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Last updated on September 10, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 28 and 63.
The greatest common factor of 28 and 63 is 7. The largest divisor of two or more numbers is called the GCF of the numbers. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 28 and 63, a few methods are described below -
Steps to find the GCF of 28 and 63 using the listing of factors
Step 1: Firstly, list the factors of each number
Factors of 28 = 1, 2, 4, 7, 14, 28.
Factors of 63 = 1, 3, 7, 9, 21, 63.
Step 2: Now, identify the common factors of them Common factors of 28 and 63: 1, 7.
Step 3: Choose the largest factor The largest factor that both numbers have is 7. The GCF of 28 and 63 is 7.
To find the GCF of 28 and 63 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 28: 28 = 2 x 2 x 7 = 2² x 7
Prime Factors of 63: 63 = 3 x 3 x 7 = 3² x 7
Step 2: Now, identify the common prime factors The common prime factor is: 7
Step 3: Multiply the common prime factors 7 The Greatest Common Factor of 28 and 63 is 7.
Find the GCF of 28 and 63 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 63 by 28 63 ÷ 28 = 2 (quotient), The remainder is calculated as 63 − (28×2) = 7
The remainder is 7, not zero, so continue the process
Step 2: Now divide the previous divisor (28) by the previous remainder (7) Divide 28 by 7 28 ÷ 7 = 4 (quotient), remainder = 28 − (7×4) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 28 and 63 is 7.
Finding GCF of 28 and 63 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A gardener has 28 roses and 63 tulips. She wants to create bouquets with the largest number of flowers in each bouquet. How many flowers will be in each bouquet?
We should find the GCF of 28 and 63 GCF of 28 and 63 is 7.
There are 7 equal bouquets 28 ÷ 7 = 4 63 ÷ 7 = 9
There will be 7 bouquets, and each bouquet gets 4 roses and 9 tulips.
As the GCF of 28 and 63 is 7, the gardener can make 7 bouquets. Now divide 28 and 63 by 7. Each bouquet gets 4 roses and 9 tulips.
A farmer has 28 apple trees and 63 orange trees. They want to arrange them in rows with the same number of trees in each row, using the largest possible number of trees per row. How many trees will be in each row?
GCF of 28 and 63 is 7. So each row will have 7 trees.
There are 28 apple trees and 63 orange trees. To find the total number of trees in each row, we should find the GCF of 28 and 63. There will be 7 trees in each row.
A ribbon factory has 28 meters of red ribbon and 63 meters of blue ribbon. They want to cut both ribbons into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 28 and 63. The GCF of 28 and 63 is 7. The ribbon is 7 meters long.
For calculating the longest length of the ribbon, first, we need to calculate the GCF of 28 and 63, which is 7. The length of each piece of the ribbon will be 7 meters.
A carpenter has two wooden planks, one 28 cm long and the other 63 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood. GCF of 28 and 63 is 7. The longest length of each piece is 7 cm.
To find the longest length of each piece of the two wooden planks, 28 cm and 63 cm, respectively, we have to find the GCF of 28 and 63, which is 7 cm. The longest length of each piece is 7 cm.
If the GCF of 28 and 'a' is 7, and the LCM is 252, find 'a'.
The value of 'a' is 63.
GCF x LCM = product of the numbers
7 × 252 = 28 × a
1764 = 28a
a = 1764 ÷ 28 = 63
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.