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127 LearnersLast updated on December 11, 2025

The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 27 and 125.
The greatest common factor of 27 and 125 is 1.
The largest divisor of two or more numbers is called the GCF of the numbers.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 27 and 125, a few methods are described below :-
Steps to find the GCF of 27 and 125 using the listing of factors
Step 1: Firstly, list the factors of each number Factors of 27 = 1, 3, 9, 27. Factors of 125 = 1, 5, 25, 125.
Step 2: Now, identify the common factors of them Common factors of 27 and 125: 1.
Step 3: Choose the largest factor The largest factor that both numbers have is 1.
The GCF of 27 and 125 is 1.


To find the GCF of 27 and 125 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 27: 27 = 3 x 3 x 3 = 3³ Prime Factors of 125: 125 = 5 x 5 x 5 = 5³
Step 2: Now, identify the common prime factors There are no common prime factors.
Step 3: Multiply the common prime factors Since there are no common prime factors, the GCF is 1.
The Greatest Common Factor of 27 and 125 is 1.
Find the GCF of 27 and 125 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 125 by 27 125 ÷ 27 = 4 (quotient), The remainder is calculated as 125 − (27×4) = 17 The remainder is 17, not zero, so continue the process.
Step 2: Now divide the previous divisor (27) by the previous remainder (17) Divide 27 by 17 27 ÷ 17 = 1 (quotient), remainder = 27 − (17×1) = 10.
Step 3: Now divide the previous divisor (17) by the previous remainder (10) 17 ÷ 10 = 1 (quotient), remainder = 17 − (10×1) = 7.
Step 4: Now divide the previous divisor (10) by the previous remainder (7) 10 ÷ 7 = 1 (quotient), remainder = 10 − (7×1) = 3.
Step 5: Now divide the previous divisor (7) by the previous remainder (3) 7 ÷ 3 = 2 (quotient), remainder = 7 − (3×2) = 1.
Step 6: Now divide the previous divisor (3) by the previous remainder (1) 3 ÷ 1 = 3 (quotient), remainder = 3 − (1×3) = 0 The remainder is zero; thus, the divisor is the GCF.
The GCF of 27 and 125 is 1.
Finding the GCF of 27 and 125 looks simple, but students often make mistakes while calculating the GCF.
Here are some common mistakes to be avoided by the students.
A baker has 27 chocolate cupcakes and 125 vanilla cupcakes. He wants to pack them into boxes with the largest number of cupcakes in each box. How many cupcakes will be in each box?
We should find the GCF of 27 and 125 GCF of 27 and 125 is 1.
There will be 1 cupcake in each box.
As the GCF of 27 and 125 is 1, the baker can only pack 1 cupcake in each box.
A gardener has 27 rose bushes and 125 tulip bulbs. She wants to plant them in rows with the same number of plants in each row, using the largest possible number of plants per row. How many plants will be in each row?
GCF of 27 and 125 is 1.
So each row will have 1 plant.
There are 27 rose bushes and 125 tulip bulbs.
To find the total number of plants in each row, we should find the GCF of 27 and 125.
There will be 1 plant in each row.
A chef has 27 grams of sugar and 125 grams of flour. She wants to divide both into portions of equal weight, using the largest possible weight. What should be the weight of each portion?
To calculate the largest equal weight, we have to calculate the GCF of 27 and 125.
The GCF of 27 and 125 is 1.
The weight of each portion is 1 gram.
For calculating the largest weight of the portions, we first need to calculate the GCF of 27 and 125, which is 1.
The weight of each portion will be 1 gram.
A tailor has two pieces of fabric, one 27 meters long and the other 125 meters long. She wants to cut them into the longest possible equal pieces, without any fabric left over. What should be the length of each piece?
The tailor needs the longest piece of fabric GCF of 27 and 125 is 1.
The longest length of each piece is 1 meter.
To find the longest length of each piece of the two pieces of fabric, 27 meters and 125 meters, respectively.
We have to find the GCF of 27 and 125, which is 1 meter.
The longest length of each piece is 1 meter.
If the GCF of 27 and โbโ is 1, and the LCM is 3375, find โbโ.
The value of ‘b’ is 125.
GCF x LCM = product of the numbers
1 × 3375 = 27 × b
3375 = 27b
b = 3375 ÷ 27 = 125

Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.






