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Last updated on September 17, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 10 and 16.
The greatest common factor of 10 and 16 is 2. The largest divisor of two or more numbers is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1.
The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 10 and 16, a few methods are described below
Steps to find the GCF of 10 and 16 using the listing of factors:
Step 1: Firstly, list the factors of each number Factors of 10 = 1, 2, 5, 10. Factors of 16 = 1, 2, 4, 8, 16.
Step 2: Now, identify the common factors of them Common factors of 10 and 16: 1, 2.
Step 3: Choose the largest factor The largest factor that both numbers have is 2. The GCF of 10 and 16 is 2.
To find the GCF of 10 and 16 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 10: 10 = 2 x 5
Prime Factors of 16: 16 = 2 x 2 x 2 x 2 = 24
Step 2: Now, identify the common prime factors The common prime factor is: 2
Step 3: Multiply the common prime factors 2 = 2. The Greatest Common Factor of 10 and 16 is 2.
Find the GCF of 10 and 16 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number
Here, divide 16 by 10 16 ÷ 10 = 1 (quotient),
The remainder is calculated as 16 − (10×1) = 6
The remainder is 6, not zero, so continue the process
Step 2: Now divide the previous divisor (10) by the previous remainder (6)
Divide 10 by 6 10 ÷ 6 = 1 (quotient), remainder = 10 − (6×1) = 4 Continue the process
Step 3: Now divide the previous divisor (6) by the previous remainder (4)
Divide 6 by 4 6 ÷ 4 = 1 (quotient), remainder = 6 − (4×1) = 2
Continue the process
Step 4: Now divide the previous divisor (4) by the previous remainder (2)
Divide 4 by 2 4 ÷ 2 = 2 (quotient), remainder = 4 − (2×2) = 0
The remainder is zero, the divisor will become the GCF. The GCF of 10 and 16 is 2.
Finding GCF of 10 and 16 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A gardener has 10 red roses and 16 white roses. She wants to bundle them into bouquets with an equal number of roses in each. How many roses will be in each bouquet?
We should find the GCF of 10 and 16 GCF of 10 and 16 2.
There are 2 equal bouquets 10 ÷ 2 = 5
16 ÷ 2 = 8
There will be 2 bouquets, and each bouquet gets 5 red roses and 8 white roses.
As the GCF of 10 and 16 is 2, the gardener can make 2 bouquets.
Now divide 10 and 16 by 2. Each bouquet gets 5 red roses and 8 white roses.
A chef has 10 lemons and 16 oranges. He wants to arrange them in baskets with the same number of fruits in each. How many fruits will be in each basket?
GCF of 10 and 16 2.
So each basket will have 2 fruits.
There are 10 lemons and 16 oranges.
To find the total number of fruits in each basket, we should find the GCF of 10 and 16.
There will be 2 fruits in each basket.
A tailor has 10 meters of fabric A and 16 meters of fabric B. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 10 and 16
The GCF of 10 and 16 2.
The fabric piece is 2 meters long.
For calculating the longest length of the fabric, first, we need to calculate the GCF of 10 and 16 which is 2. The length of each piece of fabric will be 2 meters.
A carpenter has two wooden planks, one 10 cm long and the other 16 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 10 and 16 2.
The longest length of each piece is 2 cm.
To find the longest length of each piece of the two wooden planks, 10 cm and 16 cm, respectively.
We have to find the GCF of 10 and 16, which is 2 cm.
The longest length of each piece is 2 cm.
If the GCF of 10 and ‘a’ is 2, and the LCM is 80. Find ‘a’.
The value of ‘a’ is 16.
GCF x LCM = product of the numbers
2 × 80 = 10 × a
160 = 10a
a = 160 ÷ 10 = 16
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.