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Last updated on September 24, 2025
The GCF is the largest number that can divide two or more numbers without leaving any remainder. GCF is used to share the items equally, to group or arrange items, and schedule events. In this topic, we will learn about the GCF of 7 and 30.
The greatest common factor of 7 and 30 is 1. The largest divisor of two or more numbers is called the GCF of the number.
If two numbers are co-prime, they have no common factors other than 1, so their GCF is 1. The GCF of two numbers cannot be negative because divisors are always positive.
To find the GCF of 7 and 30, a few methods are described below
Steps to find the GCF of 7 and 30 using the listing of factors
Step 1: Firstly, list the factors of each number Factors of 7 = 1, 7. Factors of 30 = 1, 2, 3, 5, 6, 10, 15, 30.
Step 2: Now, identify the common factors of them Common factors of 7 and 30: 1.
Step 3: Choose the largest factor The largest factor that both numbers have is 1. The GCF of 7 and 30 is 1.
To find the GCF of 7 and 30 using the Prime Factorization Method, follow these steps:
Step 1: Find the prime factors of each number Prime Factors of 7: 7 = 7 Prime Factors of 30: 30 = 2 x 3 x 5
Step 2: Now, identify the common prime factors The common prime factor is: None (except 1)
Step 3: Since there are no common prime factors except 1, the GCF is 1. The Greatest Common Factor of 7 and 30 is 1.
Find the GCF of 7 and 30 using the division method or Euclidean Algorithm Method. Follow these steps:
Step 1: First, divide the larger number by the smaller number Here, divide 30 by 7 30 ÷ 7 = 4 (quotient), The remainder is calculated as 30 − (7×4) = 2 The remainder is 2, not zero, so continue the process
Step 2: Now divide the previous divisor (7) by the previous remainder (2) Divide 7 by 2 7 ÷ 2 = 3 (quotient), remainder = 7 − (2×3) = 1 The remainder is 1, not zero, so continue the process
Step 3: Divide the previous divisor (2) by the previous remainder (1) 2 ÷ 1 = 2 (quotient), remainder = 2 − (1×2) = 0 The remainder is zero, the divisor will become the GCF. The GCF of 7 and 30 is 1.
Finding GCF of 7 and 30 looks simple, but students often make mistakes while calculating the GCF. Here are some common mistakes to be avoided by the students.
A chef has 7 apples and 30 oranges. He wants to create fruit baskets with the largest possible number of apples and oranges in each basket. How many apples and oranges will be in each basket?
We should find the GCF of 7 and 30 GCF of 7 and 30 is 1. There will be 1 apple and 1 orange in each basket.
As the GCF of 7 and 30 is 1, the chef can only make baskets with 1 apple and 1 orange in each.
An artist has 7 tubes of red paint and 30 tubes of blue paint. They want to arrange them in rows with the same number of tubes in each row, using the largest possible number of tubes per row. How many tubes will be in each row?
GCF of 7 and 30 is 1. So each row will have 1 tube of paint.
There are 7 red and 30 blue tubes of paint.
To find the total number of tubes in each row, we should find the GCF of 7 and 30.
There will be 1 tube in each row.
A gardener has 7 meters of rope and 30 meters of twine. She wants to cut both into pieces of equal length, using the longest possible length. What should be the length of each piece?
For calculating the longest equal length, we have to calculate the GCF of 7 and 30 The GCF of 7 and 30 is 1. The length of each piece is 1 meter.
For calculating the longest length of the rope and twine, first, we need to calculate the GCF of 7 and 30, which is 1.
The length of each piece will be 1 meter.
A carpenter has two wooden planks, one 7 cm long and the other 30 cm long. He wants to cut them into the longest possible equal pieces, without any wood left over. What should be the length of each piece?
The carpenter needs the longest piece of wood GCF of 7 and 30 is 1. The longest length of each piece is 1 cm.
To find the longest length of each piece of the two wooden planks, 7 cm and 30 cm, respectively.
We have to find the GCF of 7 and 30, which is 1 cm.
The longest length of each piece is 1 cm.
If the GCF of 7 and ‘a’ is 1, and the LCM is 210. Find ‘a’.
The value of ‘a’ is 30.
GCF x LCM = product of the numbers
1 × 210 = 7 × a
210 = 7a
a = 210 ÷ 7
= 30
Hiralee Lalitkumar Makwana has almost two years of teaching experience. She is a number ninja as she loves numbers. Her interest in numbers can be seen in the way she cracks math puzzles and hidden patterns.
: She loves to read number jokes and games.