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Last updated on September 18, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 9 and 30.
The greatest common factor of 9 and 30 is 3. The largest divisor of two or more numbers is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 9 and 30, a few methods are described below
Steps to find the GCF of 9 and 30 using the listing of factors:
Step 1: Firstly, list the factors of each number
Factors of 9 = 1, 3, 9.
Factors of 30 = 1, 2, 3, 5, 6, 10, 15, 30.
Step 2: Now, identify the common factors of them Common factors of 9 and 30: 1, 3.
Step 3: Choose the largest factor The largest factor that both numbers have is 3. The GCF of 9 and 30 is 3.
To find the GCF of 9 and 30 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 9: 9 = 3 × 3 = 3²
Prime Factors of 30: 30 = 2 × 3 × 5 = 2 × 3 × 5
Step 2: Now, identify the common prime factors The common prime factor is 3.
Step 3: Multiply the common prime factors The Greatest Common Factor of 9 and 30 is 3.
Find the GCF of 9 and 30 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 30 by 9 30 ÷ 9 = 3 (quotient), The remainder is calculated as 30 − (9×3) = 3 The remainder is 3, not zero, so continue the process
Step 2: Now divide the previous divisor (9) by the previous remainder (3)
Divide 9 by 3 9 ÷ 3 = 3 (quotient), remainder = 9 − (3×3) = 0
The remainder is zero, the divisor will become the GCF.
The GCF of 9 and 30 is 3.
Finding GCF of 9 and 30 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A florist is arranging 9 red roses and 30 white roses into bouquets. She wants to use the greatest number of roses in each bouquet without any left over. How many roses will be in each bouquet?
We should find the GCF of 9 and 30 GCF of 9 and 30 is 3.
There are 3 roses in each bouquet. 9 ÷ 3 = 3 30 ÷ 3 = 10
There will be 3 bouquets, and each bouquet contains 3 red roses and 10 white roses.
As the GCF of 9 and 30 is 3, the florist can make bouquets with 3 roses each.
Now divide 9 and 30 by 3.
Each bouquet contains 3 red roses and 10 white roses.
A band has 9 trumpets and 30 flutes. They want to arrange them in rows with the same number of instruments in each row, using the largest possible number of instruments per row. How many instruments will be in each row?
GCF of 9 and 30 is 3. So each row will have 3 instruments.
There are 9 trumpets and 30 flutes.
To find the total number of instruments in each row, we should find the GCF of 9 and 30.
There will be 3 instruments in each row.
A chef has 9 kilograms of flour and 30 kilograms of sugar. He wants to package them into bags of equal weight, using the greatest possible weight for each bag. What should be the weight of each bag?
For calculating the greatest equal weight, we have to calculate the GCF of 9 and 30.
The GCF of 9 and 30 is 3.
Each bag will weigh 3 kilograms.
For calculating the greatest weight of each bag, first, we need to calculate the GCF of 9 and 30, which is 3.
The weight of each bag will be 3 kilograms.
A carpenter has two wooden planks, one 9 cm long and the other 30 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 9 and 30 is 3.
The longest length of each piece is 3 cm.
To find the longest length of each piece of the two wooden planks, 9 cm and 30 cm, respectively.
We have to find the GCF of 9 and 30, which is 3 cm.
The longest length of each piece is 3 cm.
If the GCF of 9 and ‘b’ is 3, and the LCM is 90, find ‘b’.
The value of ‘b’ is 30.
GCF × LCM = product of the numbers
3 × 90 = 9 × b
270 = 9b
b = 270 ÷ 9 = 30
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.