence, the mixed fraction is \(3 {7 \over 20}\)

 

Here, the value of \(6 {3 \over 5}  - 3 {1 \over 4}\) is equal to \(3 {7 \over 20}\).

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Subtracting Mixed Fractions With Regrouping

We can use regrouping while subtracting mixed numbers when the fractional part of the subtrahend is greater than that of the minuend.

 

For example, subtract \(6 {3 \over 4}\) from \(9 {1 \over 5}\)

 

Step 1: Compare the fractional parts and make the unlike denominators to a common denominator.
 

  • Here, the fractional parts are: 
    \(1 \over 5\) and \(3 \over 4\).

 

Step 2: Now, find the least common denominator of 5 and 4. 
 

  • 20 is the LCD of 4 and 5. 

 

  • Let’s convert \(1 \over 5\) and \(3 \over 4\) from unlike to like denominators.

 

  • Multiply both the numerator and the denominator of \(1 \over 5\) by 4
    \(1 \over 5\)  \(= \frac{1 × 4}{5 × 4} = {4\over 20}\)

 

  • Now multiply the numerator and the denominator of 3/4 by 5
    \(3 \over 4\)  \(= \frac{ 3 × 5}{4 × 5}  = {15 \over 20}\)

 

Step 3: Since \({15 \over 20} > {4 \over 20}\), we cannot subtract directly. Therefore, borrow 1 from the whole number part of \(9{1 \over 5}\)

1 whole can be written as \(20 \over 20\) since the LCD of 4 and 5 is 20. 

Now, add the borrowed \(20 \over 20\) to \(4 \over 20\), and we get \(24 \over 20\).

 

Step 4: The whole number 9 becomes 8, and the fraction \(4 \over 20\) becomes \(24 \over 20\)


Hence, \(9{1 \over 5}\) becomes \(8{24 \over 20}\) and \(6 {3 \over 4}\) becomes \(6{15 \over 20}\).

 

Step 5: Subtract the fractions. 
\(8{24 \over 20}\) - \(6{15 \over 20}\) 

 

  • Subtract the whole numbers
    \(8 - 6 = 2 \)   

 

  • Subtract the fractional part
    \({24 \over 20} - {15 \over 20}  = \frac{24 - 15}{20}  = {9\over 20}\)  

 

Thus, the result is \(2 {9 \over 20}\).

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Tips and Tricks to Master Subtracting Mixed Fractions

By following the right approach, subtracting mixed fractions can be easy and simple. Here are a few tips and tricks:
 

  • Always convert mixed fractions to improper fractions for easy calculation.
     
  • Find the LCM to convert unlike denominator to like denominator. 
     
  • Use visual aids like fraction bars to understand subtraction steps and avoiding mistakes.
     
  • Always write the final answer in mixed fractions or proper fraction.
     
  • Always convert the borrow into fraction, before adding it to the fractional part.
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Common Mistakes and How to Avoid Them in Subtracting Mixed Fractions

The subtraction of mixed fractions is a basic mathematical operation that helps students understand the difference between two such numbers. However, students often make some errors when they perform the subtraction. Here are some common mistakes and helpful solutions to avoid these errors. 

Mistake 1

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Mistakenly Subtracting the Denominators of Like Fractions 

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Keep in mind that when working with fractions with like denominators, the denominator should stay the same. Only the whole numbers and the numerators will be subtracted. If they mistakenly subtract the denominators as well, the answer will be incorrect. 
 

For example, \(3 {9 \over 20} - 2 {4 \over 20}\)
 
= 150   is incorrect. 

The correct difference is:
\(3 {9 \over 20} - 2 {4 \over 20} = 1 {5 \over 20}\)

Mistake 2

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Incorrect Conversion of Mixed Fraction to an Improper Fraction 

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Always remember that when converting a mixed number to an improper fraction, first multiply the whole number by its denominator. Then, add the result to the numerator and keep the denominator the same. 
 

 

For instance, \(2 {4 \over 9}\) can be converted to an improper fraction as: 

\(2 × 9 = 18\)

\(18 + 4 = 22\)

Hence, the improper fraction of \(2 {4 \over 9}\) is \(22 \over 9\).

Mistake 3

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Incorrectly Converting an Improper Fraction to a Mixed Fraction

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An improper fraction can be converted into a mixed fraction. We just need to divide the fraction; the resulting quotient will be the whole number part, the remainder becomes the numerator, and the denominator remains the same.  

 

For example, \(19 \over 3\) can be converted to a mixed fraction as:

\(19 ÷ 3 \)

Quotient = 6

Remainder = 1 

Hence, the mixed fraction can be written as \(Q {R \over D}\) where Q is the quotient, R is the remainder, and D is the denominator
\({19 \over 3} = 6{1 \over 3}\)

Mistake 4

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Forgetting to Find the LCD of Unlike Denominators

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Always remember to find the least common denominator (LCD) when subtracting mixed fractions with unlike denominators. To find the LCD, list the multiples of each denominator and identify the least common multiple.

