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Last updated on September 12, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 45 and 76.
The greatest common factor of 45 and 76 is 1. The largest divisor of two or more numbers is called the GCF of the number. If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 45 and 76, a few methods are described below -
Steps to find the GCF of 45 and 76 using the listing of factors:
Step 1: Firstly, list the factors of each number Factors of 45 = 1, 3, 5, 9, 15, 45. Factors of 76 = 1, 2, 4, 19, 38, 76.
Step 2: Now, identify the common factors of them Common factor of 45 and 76: 1.
Step 3: Choose the largest factor The largest factor that both numbers have is 1. The GCF of 45 and 76 is 1.
To find the GCF of 45 and 76 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number
Prime Factors of 45: 45 = 3 × 3 × 5 = 3² × 5
Prime Factors of 76: 76 = 2 × 2 × 19 = 2² × 19
Step 2: Now, identify the common prime factors There are no common prime factors.
Step 3: Since there are no common prime factors, the GCF is 1.
Find the GCF of 45 and 76 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 76 by 45 76 ÷ 45 = 1 (quotient), The remainder is calculated as 76 − (45 × 1) = 31
The remainder is 31, not zero, so continue the process
Step 2: Now divide the previous divisor (45) by the previous remainder (31) 45 ÷ 31 = 1 (quotient), remainder = 45 − (31 × 1) = 14
Step 3: Continue the process 31 ÷ 14 = 2 (quotient), remainder = 31 − (14 × 2) = 3
Step 4: Continue the process 14 ÷ 3 = 4 (quotient), remainder = 14 − (3 × 4) = 2
Step 5: Continue the process 3 ÷ 2 = 1 (quotient), remainder = 3 − (2 × 1) = 1
Step 6: Continue the process 2 ÷ 1 = 2 (quotient), remainder = 2 − (1 × 2) = 0
The remainder is zero, so the divisor will become the GCF. The GCF of 45 and 76 is 1.
Finding the GCF of 45 and 76 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A teacher has 45 apples and 76 oranges. She wants to group them into equal sets, with the largest number of items in each group. How many items will be in each group?
We should find the GCF of 45 and 76. The GCF of 45 and 76 is 1.
There will be 1 group, with each group having 45 apples and 76 oranges.
As the GCF of 45 and 76 is 1, the teacher can make only 1 group. Each group will consist of 45 apples and 76 oranges.
A school has 45 red chairs and 76 blue chairs. They want to arrange them in rows with the same number of chairs in each row, using the largest possible number of chairs per row. How many chairs will be in each row?
The GCF of 45 and 76 is 1. So each row will have 1 chair.
There are 45 red and 76 blue chairs. To find the total number of chairs in each row, we should find the GCF of 45 and 76. There will be 1 chair in each row.
A tailor has 45 meters of red fabric and 76 meters of blue fabric. She wants to cut both fabrics into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 45 and 76.
The GCF of 45 and 76 is 1. The fabric is 1 meter long.
For calculating the longest length of the fabric, we first need to calculate the GCF of 45 and 76, which is 1. The length of each piece of fabric will be 1 meter.
A carpenter has two wooden planks, one 45 cm long and the other 76 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood. The GCF of 45 and 76 is 1.
The longest length of each piece is 1 cm.
To find the longest length of each piece of the two wooden planks, 45 cm and 76 cm, respectively, we have to find the GCF of 45 and 76, which is 1 cm. The longest length of each piece is 1 cm.
If the GCF of 45 and ‘b’ is 15, and the LCM is 225. Find ‘b’.
The value of ‘b’ is 75.
GCF x LCM = product of the numbers
15 × 225 = 45 × b
3375 = 45b
b = 3375 ÷ 45 = 75
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.