Last updated on May 26th, 2025
The divisibility rule is a method to determine if a number is divisible by another number without performing actual division. In real life, this can be used for quick calculations, evenly dividing items, and sorting. In this topic, we will explore the divisibility rule of 63.
The divisibility rule for 63 allows us to determine if a number is divisible by 63 without using division. Check whether 756 is divisible by 63 using the divisibility rule.
Step 1: Check if the number is divisible by both 7 and 9, as 63 is the product of these two numbers.
Step 2: To check divisibility by 7, multiply the last digit by 2 and subtract it from the rest of the number. For 756, multiply 6 by 2 to get 12 and subtract from 75 to get 63, which is divisible by 7.
Step 3: To check divisibility by 9, add all the digits of the number. For 756, the sum is 7 + 5 + 6 = 18, which is divisible by 9.
Since 756 is divisible by both 7 and 9, it is divisible by 63.
Understanding divisibility rules will help improve division skills. Here are some tips and tricks for the divisibility rule of 63:
Memorize multiples of 63 (63, 126, 189, 252, etc.) to quickly verify divisibility.
If after subtraction the result is negative, consider it as positive to check divisibility.
If the number is large, repeat the divisibility check for both 7 and 9 until reaching a smaller number.
Use the division method to confirm and crosscheck results for better understanding.
The divisibility rule of 63 helps quickly determine divisibility, but mistakes in calculations can lead to errors. Here are some common mistakes and solutions:
Is 756 divisible by 63?
Yes, 756 is divisible by 63.
To check divisibility by 63, we need to ensure divisibility by both 7 and 9, since 63 = 7 × 9.
1) Check divisibility by 7: Multiply the last digit by 2, 6 × 2 = 12. Subtract from the rest, 75 – 12 = 63, which is divisible by 7.
2) Check divisibility by 9: Add all digits, 7 + 5 + 6 = 18, which is divisible by 9.
Since 756 is divisible by both 7 and 9, it is divisible by 63.
Can 945 be divisible by 63 following the divisibility rule?
Can 945 be divisible by 63 following the divisibility rule?
Check divisibility by both 7 and 9.
1) For 7: Multiply the last digit by 2, 5 × 2 = 10. Subtract from the rest, 94 – 10 = 84, which is divisible by 7.
2) For 9: Add the digits, 9 + 4 + 5 = 18, which is divisible by 9.
945 is divisible by both 7 and 9, so it is divisible by 63.
Is 378 divisible by 63?
Yes, 378 is divisible by 63.
Check divisibility by both 7 and 9.
1) For 7: Multiply the last digit by 2, 8 × 2 = 16. Subtract from the rest, 37 – 16 = 21, which is divisible by 7.
2) For 9: Add the digits, 3 + 7 + 8 = 18, which is divisible by 9.
Since 378 is divisible by both 7 and 9, it is divisible by 63.
Is 512 divisible by 63?
No, 512 is not divisible by 63.
Check divisibility by both 7 and 9.
1) For 7: Multiply the last digit by 2, 2 × 2 = 4. Subtract from the rest, 51 – 4 = 47, which is not divisible by 7.
2) For 9: Add the digits, 5 + 1 + 2 = 8, which is not divisible by 9.
512 is neither divisible by 7 nor 9, so it is not divisible by 63.
Check the divisibility rule of 63 for 1260.
Yes, 1260 is divisible by 63.
Check divisibility by both 7 and 9.
1) For 7: Multiply the last digit by 2, 0 × 2 = 0. Subtract from the rest, 126 – 0 = 126. Repeat the process: 6 × 2 = 12, 12 – 12 = 0, which is divisible by 7.
2) For 9: Add the digits, 1 + 2 + 6 + 0 = 9, which is divisible by 9.
Since 1260 is divisible by both 7 and 9, it is divisible by 63.
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.