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Last updated on September 18, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 21 and 30.
The greatest common factor of 21 and 30 is 3. The largest divisor of two or more numbers is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 21 and 30, a few methods are described below
Steps to find the GCF of 21 and 30 using the listing of factors
Step 1: Firstly, list the factors of each number
Factors of 21 = 1, 3, 7, 21.
Factors of 30 = 1, 2, 3, 5, 6, 10, 15, 30.
Step 2: Now, identify the common factors of them Common factors of 21 and 30: 1, 3.
Step 3: Choose the largest factor The largest factor that both numbers have is 3. The GCF of 21 and 30 is 3.
To find the GCF of 21 and 30 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 21: 21 = 3 x 7
Prime Factors of 30: 30 = 2 x 3 x 5
Step 2: Now, identify the common prime factors The common prime factor is: 3
Step 3: Multiply the common prime factors The Greatest Common Factor of 21 and 30 is 3.
Find the GCF of 21 and 30 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 30 by 21 30 ÷ 21 = 1 (quotient),
The remainder is calculated as 30 − (21×1) = 9 The remainder is 9, not zero, so continue the process
Step 2: Now divide the previous divisor (21) by the previous remainder (9)
Divide 21 by 9 21 ÷ 9 = 2 (quotient), remainder = 21 − (9×2) = 3
The remainder is 3, not zero, so continue the process
Step 3: Now divide the previous divisor (9) by the previous remainder (3)
Divide 9 by 3 9 ÷ 3 = 3 (quotient), remainder = 9 − (3×3) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 21 and 30 is 3.
Finding GCF of 21 and 30 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A gardener has 21 rose bushes and 30 tulip plants. She wants to arrange them into equal rows with the largest number of plants in each row. How many plants will be in each row?
We should find the GCF of 21 and 30 GCF of 21 and 30 is 3.
There are 3 equal rows 21 ÷ 3 = 7 30 ÷ 3 = 10
There will be 3 rows, and each row gets 7 rose bushes and 10 tulip plants.
As the GCF of 21 and 30 is 3, the gardener can make 3 rows.
Now divide 21 and 30 by 3.
Each row gets 7 rose bushes and 10 tulip plants.
A library has 21 fiction books and 30 non-fiction books. They want to organize them on shelves with the same number of books on each shelf, using the largest possible number of books per shelf. How many books will be on each shelf?
GCF of 21 and 30 is 3. So each shelf will have 3 books.
There are 21 fiction and 30 non-fiction books.
To find the total number of books on each shelf, we should find the GCF of 21 and 30.
There will be 3 books on each shelf.
A tailor has 21 meters of green fabric and 30 meters of blue fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 21 and 30
The GCF of 21 and 30 is 3.
The fabric is 3 meters long.
For calculating the longest length of the fabric, first, we need to calculate the GCF of 21 and 30, which is 3.
The length of each piece of the fabric will be 3 meters.
A carpenter has two wooden planks, one 21 cm long and the other 30 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 21 and 30 is 3.
The longest length of each piece is 3 cm.
To find the longest length of each piece of the two wooden planks, 21 cm and 30 cm, respectively, we have to find the GCF of 21 and 30, which is 3 cm.
The longest length of each piece is 3 cm.
If the GCF of 21 and ‘b’ is 3, and the LCM is 210. Find ‘b’.
The value of ‘b’ is 30.
GCF x LCM = product of the numbers
3 × 210 = 21 × b
630 = 21b
b = 630 ÷ 21 = 30
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.