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Last updated on September 12, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 15 and 24.
The greatest common factor of 15 and 24 is 3. The largest divisor of two or more numbers is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 15 and 24, a few methods are described below -
Steps to find the GCF of 15 and 24 using the listing of factors
Step 1: Firstly, list the factors of each number Factors of 15 = 1, 3, 5, 15. Factors of 24 = 1, 2, 3, 4, 6, 8, 12, 24.
Step 2: Now, identify the common factors of them Common factors of 15 and 24: 1, 3.
Step 3: Choose the largest factor The largest factor that both numbers have is 3. The GCF of 15 and 24 is 3.
To find the GCF of 15 and 24 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime factors of 15: 15 = 3 × 5
Prime factors of 24: 24 = 2 × 2 × 2 × 3 = 2³ × 3
Step 2: Now, identify the common prime factors The common prime factor is: 3
Step 3: Multiply the common prime factors 3 = 3 The Greatest Common Factor of 15 and 24 is 3.
Find the GCF of 15 and 24 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 24 by 15 24 ÷ 15 = 1 (quotient) The remainder is calculated as 24 − (15×1) = 9 The remainder is 9, not zero, so continue the process
Step 2: Now divide the previous divisor (15) by the previous remainder (9) Divide 15 by 9 15 ÷ 9 = 1 (quotient), remainder = 15 − (9×1) = 6
Step 3: Continue the process Now divide the previous divisor (9) by the previous remainder (6) Divide 9 by 6 9 ÷ 6 = 1 (quotient), remainder = 9 − (6×1) = 3
Step 4: Continue the process Now divide the previous divisor (6) by the previous remainder (3) Divide 6 by 3 6 ÷ 3 = 2 (quotient), remainder = 6 − (3×2) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 15 and 24 is 3.
Finding GCF of 15 and 24 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A baker has 15 loaves of whole wheat bread and 24 loaves of rye bread. He wants to pack them in boxes with the largest number of loaves per box, equally. How many loaves will be in each box?
We should find the GCF of 15 and 24 GCF of 15 and 24 = 3
There are 3 equal groups 15 ÷ 3 = 5
24 ÷ 3 = 8
There will be 3 groups, and each box gets 5 loaves of whole wheat bread and 8 loaves of rye bread.
As the GCF of 15 and 24 is 3, the baker can make 3 groups. Now divide 15 and 24 by 3. Each box gets 5 loaves of whole wheat bread and 8 loaves of rye bread.
A gardener has 15 pots of red roses and 24 pots of white roses. She wants to arrange them in rows with the same number of pots in each row, using the largest possible number of pots per row. How many pots will be in each row?
GCF of 15 and 24 3 = 3
So each row will have 3 pots.
There are 15 pots of red roses and 24 pots of white roses. To find the total number of pots in each row, we should find the GCF of 15 and 24. There will be 3 pots in each row.
A chef has 15 meters of sausage casing and 24 meters of vegetable wrap. She wants to cut both into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 15 and 24 The GCF of 15 and 24 = 3 The length of each piece is 3 meters.
For calculating the longest length of the casing and wrap, first, we need to calculate the GCF of 15 and 24, which is 3. The length of each piece will be 3 meters.
An artist has two canvases, one 15 cm wide and the other 24 cm wide. She wants to cut them into the longest possible equal strips, without any canvas left over. What should be the width of each strip?
The artist needs the longest strip of canvas GCF of 15 and 24 3 = 3 The longest width of each strip is 3 cm.
To find the longest width of each strip of the two canvases, 15 cm and 24 cm wide, respectively, we have to find the GCF of 15 and 24, which is 3 cm. The longest width of each strip is 3 cm.
If the GCF of 15 and ‘b’ is 3, and the LCM is 120. Find ‘b’.
The value of ‘b’ is 24.
GCF × LCM = product of the numbers
3 × 120 = 15 × b
360 = 15b
b = 360 ÷ 15 = 24
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.