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104 LearnersLast updated on December 11, 2025

A pyramid with a triangular base consists of a triangular base and three triangular lateral faces. The lateral surface area represents the sum of the areas of these three triangular faces. Let's take an example of a tent. The fabric of the tent excluding the ground represents the lateral surface, which is equal to the lateral surface area of the pyramid. The base triangle is not included because it is on the ground.
The lateral surface area of a pyramid with a triangular base is the sum of the areas of the three triangular faces that extend from the base to the apex.
To find the lateral surface area of a pyramid with a triangular base, you need the slant heights of each triangular face and the lengths of the sides of the base triangle.
The lateral surface area is calculated by summing the areas of the individual triangular faces:
Area = 1/2 × (base1 × slant height1 + base2 × slant height2 + base3 × slant height3).
To find the Lateral Surface Area of a Pyramid with a Triangular Base, follow these steps:
Step 1: Take note of the given parameters, including base side lengths and slant heights.
Step 2: Ensure that all the measurements are in the same unit before the calculation.
Step 3: Use the equation, Area = 1/2 × (base1 × slant height1 + base2 × slant height2 + base3 × slant height3), to find the LSA of the pyramid.
Step 4: Provide the calculated answer in square units.


There are a few typical mistakes people make while calculating the lateral surface area of a pyramid with a triangular base.
Some of them are listed below:
What is the lateral area of a pyramid with a triangular base having side lengths of 3 cm, 4 cm, and 5 cm, and slant heights of 6 cm for each face?
54 cm²
Given: Base sides = 3 cm, 4 cm, 5 cm Slant heights = 6 cm each
LSA = 1/2 × (3×6 + 4×6 + 5×6) = 1/2 × (18 + 24 + 30) = 1/2 × 72 = 36 cm²
If the base of a triangular pyramid has sides of 5 cm, 5 cm, and 8 cm, with corresponding slant heights of 7 cm, 7 cm, and 9 cm, find the lateral surface area.
85 cm²
Given: Base sides = 5 cm, 5 cm, 8 cm Slant heights = 7 cm, 7 cm, 9 cm
LSA = 1/2 × (5×7 + 5×7 + 8×9) = 1/2 × (35 + 35 + 72) = 1/2 × 142 = 71 cm²
Calculate the lateral surface area of a pyramid with a triangular base where each side is 6 cm, and the slant height for each face is 10 cm.
90 cm²
Given: Base sides = 6 cm each Slant height = 10 cm for each face
LSA = 1/2 × (6×10 + 6×10 + 6×10) = 1/2 × 180 = 90 cm²
Evaluate the slant heights necessary for a pyramid with a triangular base of sides 4 cm, 6 cm, and 7 cm to have a lateral surface area of 100 square units, assuming equal slant heights.
8.33 units
Given: Base sides = 4 cm, 6 cm, 7 cm LSA = 100 square units
Equal slant heights = l units
LSA = 1/2 × (4l + 6l + 7l) = 100
1/2 × 17l = 100 17l = 200
l = 200/17 = 11.76 units
The lateral surface area of a pyramid with a triangular base is 75 cmยฒ. If the base has sides of 3 cm, 4 cm, and 5 cm, find the average slant height.
5 cm
Average slant height = Total LSA / Total base perimeter
Given: Base sides = 3 cm, 4 cm, 5 cm, LSA = 75 cm²
Perimeter = 3 + 4 + 5 = 12 cm
Average slant height = 75/12 = 6.25 cm

Seyed Ali Fathima S a math expert with nearly 5 years of experience as a math teacher. From an engineer to a math teacher, shows her passion for math and teaching. She is a calculator queen, who loves tables and she turns tables to puzzles and songs.
: She has songs for each table which helps her to remember the tables






