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127 LearnersLast updated on December 11, 2025

The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, group or arrange items, and schedule events. In this topic, we will learn about the GCF of 35 and 50.
The greatest common factor of 35 and 50 is 5.
The largest divisor of two or more numbers is called the GCF of the numbers.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 35 and 50, a few methods are described below :-
Steps to find the GCF of 35 and 50 using the listing of factors:
Step 1: Firstly, list the factors of each number. Factors of 35 = 1, 5, 7, 35. Factors of 50 = 1, 2, 5, 10, 25, 50.
Step 2: Now, identify the common factors of them. Common factors of 35 and 50: 1, 5.
Step 3: Choose the largest factor. The largest factor that both numbers have is 5.
The GCF of 35 and 50 is 5.


To find the GCF of 35 and 50 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number. Prime Factors of 35: 35 = 5 x 7. Prime Factors of 50: 50 = 2 x 5 x 5 = 2 x 5².
Step 2: Now, identify the common prime factors. The common prime factor is: 5.
Step 3: Multiply the common prime factors. 5 = 5. The Greatest Common Factor of 35 and 50 is 5.
Find the GCF of 35 and 50 using the division method or Euclidean Algorithm Method.
Follow these steps:
Step 1: First, divide the larger number by the smaller number. Here, divide 50 by 35. 50 ÷ 35 = 1 (quotient), The remainder is calculated as 50 − (35×1) = 15. The remainder is 15, not zero, so continue the process.
Step 2: Now divide the previous divisor (35) by the previous remainder (15). Divide 35 by 15. 35 ÷ 15 = 2 (quotient), remainder = 35 − (15×2) = 5. The remainder is 5, not zero, so continue the process.
Step 3: Divide the previous divisor (15) by the previous remainder (5). 15 ÷ 5 = 3 (quotient), remainder = 15 - (5×3) = 0. The remainder is zero, the divisor will become the GCF.
The GCF of 35 and 50 is 5.
Finding the GCF of 35 and 50 looks simple, but students often make mistakes while calculating the GCF.
Here are some common mistakes to be avoided by the students.
A gardener has 35 red roses and 50 white roses. She wants to arrange them into the largest possible equal groups. How many roses will be in each group?
We should find the GCF of 35 and 50.
GCF of 35 and 50 is 5.
There are 5 equal groups. 35 ÷ 5 = 7 and 50 ÷ 5 = 10.
There will be 5 groups, and each group gets 7 red roses and 10 white roses.
As the GCF of 35 and 50 is 5, the gardener can make 5 groups.
Now divide 35 and 50 by 5.
Each group gets 7 red roses and 10 white roses.
A baker has 35 chocolate cupcakes and 50 vanilla cupcakes. He wants to pack them into boxes with the same number of cupcakes in each box, using the largest possible number of cupcakes per box. How many cupcakes will be in each box?
GCF of 35 and 50 is 5.
So each box will have 5 cupcakes.
There are 35 chocolate and 50 vanilla cupcakes.
To find the total number of cupcakes in each box, we should find the GCF of 35 and 50.
There will be 5 cupcakes in each box.
A tailor has 35 meters of silk fabric and 50 meters of cotton fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 35 and 50.
The GCF of 35 and 50 is 5.
The fabric is 5 meters long.
For calculating the longest length of the fabric, first, we need to calculate the GCF of 35 and 50, which is 5.
The length of each piece of fabric will be 5 meters.
A carpenter has two wooden planks, one 35 cm long and the other 50 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood.
GCF of 35 and 50 is 5.
The longest length of each piece is 5 cm.
To find the longest length of each piece of the two wooden planks, 35 cm and 50 cm, respectively, we have to find the GCF of 35 and 50, which is 5 cm.
The longest length of each piece is 5 cm.
If the GCF of 35 and โbโ is 5, and the LCM is 350. Find โbโ.
The value of ‘b’ is 50.
GCF x LCM = product of the numbers
5 × 350 = 35 × b
1750 = 35b
b = 1750 ÷ 35 = 50

Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.