Mistake 5

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Incorrect Subtraction With Regrouping 

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Sometimes, students fail to borrow when it is needed. Borrowing 1 from the whole number is important to convert it into an equivalent fraction.  

 

For example, borrowing is required when we need to subtract \(4 {2 \over 5} - 3 {3 \over 4}\)
 

Since \({2 \over 5} < {3 \over 4}\) , we have to borrow 1 from the whole number 4. 
 

If students forget to borrow 1 from the whole number, then the difference will be incorrect. 

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Real-Life Applications of Subtracting Mixed Fractions

Understanding the process of subtracting mixed fractions will help us to solve various real-life problems easily. We can use this concept in various situations, ranging from cooking to engineering. Here are some real-life applications of subtracting mixed fractions: 

 

  • When cooking, we need to subtract mixed fractions to ensure the correct quantity of items is used.  For example, to bake a cake, we need \(3{1 \over 2}\) cups of flour, but we have already added \(2{1 \over 2}\)cups. To find the remaining cups, we should subtract 2 1/2 from 3 1/2.

    \(3 {1 \over 2} - 2 {1\over 2} = 1 \)

    So, 1 cup of flour is still needed. 

 

  • In engineering and construction, engineers use the subtraction of mixed fractions to measure the materials accurately. For instance, an engineer builds a room that is \(8{1 \over 4}\) square feet long. If he wants to remove \(2{3 \over 7}\) square feet, he needs to subtract: 

    \(8 {1 \over 4} - 2 {3\over 7} = 5 {23 \over 28}\)

    So, the remaining space is \(5 {23 \over 28}\) feet. 

 

  • While shopping, we must compare the overall price of items with our total budget. For example, our total budget is \($6 {1 \over 2}\), and we buy two items that cost \($1 {1 \over 2}\) and \($2 {1 \over 2}\). To calculate how much money we have left: 

    \(6{ 1 \over 2} - 1 {1 \over 2} = 5\)

    $5 left after shopping. 

 

  • When calculating remaining time, after a fraction of time has already passed, we use subtraction of mixed fractions. For example, if a movie is \(2 {1 \over 2}\) hours, and  {1 \over 2}\(1 {1 \over 2}\) hours has already passed. To calculate the time left for the movie to be finished:  

    \(2 {1 \over 2} - 1 {1 \over 2} = 1 {1 \over 2}\)

    The remaining movie will be finished in \(1 {1 \over 2}\) hours.

 

  • During a marathon, to calculate the path you have left to cover, subtracting a mixed fraction is applied. For example, if you have covered \(2 {2 \over 5}\) km and the marathon is of \(6 {4 \over 5}\) km, the distance left to cover can be calculated by:

    \(6 {4 \over 5} - 2 {2 \over 5} = 4 {2 \over 5}\)

    The remaining distance is \(4 {2 \over 5}\) km.

 

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Solved Examples of Subtracting Mixed Fractions

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Problem 1

Subtract 2 1/5 from 6 2/5 .

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\(4 \frac{1}{5} \)

Explanation

To subtract \(6\frac{2}{5} \) -  \(2\frac{1}{5} \)
 

  • First, subtract the whole numbers: 

\(6 - 2 = 4\)

 

  • Next, subtract the fractional parts:

\(\frac{2}{5} \) - \(\frac{1}{5} \) = \( \frac{1}{5} \)

 

Hence, the final answer is \(4\frac{1}{5} \)

 

The difference between \(6\frac{2}{5} \) and \(2\frac{1}{5} \) is \(4\frac{1}{5} \).

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Problem 2

Subtract 3 2/4 from 5 3/4.

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\(2 \frac{1}{4} \)

Explanation

Here, the problem is \(5\frac{3}{4} - 3\frac{2}{4} \) 

 

  • First, we can subtract the whole number parts: 

\(5 - 3 = 2\)

 

  • Next, the fractional parts: 

\(\frac{3}{4} \) - \(\frac{2}{4} \) = \(\frac{1}{4} \)

 

Therefore, the final answer is \(2 \frac{1}{4} \).

 

\(2 \frac{1}{4} \) is the difference between  \(5\frac{3}{4} \) and \(3\frac{2}{4} \).

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Problem 3

Find the difference between 6 1/4 and 4 2/5.

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 \(1\frac{17}{20} \)

Explanation

Here, the problem is \(6\frac{1}{4} - 4 \frac{2}{5}\) .

 

  • Since we have an unlike denominator, the LCD of 4 and 5 must be determined.
    The LCD of 4 and 5 is 20.

