Last updated on May 26th, 2025
In math, multiples are the products we get while multiplying a number with other numbers. Multiples play a key role in construction and design, counting groups of items, sharing resources equally, and managing time effectively. In this topic, we will learn the essential concepts of multiples of 801.
Now, let us learn more about multiples of 801. Multiples of 801 are the numbers you get when you multiply 801 by any whole number, including zero. Each number has an infinite number of multiples, including a multiple of itself. In multiplication, a multiple of 801 can be denoted as 801 × n, where ‘n’ represents any whole number (0, 1, 2, 3,…). So, we can summarize that:
Multiple of a number = Number × Any whole number
For example, multiplying 801 × 1 will give us 801 as the product. Multiples of 801 will be larger or equal to 801.
Multiples of 801 include the products of 801 and an integer. Multiples of 801 are divisible by 801 evenly. The first few multiples of 801 are given below:
TABLE OF 801 (1-10) | |
---|---|
801 × 1 = 801 |
801 × 6 = 4806 |
801 × 2 = 1602 |
801 × 7 = 5607 |
801 × 3 = 2403 |
801 × 8 = 6408 |
801 × 4 = 3204 |
801 × 9 = 7209 |
801 × 5 = 4005 |
801 × 10 = 8010 |
TABLE OF 801 (11-20) | |
---|---|
801 × 11 = 8811 |
801 × 16 = 12816 |
801 × 12 = 9612 |
801 × 17 = 13617 |
801 × 13 = 10413 |
801 × 18 = 14418 |
801 × 14 = 11214 |
801 × 19 = 15219 |
801 × 15 = 12015 |
801 × 20 = 16020 |
Now, we know the first few multiples of 801. They are 0, 801, 1602, 2403, 3204, 4005, 4806, 5607, 6408, 7209, 8010,...
Understanding the multiples of 801 helps solve mathematical problems and boost our multiplication and division skills. When working with multiples of 801, we need to apply it to different mathematical operations such as addition, subtraction, multiplication, and division.
801, 1602, 2403, 3204, and 4005 are the first five multiples of 801. When multiplying 801 from 1 to 5, we get these numbers as the products.
So, the sum of these multiples is:
801 + 1602 + 2403 + 3204 + 4005 = 12015
When we add the first 5 multiples of 801, the answer will be 12015.
While we do subtraction, it improves our comprehension of how the value decreases when each multiple is subtracted from the previous one. 801, 1602, 2403, 3204, and 4005 are the first five multiples of 801. So, let us calculate it as given below:
801 - 1602 = -801
-801 - 2403 = -3204
-3204 - 3204 = -6408
-6408 - 4005 = -10413
Hence, the result of subtracting the first 5 multiples of 801 is -10413.
To calculate the average, we need to identify the sum of the first 5 multiples of 801 and then divide it by the count, i.e., 5. Because there are 5 multiples presented in the calculation. Averaging helps us to understand the concepts of central tendencies and other values. We know the sum of the first 5 multiples of 801 is 12015.
801 + 1602 + 2403 + 3204 + 4005 = 12015
Next, divide the sum by 5:
12015 ÷ 5 = 2403
2403 is the average of the first 5 multiples of 801.
The product of given numbers is the result of multiplying all of them together. Here, the first 5 multiples of 801 include: 801, 1602, 2403, 3204, and 4005. Now, the product of these numbers is:
801 × 1602 × 2403 × 3204 × 4005 = 1,228,539,549,430,000
The product of the first 5 multiples of 801 is 1,228,539,549,430,000.
While we perform division, we get to know how many times 801 can fit into each of the given multiples. 801, 1602, 2403, 3204, and 4005 are the first 5 multiples of 801.
801 ÷ 801 = 1
1602 ÷ 801 = 2
2403 ÷ 801 = 3
3204 ÷ 801 = 4
4005 ÷ 801 = 5
The results of dividing the first 5 multiples of 801 are: 1, 2, 3, 4, and 5.
While working with multiples of 801, we make common mistakes. Identifying these errors and understanding how to avoid them can be helpful. Below are some frequent mistakes and tips to avoid them:
A new art gallery is being set up, and the curator decides to display paintings in sections. Each section holds 801 paintings. If they set up 5 sections, how many paintings will be on display in total?
4005 paintings
Each section has 801 paintings. To find the total number of paintings, multiply the number of sections by the number of paintings per section.
Number of sections = 5
Paintings per section = 801
[801 times 5 = 4005]
Therefore, there will be 4005 paintings on display.
A factory produces 801 gadgets every day. If the factory operates for 6 days, how many gadgets will it produce in total?
4806 gadgets
To find the total number of gadgets produced, multiply the number of gadgets produced each day by the number of days the factory operates.
Gadgets per day = 801
Number of days = 6
[801 times 6 = 4806]
Hence, the factory will produce 4806 gadgets in 6 days.
In a giant puzzle contest, each team gets 801 pieces. If there are 8 teams participating, how many puzzle pieces are there in total?
6408 pieces
Multiply the number of pieces each team receives by the total number of teams to find the total number of puzzle pieces.
Pieces per team = 801
Number of teams = 8
[801 times 8 = 6408]
So, there are 6408 puzzle pieces in total.
A warehouse stores 801 boxes of supplies on each shelf. If there are 3 shelves, how many boxes are stored in total?
2403 boxes
To find the total number of boxes, multiply the number of shelves by the number of boxes on each shelf.
Boxes per shelf = 801
Number of shelves = 3
[801 times 3 = 2403]
Therefore, there are 2403 boxes stored in the warehouse.
Emma is arranging chairs for a conference. She places 801 chairs in the first row, 1602 chairs in the second row, and 2403 chairs in the third row. How many chairs are there in total?
4806 chairs
To find the total number of chairs, add the number of chairs in each row.
First row = 801 chairs
Second row = 1602 chairs
Third row = 2403 chairs
[801 + 1602 + 2403 = 4806]
Thus, there are a total of 4806 chairs arranged for the conference.
Seyed Ali Fathima S a math expert with nearly 5 years of experience as a math teacher. From an engineer to a math teacher, shows her passion for math and teaching. She is a calculator queen, who loves tables and she turns tables to puzzles and songs.
: She has songs for each table which helps her to remember the tables