 

  • Now, convert the unlike fractions to have the same denominator:

    Convert \(\frac{1}{4} = \frac{1 \times 5}{4 \times 5} = \frac{5}{20} \)

    Convert \(\frac{2}{5} = \frac{2 \times 4}{5 \times 4} = \frac{8}{20} \)

 

  • Now, the expression becomes:
    \( 6 \frac{5}{20} - 4 \frac{8}{20} \)

 

  • Since \(\frac{5}{20} \) is less than \(\frac{8}{20} \), we need to borrow 1 from the whole number part.

 

  • We borrow 1 from the whole number 6, and it becomes 5.

 

  • Borrowed 1 can be written as \(\frac{20}{20} \) since the denominator is 20. 

 

  • Add \(\frac{20}{20} \) to \(\frac{5}{20} \):

    \(\frac{20}{20} \)+ \(\frac{5}{20} \) = \(\frac{25}{20} \)

 

  • Now, the expression becomes: 
    \(5\frac{25}{20} - 4\frac{8}{20} \) 

 

  • Next, subtract the whole numbers: 
    \(5 - 4 = 1\)

 

  • Then, the fractional parts:
    \(\frac{25}{20} \) - \(\frac{8}{20} \) = \(\frac{17}{20} \)

 

Therefore, the final answer is  \(1\frac{17}{20} \)

The difference between \(6\frac{1}{4} \ \text{and} \ 4 \frac{2}{5}\) is \(1\frac{17}{20} \)

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Problem 4

Subtract 10 7/9 - 5 2/3.

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 \(5\frac{1}{9} \)

Explanation

  • Here, we have an unlike denominator. So the first step is to find the LCD of 9 and 3. 

9 is the least common denominator of 9 and 3. 

 

  • Since 9 is the denominator of \(10\frac{7}{9} \), we don’t have to change the denominator here. However, we need to change the denominator of \(5\frac{2}{3} \) to 9, to make subtraction possible. To do that, let’s multiply both the numerator and the denominator by 3.
    \(\frac{2}{3} = \frac{2 \times 3}{3 \times 3} \) = \(\frac{6}{9} \) 

 

  • Now, the expression becomes: 
    \(10\frac{7}{9} - 5 \frac{6}{9}\)

 

  • Subtract the whole numbers:
    \(10 - 5 = 5\)

 

  • Next, subtract the fractional parts: 
    \( \frac{7}{9} - \frac{6}{9} = \frac{7 - 6}{9} = \frac{1}{9} \)

 

Hence, the final answer is \(5 \tfrac{1}{9} \)

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Problem 5

Subtract 3 2/8 from 7 5/8.

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\(4 \tfrac{3}{8} \)

Explanation

Subtract  \(7 \tfrac{5}{8} \) and \(3 \tfrac{2}{8} \) 

 

  • First, the whole numbers: 
    \(7 - 3 = 4\)

 

  • Next, the fractional parts:
    \(\frac{5}{8} - \frac{2}{8} = \frac{3}{8} \)

 

Therefore, the difference between \(7 \tfrac{5}{8} \) and \(3 \tfrac{2}{8} \) is \(4 \tfrac{3}{8} \)

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FAQs on Subtracting Mixed Fractions

1.How to define mixed fraction to my child?

A mixed fraction has a combination of a whole number and a proper fraction. Use real life examples, like give your child a whole cookie and a half from another cookie. Now, he has the total of \(1{1 \over 2}\) cookies.

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2.How to teach subtraction of mixed fractions with the same denominator to children?

To teach subtraction of mixed fractions with the same denominator, explain the given steps to children

Step 1: Subtract the whole numbers.

Step 2: Subtract the fractions.

Step 3: Write the answer. 

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3.How to teach subtraction of mixed fractions with different denominators to young students?

For the subtraction of mixed fractions with different denominator, ask them to follow these steps:


Step 1: Find the least common denominator of the given fractions. 

Step 2: Convert the unlike fractions to the same denominator.

Step 3: Subtract the whole number.

Step 4: Subtract the fractions.

Step 5: Write the answer. 

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4.How to explain conversion of mixed fraction to improper fraction to my child?

Teach these two steps for the conversion of mixed fraction to improper fraction:

 

Step 1: Multiply the whole number by its denominator. 

Step 2: Add the result to the numerator and keep the denominator the same. 

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5.How to explain the importance of simplification to my child?

Give two subtraction to your child, like \({12 \over 15} - {2 \over 5}\) and \({3 \over 5} - {2 \over 5}\)

Now, ask them to solve both. For the first subtraction, they will first need to find LCM and then subtract. But in the second solution, they can directly subtract the numerator. Ask them which subtraction was easy.

Explain to them that \({3 \over 5}\) is the simplified form of \({12 \over 15} \), due to which the calculation became simple and easy.

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Hiralee Lalitkumar Makwana

About the Author

Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.

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Fun Fact

: She loves to read number jokes and games.

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